在Windows (Windows XP)批处理脚本中,我需要格式化当前日期和时间,以便以后在文件名等中使用。

这类似于堆栈溢出问题如何在批处理文件中添加日期,但也包含时间。

到目前为止,我有这个:

echo %DATE%
echo %TIME%
set datetimef=%date:~-4%_%date:~3,2%_%date:~0,2%__%time:~0,2%_%time:~3,2%_%time:~6,2%
echo %datetimef%

这使:

28/07/2009
 8:35:31.01
2009_07_28__ 8_36_01

是否有一种方法可以允许%TIME%中的个位数小时,以便我可以得到以下结果?

2009_07_28__08_36_01

当前回答

用斜杠分隔date命令的结果,然后可以将每个标记移动到适当的变量中。

FOR /F "tokens=1-3 delims=/" %%a IN ("%date:~4%") DO (
SET _Month=%%a
SET _Day=%%b
SET _Year=%%c
)
ECHO Month %_Month%
ECHO Day %_Day%
ECHO Year %_Year%

其他回答

我是这样做的:

REM Generate FileName from date and time in format YYYYMMTTHHMM

Time /T > Time.dat
set /P ftime= < Time.dat

set FileName=LogFile%date:~6%%date:~3,2%%date:~0,2%%ftime:~0,2%%ftime:~3,2%.log

echo %FileName%

LogFile201310170928.log

还有另一种简单的方法:

set HH=%time:~0,2%
if %HH% LEQ 9 (
set HH=%time:~1,1%
)

我最终得到了这个脚本:

set hour=%time:~0,2%
if "%hour:~0,1%" == " " set hour=0%hour:~1,1%
echo hour=%hour%
set min=%time:~3,2%
if "%min:~0,1%" == " " set min=0%min:~1,1%
echo min=%min%
set secs=%time:~6,2%
if "%secs:~0,1%" == " " set secs=0%secs:~1,1%
echo secs=%secs%

set year=%date:~-4%
echo year=%year%

在WIN2008R2上,例如,我需要使您的'set month=%date:~3,2%'如下所示::否则,00表示month

set month=%date:~4,2%
if "%month:~0,1%" == " " set month=0%month:~1,1%
echo month=%month%
set day=%date:~0,2%
if "%day:~0,1%" == " " set day=0%day:~1,1%
echo day=%day%

set datetimef=%year%%month%%day%_%hour%%min%%secs%

echo datetimef=%datetimef%

一个很好的单行技巧是使用cmd /c echo ^%time^%来避免早期变量展开

cmd /c echo ^%time^% & dir /s somelongcommand & cmd /c echo ^%time^%

以下可能不是一个直接的答案,但一个接近的答案?

set hour=%time:~0,2%
if "%hour:~0,1%" == " " set datetimef=%date:~-4%_%date:~3,2%_%date:~0,2%__0%time:~1,2%_%time:~3,2%_%time:~6,2%
else set datetimef=%date:~-4%_%date:~3,2%_%date:~0,2%__%time:~0,2%_%time:~3,2%_%time:~6,2%

至少这可能是鼓舞人心的。