我试图打开一个对话框窗口，但每次我试图打开它时，它都会抛出这个异常:
Uncaught handler: thread main exiting due to uncaught exception
android.view.WindowManager$BadTokenException:
Unable to add window -- token null is not for an application
at android.view.ViewRoot.setView(ViewRoot.java:460)
at android.view.WindowManagerImpl.addView(WindowManagerImpl.java:177)
at android.view.WindowManagerImpl.addView(WindowManagerImpl.java:91)
at android.app.Dialog.show(Dialog.java:238)
at android.app.Activity.showDialog(Activity.java:2413)
我是通过调用showDialog来创建它的。onCreateDialog处理程序日志很好，我可以一步通过它没有问题，但我已经附加了它，因为它似乎我错过了一些东西:
@Override
public Dialog onCreateDialog(int id)
{
Dialog dialog;
Context appContext = this.getApplicationContext();
switch(id)
{
case RENAME_DIALOG_ID:
Log.i("Edit", "Creating rename dialog...");
dialog = new Dialog(appContext);
dialog.setContentView(R.layout.rename);
dialog.setTitle("Rename " + noteName);
break;
default:
dialog = null;
break;
}
return dialog;
}
这里面是不是少了什么?一些问题已经讨论过在从onCreate创建对话框时遇到这个问题，这是因为活动还没有创建，但这来自一个菜单对象的调用，appContext变量似乎在调试器中被正确填充。
public class Splash extends Activity {
Location location;
LocationManager locationManager;
LocationListener locationlistener;
ImageView image_view;
ublic static ProgressDialog progressdialog;
@Override
protected void onCreate(Bundle savedInstanceState) {
// TODO Auto-generated method stub
super.onCreate(savedInstanceState);
setContentView(R.layout.splash);
progressdialog = new ProgressDialog(Splash.this);
image_view.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
// TODO Auto-generated method stub
locationManager.requestLocationUpdates("gps", 100000, 1, locationlistener);
Toast.makeText(getApplicationContext(), "Getting Location plz wait...", Toast.LENGTH_SHORT).show();
progressdialog.setMessage("getting Location");
progressdialog.show();
Intent intent = new Intent(Splash.this,Show_LatLng.class);
// }
});
}
文本在这里:
使用这个来获取progressdialog的活动上下文
progressdialog = new ProgressDialog(Splash.this);
or progressdialog = new progressdialog (this);
使用它来获取BroadcastListener的应用程序上下文
不是progressdialog。
progressdialog = new ProgressDialog(getApplicationContext());
progressdialog = new ProgressDialog(getBaseContext());
我在另一节课上也遇到过类似的问题:
public class Something {
MyActivity myActivity;
public Something(MyActivity myActivity) {
this.myActivity=myActivity;
}
public void someMethod() {
.
.
AlertDialog.Builder builder = new AlertDialog.Builder(myActivity);
.
AlertDialog alert = builder.create();
alert.show();
}
}
大部分时间工作正常，但有时会因为同样的错误而崩溃。然后我意识到在我的活动中我有…
public class MyActivity extends Activity {
public static Something something;
public void someMethod() {
if (something==null) {
something=new Something(this);
}
}
}
因为我保持对象为静态，第二次运行的代码仍然保持对象的原始版本，因此仍然引用原始的Activity，它已经不存在了。
愚蠢的错误，尤其是当我真的不需要把物体放在静止的位置……
