在Windows (Windows XP)批处理脚本中，我需要格式化当前日期和时间，以便以后在文件名等中使用。
这类似于堆栈溢出问题如何在批处理文件中添加日期，但也包含时间。
到目前为止，我有这个:
echo %DATE%
echo %TIME%
set datetimef=%date:~-4%_%date:~3,2%_%date:~0,2%__%time:~0,2%_%time:~3,2%_%time:~6,2%
echo %datetimef%
这使:
28/07/2009
8:35:31.01
2009_07_28__ 8_36_01
是否有一种方法可以允许%TIME%中的个位数小时，以便我可以得到以下结果?
2009_07_28__08_36_01
当前回答
我真的是批处理文件的新手，这是我的代码!!(我不知道为什么，但我不能结合日期/t和时间/t在一起，我不能直接使用%date%和%time%没有变量…)
@ECHO OFF
set ldt=%date% %time%
echo %ldt%>> logs.txt
EXIT
它在某种程度上是从其他人那里重用的(问题是获得一个格式化的时间作为文件名)。
其他回答
我是这样做的:
REM Generate FileName from date and time in format YYYYMMTTHHMM
Time /T > Time.dat
set /P ftime= < Time.dat
set FileName=LogFile%date:~6%%date:~3,2%%date:~0,2%%ftime:~0,2%%ftime:~3,2%.log
echo %FileName%
LogFile201310170928.log
::========================================================================
::== CREATE UNIQUE DATETIME STRING IN FORMAT YYYYMMDD-HHMMSS
::======= ================================================================
FOR /f %%a IN ('WMIC OS GET LocalDateTime ^| FIND "."') DO SET DTS=%%a
SET DATETIME=%DTS:~0,8%-%DTS:~8,6%
第一行输出的格式与时区无关: 20150515150941.077000 + 120 这样，您只需按照自己的愿望格式化输出即可。
:: =============================================================
:: Batch file to display Date and Time seprated by undescore.
:: =============================================================
:: Read the system date.
:: =============================================================
@SET MyDate=%DATE%
@SET MyDate=%MyDate:/=:%
@SET MyDate=%MyDate:-=:%
@SET MyDate=%MyDate: =:%
@SET MyDate=%MyDate:\=:%
@SET MyDate=%MyDate::=_%
:: =============================================================
:: Read the system time.
:: =============================================================
@SET MyTime=%TIME%
@SET MyTime=%MyTime: =0%
@SET MyTime=%MyTime:.=:%
@SET MyTime=%MyTime::=_%
:: =============================================================
:: Build the DateTime string.
:: =============================================================
@SET DateTime=%MyDate%_%MyTime%
:: =============================================================
:: Display the Date and Time as it is now.
:: =============================================================
@ECHO MyDate="%MyDate%" MyTime="%MyTime%" DateTime="%DateTime%"
:: =============================================================
:: Wait before close.
:: =============================================================
@PAUSE
:: =============================================================
当我需要一个日期/时间字符串时，我通常这样做:
set dt=%DATE:~6,4%_%DATE:~3,2%_%DATE:~0,2%__%TIME:~0,2%_%TIME:~3,2%_%TIME:~6,2%
set dt=%dt: =0%
这是为德国日期/时间格式(dd.mm。yyyy hh: mm: ss)。基本上，我将子字符串连接起来，最后将所有空格替换为零。
结果字符串的格式为:yyyy_mm_dd__hh_mm_ss
子字符串如何工作的简短解释:
%VARIABLE:~num_chars_to_skip,num_chars_to_keep%
因此，要想从“29.03.2018”这样的日期中得到年份，可以使用:
%DATE:~6,4%
^-----skip 6 characters
^---keep 4 characters
使用%，当时间值为7-9时，您将遇到十六进制操作错误。为了避免这种情况，请使用delayeexpand并使用!min:~1!
如果你有PowerShell，另一个方法是调用它:
for /F "usebackq delims=Z" %%i IN (`powershell Get-Date -format u`) do (set server-time=%%i)
