扩展一下@ tj。的答案，如果你在寻找简单的月份，而不是完整的日历月份，你可以检查d2的日期是否大于或等于d1的日期。也就是说，如果d2的月份晚于d1的月份，那么就多了一个月。所以你应该可以这样做:

function monthDiff(d1, d2) {
    var months;
    months = (d2.getFullYear() - d1.getFullYear()) * 12;
    months -= d1.getMonth() + 1;
    months += d2.getMonth();
    // edit: increment months if d2 comes later in its month than d1 in its month
    if (d2.getDate() >= d1.getDate())
        months++
    // end edit
    return months <= 0 ? 0 : months;
}

monthDiff(
    new Date(2008, 10, 4), // November 4th, 2008
    new Date(2010, 2, 12)  // March 12th, 2010
);
// Result: 16; 4 Nov – 4 Dec '08, 4 Dec '08 – 4 Dec '09, 4 Dec '09 – 4 March '10

这并没有完全考虑到时间问题(例如，3月3日下午4:00和4月3日下午3:00)，但它更准确，而且只适用于几行代码。

anyVar = (((DisplayTo.getFullYear() * 12) + DisplayTo.getMonth()) - ((DisplayFrom.getFullYear() * 12) + DisplayFrom.getMonth()));

#这是我写的一段很好的代码，用于获取天数和月份 从给定日期开始

把你的手

/** * Date a end day * Date b start day * @param DateA Date @param DateB Date * @returns Date difference */ function getDateDifference(dateA, DateB, type = 'month') { const END_DAY = new Date(dateA) const START_DAY = new Date(DateB) let calculatedDateBy let returnDateDiff if (type === 'month') { const startMonth = START_DAY.getMonth() const endMonth = END_DAY.getMonth() calculatedDateBy = startMonth - endMonth returnDateDiff = Math.abs( calculatedDateBy + 12 * (START_DAY.getFullYear() - END_DAY.getFullYear()) ) } else { calculatedDateBy = Math.abs(START_DAY - END_DAY) returnDateDiff = Math.ceil(calculatedDateBy / (1000 * 60 * 60 * 24)) } const out = document.getElementById('output') out.innerText = returnDateDiff return returnDateDiff } // Gets number of days from given dates /* getDateDifference('2022-03-31','2022-04-08','day') */ // Get number of months from given dates getDateDifference('2021-12-02','2022-04-08','month') <div id="output"> </div>

下面是另一种更少循环的方法:

calculateTotalMonthsDifference = function(firstDate, secondDate) {
        var fm = firstDate.getMonth();
        var fy = firstDate.getFullYear();
        var sm = secondDate.getMonth();
        var sy = secondDate.getFullYear();
        var months = Math.abs(((fy - sy) * 12) + fm - sm);
        var firstBefore = firstDate > secondDate;
        firstDate.setFullYear(sy);
        firstDate.setMonth(sm);
        firstBefore ? firstDate < secondDate ? months-- : "" : secondDate < firstDate ? months-- : "";
        return months;
}

function monthDiff(d1, d2) {
var months, d1day, d2day, d1new, d2new, diffdate,d2month,d2year,d1maxday,d2maxday;
months = (d2.getFullYear() - d1.getFullYear()) * 12;
months -= d1.getMonth() + 1;
months += d2.getMonth();
months = (months <= 0 ? 0 : months);
d1day = d1.getDate();
d2day = d2.getDate();
if(d1day > d2day)
{
    d2month = d2.getMonth();
    d2year = d2.getFullYear();
    d1new = new Date(d2year, d2month-1, d1day,0,0,0,0);
    var timeDiff = Math.abs(d2.getTime() - d1new.getTime());
          diffdate = Math.abs(Math.ceil(timeDiff / (1000 * 3600 * 24))); 
    d1new = new Date(d2year, d2month, 1,0,0,0,0);
    d1new.setDate(d1new.getDate()-1);
    d1maxday = d1new.getDate();
    months += diffdate / d1maxday;
}
else
{
      if(!(d1.getMonth() == d2.getMonth() && d1.getFullYear() == d2.getFullYear()))
    {
        months += 1;
    }
    diffdate = d2day - d1day + 1;
    d2month = d2.getMonth();
    d2year = d2.getFullYear();
    d2new = new Date(d2year, d2month + 1, 1, 0, 0, 0, 0);
    d2new.setDate(d2new.getDate()-1);
    d2maxday = d2new.getDate();
    months += diffdate / d2maxday;
}

return months;

}

下面的逻辑将在几个月内取得差异

(endDate.getFullYear()*12+endDate.getMonth())-(startDate.getFullYear()*12+startDate.getMonth())