要从数组中删除元素，使用remove(at:)， removeLast()和removeAll()。

yourArray = [1,2,3,4]

删除2位置的值

yourArray.remove(at: 2)

从数组中移除最后一个值

yourArray.removeLast()

从集合中移除所有成员

yourArray.removeAll()

你可以这么做。首先确保Dog确实存在于数组中，然后删除它。如果您认为Dog可能在数组中发生多次，则添加for语句。

var animals = ["Dog", "Cat", "Mouse", "Dog"]
let animalToRemove = "Dog"

for object in animals {
    if object == animalToRemove {
        animals.remove(at: animals.firstIndex(of: animalToRemove)!)
    }
}

如果你确定Dog在数组中退出并且只发生了一次，那么就这样做:

animals.remove(at: animals.firstIndex(of: animalToRemove)!)

如果两者都有，字符串和数字

var array = [12, 23, "Dog", 78, 23]
let numberToRemove = 23
let animalToRemove = "Dog"

for object in array {

    if object is Int {
        // this will deal with integer. You can change to Float, Bool, etc...
        if object == numberToRemove {
        array.remove(at: array.firstIndex(of: numberToRemove)!)
        }
    }
    if object is String {
        // this will deal with strings
        if object == animalToRemove {
        array.remove(at: array.firstIndex(of: animalToRemove)!)
        }
    }
}

Swift4:

list = list.filter{$0 != "your Value"}

如果你有一个自定义对象数组，你可以像这样通过特定的属性进行搜索:

if let index = doctorsInArea.firstIndex(where: {$0.id == doctor.id}){
    doctorsInArea.remove(at: index)
}

或者如果你想通过名字来搜索

if let index = doctorsInArea.firstIndex(where: {$0.name == doctor.name}){
    doctorsInArea.remove(at: index)
}

斯威夫特5: 这是一个很酷的和简单的扩展来删除数组中的元素，而不需要过滤:

   extension Array where Element: Equatable {

    // Remove first collection element that is equal to the given `object`:
    mutating func remove(object: Element) {
        guard let index = firstIndex(of: object) else {return}
        remove(at: index)
    }

}

用法:

var myArray = ["cat", "barbecue", "pancake", "frog"]
let objectToRemove = "cat"

myArray.remove(object: objectToRemove) // ["barbecue", "pancake", "frog"]

也适用于其他类型，例如Int，因为Element是泛型类型:

var myArray = [4, 8, 17, 6, 2]
let objectToRemove = 17

myArray.remove(object: objectToRemove) // [4, 8, 6, 2]

斯威夫特5

guard let index = orders.firstIndex(of: videoID) else { return }
orders.remove(at: index)