在Windows (Windows XP)批处理脚本中,我需要格式化当前日期和时间,以便以后在文件名等中使用。

这类似于堆栈溢出问题如何在批处理文件中添加日期,但也包含时间。

到目前为止,我有这个:

echo %DATE%
echo %TIME%
set datetimef=%date:~-4%_%date:~3,2%_%date:~0,2%__%time:~0,2%_%time:~3,2%_%time:~6,2%
echo %datetimef%

这使:

28/07/2009
 8:35:31.01
2009_07_28__ 8_36_01

是否有一种方法可以允许%TIME%中的个位数小时,以便我可以得到以下结果?

2009_07_28__08_36_01

当前回答

以下可能不是一个直接的答案,但一个接近的答案?

set hour=%time:~0,2%
if "%hour:~0,1%" == " " set datetimef=%date:~-4%_%date:~3,2%_%date:~0,2%__0%time:~1,2%_%time:~3,2%_%time:~6,2%
else set datetimef=%date:~-4%_%date:~3,2%_%date:~0,2%__%time:~0,2%_%time:~3,2%_%time:~6,2%

至少这可能是鼓舞人心的。

其他回答

用斜杠分隔date命令的结果,然后可以将每个标记移动到适当的变量中。

FOR /F "tokens=1-3 delims=/" %%a IN ("%date:~4%") DO (
SET _Month=%%a
SET _Day=%%b
SET _Year=%%c
)
ECHO Month %_Month%
ECHO Day %_Day%
ECHO Year %_Year%

创建一个名为“search_files.bat”的文件,并将下面的内容放入该文件中。然后双击它。临时的%THH%变量被放置在适当的位置来处理AM。如果时间的前两位数字为0,Windows将忽略LOG文件的其余文件名。

CD .
SET THH=%time:~0,2%
SET THH=%THH: =0%
dir /s /b *.* > %date:~10,4%-%date:~4,2%-%date:~7,2%@%THH%.%time:~3,2%.%time:~6,2%.LOG

这个脚本使用一个WMI接口,主要通过WMIC工具访问,这是Windows的一个组成部分,因为Windows XP专业版(家庭版也支持,但默认情况下不安装该工具)。该脚本还通过创建和调用WSH vbscript来访问WMI接口,并以与WMIC工具提供的相同格式写入控制台输出时间,从而实现了缺少WMIC工具的解决方案。

@ECHO OFF
REM Returns: RETURN
REM Modify:  RETURN, StdOut
REM Required - mandatory: none
REM Required - optionaly: format strings delimited by a space to format an output delimited by predefined delimiter
REM    YYYY = 4-digit year
REM      MM = 2-digit month
REM      DD = 2-digit day
REM      hh = 2-digit hour
REM      mm = 2-digit minute
REM      ss = 2-digit second
REM      ms = 3-digit millisecond

CALL :getTime %*
ECHO %RETURN%
GOTO :EOF


REM SUBROUTINE
REM Returns: RETURN
REM Modify:  RETURN
REM Required - mandatory: none
REM Required - optionaly: format strings delimited by a space to format an output delimited by predefined delimiter
REM    YYYY = 4-digit year
REM      MM = 2-digit month
REM      DD = 2-digit day
REM      hh = 2-digit hour
REM      mm = 2-digit minute
REM      ss = 2-digit second
REM      ms = 3-digit millisecond
:getTime
  SETLOCAL EnableDelayedExpansion
    SET DELIM=-
    WHERE /Q wmic.exe
    IF NOT ERRORLEVEL 1 FOR /F "usebackq skip=1 tokens=*" %%x IN (`wmic.exe os get LocalDateTime`) DO (SET DT=%%x & GOTO getTime_Parse)
    SET _TMP=%TEMP:"=%
    ECHO Wscript.StdOut.WriteLine (GetObject("winmgmts:root\cimv2:Win32_OperatingSystem=@").LocalDateTime)>"%_TMP%\get_time_local-helper.vbs"
    FOR /F "usebackq tokens=*" %%x IN (`cscript //B //NoLogo "%_TMP%\get_time_local-helper.vbs"`) DO (SET DT=%%x & GOTO getTime_Parse)
    :getTime_Parse
      SET _RET=
      IF "%1" EQU "" (
        SET _RET=%DT:~0,4%%DELIM%%DT:~4,2%%DELIM%%DT:~6,2%%DELIM%%DT:~8,2%%DELIM%%DT:~10,2%%DELIM%%DT:~12,2%%DELIM%%DT:~15,3%
      ) ELSE (
        REM Not recognized format strings are ignored during parsing - no error is reported.
       :getTime_ParseLoop
         SET _VAL=
         IF "%1" EQU "YYYY" SET _VAL=%DT:~0,4%
         IF "%1" EQU "MM"   SET _VAL=%DT:~4,2%
         IF "%1" EQU "DD"   SET _VAL=%DT:~6,2%
         IF "%1" EQU "hh"   SET _VAL=%DT:~8,2%
         IF "%1" EQU "mm"   SET _VAL=%DT:~10,2%
         IF "%1" EQU "ss"   SET _VAL=%DT:~12,2%
         IF "%1" EQU "ms"   SET _VAL=%DT:~15,3%
         IF DEFINED _VAL (
           IF DEFINED _RET (
             SET _RET=!_RET!%DELIM%!_VAL!
           ) ELSE (
             SET _RET=!_VAL!
           )
         )
         SHIFT
         IF "%1" NEQ "" GOTO getTime_ParseLoop
      )
  ENDLOCAL & SET RETURN=%_RET%
GOTO :EOF
::========================================================================  
::== CREATE UNIQUE DATETIME STRING IN FORMAT YYYYMMDD-HHMMSS   
::======= ================================================================  
FOR /f %%a IN ('WMIC OS GET LocalDateTime ^| FIND "."') DO SET DTS=%%a  
SET DATETIME=%DTS:~0,8%-%DTS:~8,6%  

第一行输出的格式与时区无关: 20150515150941.077000 + 120 这样,您只需按照自己的愿望格式化输出即可。

因此,%DATE%的问题在于它依赖于区域设置。所以之前的大部分答案对我来说都不适用。如果你对确切的格式不挑剔,只是想要一个时间戳来区分文件,你可以这样做:

set _date=%DATE%-%TIME%
set _date=%_date:/=-%
set _date=%_date: =-%
set _date=%_date::=-%
set _date=%_date:.=-%
echo %_date%

这应该适用于大多数地区。如果它没有添加另一行,则设置_date=%_date:<offending_char>=-%以删除有问题的字符。例如:一个与文件名不兼容的字符或文件名中不希望出现的字符。

请注意,这并不符合问题所规定的确切标准。