在Windows (Windows XP)批处理脚本中,我需要格式化当前日期和时间,以便以后在文件名等中使用。

这类似于堆栈溢出问题如何在批处理文件中添加日期,但也包含时间。

到目前为止,我有这个:

echo %DATE%
echo %TIME%
set datetimef=%date:~-4%_%date:~3,2%_%date:~0,2%__%time:~0,2%_%time:~3,2%_%time:~6,2%
echo %datetimef%

这使:

28/07/2009
 8:35:31.01
2009_07_28__ 8_36_01

是否有一种方法可以允许%TIME%中的个位数小时,以便我可以得到以下结果?

2009_07_28__08_36_01

当前回答

创建一个名为“search_files.bat”的文件,并将下面的内容放入该文件中。然后双击它。临时的%THH%变量被放置在适当的位置来处理AM。如果时间的前两位数字为0,Windows将忽略LOG文件的其余文件名。

CD .
SET THH=%time:~0,2%
SET THH=%THH: =0%
dir /s /b *.* > %date:~10,4%-%date:~4,2%-%date:~7,2%@%THH%.%time:~3,2%.%time:~6,2%.LOG

其他回答

@ECHO OFF
: Sets the proper date and time stamp with 24Hr Time for log file naming
: convention ('YYYYMMDD_HHMMSS')

: Scrapes the characters out of their expected permissions in the date/time
: environment variables.

: Expects a date format of '____MM_DD_YYYY'
: Expects a time format of 'HH:MM:SS' or ' H:MM:SS'

SET HOUR=%time:~0,2%
SET dtStamp9=%date:~-4%%date:~4,2%%date:~7,2%_0%time:~1,1%%time:~3,2%%time:~6,2% 
SET dtStamp24=%date:~-4%%date:~4,2%%date:~7,2%_%time:~0,2%%time:~3,2%%time:~6,2%

if "%HOUR:~0,1%" == " " (SET dtStamp=%dtStamp9%) else (SET dtStamp=%dtStamp24%)

ECHO %dtStamp%

PAUSE

我最终得到了这个脚本:

set hour=%time:~0,2%
if "%hour:~0,1%" == " " set hour=0%hour:~1,1%
echo hour=%hour%
set min=%time:~3,2%
if "%min:~0,1%" == " " set min=0%min:~1,1%
echo min=%min%
set secs=%time:~6,2%
if "%secs:~0,1%" == " " set secs=0%secs:~1,1%
echo secs=%secs%

set year=%date:~-4%
echo year=%year%

在WIN2008R2上,例如,我需要使您的'set month=%date:~3,2%'如下所示::否则,00表示month

set month=%date:~4,2%
if "%month:~0,1%" == " " set month=0%month:~1,1%
echo month=%month%
set day=%date:~0,2%
if "%day:~0,1%" == " " set day=0%day:~1,1%
echo day=%day%

set datetimef=%year%%month%%day%_%hour%%min%%secs%

echo datetimef=%datetimef%

我今天遇到了这个问题,并解决了它:

SET LOGTIME=%TIME: =0%

它用0代替空格,基本上是零垫小时。

经过一些快速搜索,我没有发现它是否需要命令扩展(仍然使用SETLOCAL DISABLEEXTENSIONS)。

用斜杠分隔date命令的结果,然后可以将每个标记移动到适当的变量中。

FOR /F "tokens=1-3 delims=/" %%a IN ("%date:~4%") DO (
SET _Month=%%a
SET _Day=%%b
SET _Year=%%c
)
ECHO Month %_Month%
ECHO Day %_Day%
ECHO Year %_Year%

我是这样做的:

REM Generate FileName from date and time in format YYYYMMTTHHMM

Time /T > Time.dat
set /P ftime= < Time.dat

set FileName=LogFile%date:~6%%date:~3,2%%date:~0,2%%ftime:~0,2%%ftime:~3,2%.log

echo %FileName%

LogFile201310170928.log