你可以试试:

String myResource = IOUtils.toString(this.getClass().getResourceAsStream("yourfile.xml")).replace("\n","");

你可以使用Junit Rule为你的测试创建一个临时文件夹:

@Rule public TemporaryFolder temporaryFolder = new TemporaryFolder();
File file = temporaryFolder.newFile(".src/test/resources/abc.xml");

首先，确保abc.xml被复制到输出目录。然后你应该使用getResourceAsStream():

InputStream inputStream = 
    Thread.currentThread().getContextClassLoader().getResourceAsStream("test/resources/abc.xml");

获得InputStream后，只需将其转换为字符串。这个资源详细说明:http://www.kodejava.org/examples/266.html。但是，我将摘录相关代码:

public String convertStreamToString(InputStream is) throws IOException {
    if (is != null) {
        Writer writer = new StringWriter();

        char[] buffer = new char[1024];
        try {
            Reader reader = new BufferedReader(
                    new InputStreamReader(is, "UTF-8"));
            int n;
            while ((n = reader.read(buffer)) != -1) {
                writer.write(buffer, 0, n);
            }
        } finally {
            is.close();
        }
        return writer.toString();
    } else {        
        return "";
    }
}

你可以试试:

String myResource = IOUtils.toString(this.getClass().getResourceAsStream("yourfile.xml")).replace("\n","");

这是我用来获得文本文件与文本。我使用了commons的IOUtils和guava的Resources。

public static String getString(String path) throws IOException {
    try (InputStream stream = Resources.getResource(path).openStream()) {
        return IOUtils.toString(stream);
    }
}

一针见血:

ClassLoader classLoader = getClass().getClassLoader();
File file = new File(classLoader.getResource("file/test.xml").getFile());