假设我这里有一个字符串:
var fullName: String = "First Last"
我想在空白处拆分字符串,并将值分配给它们各自的变量
var fullNameArr = // something like: fullName.explode(" ")
var firstName: String = fullNameArr[0]
var lastName: String? = fullnameArr[1]
此外,有时用户可能没有姓氏。
假设我这里有一个字符串:
var fullName: String = "First Last"
我想在空白处拆分字符串,并将值分配给它们各自的变量
var fullNameArr = // something like: fullName.explode(" ")
var firstName: String = fullNameArr[0]
var lastName: String? = fullnameArr[1]
此外,有时用户可能没有姓氏。
当前回答
Swift Dev.4.0(2017年5月24日)
Swift 4(Beta版)中拆分了一个新功能。
import Foundation
let sayHello = "Hello Swift 4 2017";
let result = sayHello.split(separator: " ")
print(result)
输出:
["Hello", "Swift", "4", "2017"]
访问值:
print(result[0]) // Hello
print(result[1]) // Swift
print(result[2]) // 4
print(result[3]) // 2017
Xcode 8.1/Swift 3.0.1
这是多个分隔符与数组的方式。
import Foundation
let mathString: String = "12-37*2/5"
let numbers = mathString.components(separatedBy: ["-", "*", "/"])
print(numbers)
输出:
["12", "37", "2", "5"]
其他回答
大多数这些答案都假设输入包含一个空格,而不是空白,并且只有一个空格。如果你能安全地做出这样的假设,那么(来自bennett的)公认的答案是相当优雅的,也是我在可能的时候会采用的方法。
当我们无法做出这一假设时,一个更稳健的解决方案需要涵盖以下大多数答案没有考虑的情况:
制表符/换行符/空格(空白),包括重复出现的字符前导/尾随空格Apple/Linux(\n)和Windows(\r\n)换行符
为了涵盖这些情况,此解决方案使用正则表达式将所有空格(包括重复出现的字符和Windows换行符)转换为单个空格,然后修剪,然后拆分为单个空格:
斯威夫特3:
let searchInput = " First \r\n \n \t\t\tMiddle Last "
let searchTerms = searchInput
.replacingOccurrences(
of: "\\s+",
with: " ",
options: .regularExpression
)
.trimmingCharacters(in: .whitespaces)
.components(separatedBy: " ")
// searchTerms == ["First", "Middle", "Last"]
这是用于swift 4.2在20181206 1610的字符串和CSV文件
var dataArray : [[String]] = []
let path = Bundle.main.path(forResource: "csvfilename", ofType: "csv")
let url = URL(fileURLWithPath: path!)
do {
let data = try Data(contentsOf: url)
let content = String(data: data, encoding: .utf8)
let parsedCSV = content?.components(separatedBy: "\r\n").map{ $0.components(separatedBy: ";") }
for line in parsedCSV!
{
dataArray.append(line)
}
}
catch let jsonErr {
print("\n Error read CSV file: \n ", jsonErr)
}
print("\n MohNada 20181206 1610 - The final result is \(dataArray) \n ")
雨燕3
let line = "AAA BBB\t CCC"
let fields = line.components(separatedBy: .whitespaces).filter {!$0.isEmpty}
返回三个字符串AAA、BBB和CCC筛选出空字段处理多个空格和制表字符如果要处理新行,请将.whittespaces替换为.whittespace和新行
作为WMios答案的替代方案,您还可以使用componentsSeparatedByCharactersSet,这在分隔符(空格、逗号等)较多的情况下非常方便。
使用您的特定输入:
let separators = NSCharacterSet(charactersInString: " ")
var fullName: String = "First Last";
var words = fullName.componentsSeparatedByCharactersInSet(separators)
// words contains ["First", "Last"]
使用多个分隔符:
let separators = NSCharacterSet(charactersInString: " ,")
var fullName: String = "Last, First Middle";
var words = fullName.componentsSeparatedByCharactersInSet(separators)
// words contains ["Last", "First", "Middle"]
只有拆分才是正确的答案,这里有两个以上空格的差异。
雨燕5
var temp = "Hello world ni hao"
let arr = temp.components(separatedBy: .whitespacesAndNewlines)
// ["Hello", "world", "", "", "", "", "ni", "hao"]
let arr2 = temp.components(separatedBy: " ")
// ["Hello", "world", "", "", "", "", "ni", "hao"]
let arr3 = temp.split(whereSeparator: {$0 == " "})
// ["Hello", "world", "ni", "hao"]