Swift4:

list = list.filter{$0 != "your Value"}

使用索引数组删除元素:

Array of Strings and indexes let animals = ["cats", "dogs", "chimps", "moose", "squarrel", "cow"] let indexAnimals = [0, 3, 4] let arrayRemainingAnimals = animals .enumerated() .filter { !indexAnimals.contains($0.offset) } .map { $0.element } print(arrayRemainingAnimals) //result - ["dogs", "chimps", "cow"] Array of Integers and indexes var numbers = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12] let indexesToRemove = [3, 5, 8, 12] numbers = numbers .enumerated() .filter { !indexesToRemove.contains($0.offset) } .map { $0.element } print(numbers) //result - [0, 1, 2, 4, 6, 7, 9, 10, 11]

使用另一个数组的元素值删除元素

整数数组 let arrayResult = numbers。筛选器{元素 返回! indexesToRemove.contains(元素) ｝ 打印(arrayResult) //result - [0,1,2,4,6,7,9,10,11] 字符串数组 让arrayLetters =(“a”、“b”、“c”,“d”,“e”,“f”,“g”,“h”,“我”) let arrayRemoveLetters = ["a"， "e"， "g"， "h"] let arrayRemainingLetters = arrayLetters。过滤器{ ! arrayRemoveLetters.contains (0) ｝ 打印(arrayRemainingLetters) //result - ["b"， "c"， "d"， "f"， "i"]

Swift中很少涉及数组操作

创建数组

var stringArray = ["One", "Two", "Three", "Four"]

在数组中添加对象

stringArray = stringArray + ["Five"]

从索引对象中获取值

let x = stringArray[1]

添加对象

stringArray.append("At last position")

在索引处插入对象

stringArray.insert("Going", at: 1)

删除对象

stringArray.remove(at: 3)

Concat对象值

var string = "Concate Two object of Array \(stringArray[1]) + \(stringArray[2])"

斯威夫特5

guard let index = orders.firstIndex(of: videoID) else { return }
orders.remove(at: index)

Swift4:

list = list.filter{$0 != "your Value"}

要从数组中删除元素，使用remove(at:)， removeLast()和removeAll()。

yourArray = [1,2,3,4]

删除2位置的值

yourArray.remove(at: 2)

从数组中移除最后一个值

yourArray.removeLast()

从集合中移除所有成员

yourArray.removeAll()