假设我这里有一个字符串:

var fullName: String = "First Last"

我想在空白处拆分字符串,并将值分配给它们各自的变量

var fullNameArr = // something like: fullName.explode(" ") 

var firstName: String = fullNameArr[0]
var lastName: String? = fullnameArr[1]

此外,有时用户可能没有姓氏。


当前回答

大多数这些答案都假设输入包含一个空格,而不是空白,并且只有一个空格。如果你能安全地做出这样的假设,那么(来自bennett的)公认的答案是相当优雅的,也是我在可能的时候会采用的方法。

当我们无法做出这一假设时,一个更稳健的解决方案需要涵盖以下大多数答案没有考虑的情况:

制表符/换行符/空格(空白),包括重复出现的字符前导/尾随空格Apple/Linux(\n)和Windows(\r\n)换行符

为了涵盖这些情况,此解决方案使用正则表达式将所有空格(包括重复出现的字符和Windows换行符)转换为单个空格,然后修剪,然后拆分为单个空格:

斯威夫特3:

let searchInput = "  First \r\n \n \t\t\tMiddle    Last "
let searchTerms = searchInput 
    .replacingOccurrences(
        of: "\\s+",
        with: " ",
        options: .regularExpression
    )
    .trimmingCharacters(in: .whitespaces)
    .components(separatedBy: " ")

// searchTerms == ["First", "Middle", "Last"]

其他回答

Swift 4或更高版本

如果您只需要正确设置人名格式,可以使用PersonNameComponentsFormater。

PersonNameComponentsFormater类提供本地化人名组成部分的表示通过PersonNameComponents对象。使用此类创建本地化当向用户显示人名信息时。


// iOS (9.0 and later), macOS (10.11 and later), tvOS (9.0 and later), watchOS (2.0 and later)
let nameFormatter = PersonNameComponentsFormatter()

let name =  "Mr. Steven Paul Jobs Jr."
// personNameComponents requires iOS (10.0 and later)
if let nameComps  = nameFormatter.personNameComponents(from: name) {
    nameComps.namePrefix   // Mr.
    nameComps.givenName    // Steven
    nameComps.middleName   // Paul
    nameComps.familyName   // Jobs
    nameComps.nameSuffix   // Jr.

    // It can also be configured to format your names
    // Default (same as medium), short, long or abbreviated

    nameFormatter.style = .default
    nameFormatter.string(from: nameComps)   // "Steven Jobs"

    nameFormatter.style = .short
    nameFormatter.string(from: nameComps)   // "Steven"

    nameFormatter.style = .long
    nameFormatter.string(from: nameComps)   // "Mr. Steven Paul Jobs jr."

    nameFormatter.style = .abbreviated
    nameFormatter.string(from: nameComps)   // SJ

    // It can also be use to return an attributed string using annotatedString method
    nameFormatter.style = .long
    nameFormatter.annotatedString(from: nameComps)   // "Mr. Steven Paul Jobs jr."
}

编辑/更新:

Swift 5或更高版本

对于按非字母字符拆分字符串,我们可以使用新的Character属性isLetter:

let fullName = "First Last"

let components = fullName.split{ !$0.isLetter }
print(components)  // "["First", "Last"]\n"

我还没有找到能够处理3个或更多组件名称并支持较旧iOS版本的解决方案。

struct NameComponentsSplitter {

    static func split(fullName: String) -> (String?, String?) {
        guard !fullName.isEmpty else {
            return (nil, nil)
        }
        let components = fullName.components(separatedBy: .whitespacesAndNewlines)
        let lastName = components.last
        let firstName = components.dropLast().joined(separator: " ")
        return (firstName.isEmpty ? nil : firstName, lastName)
    }
}

通过测试用例:

func testThatItHandlesTwoComponents() {
    let (firstName, lastName) = NameComponentsSplitter.split(fullName: "John Smith")
    XCTAssertEqual(firstName, "John")
    XCTAssertEqual(lastName, "Smith")
}

func testThatItHandlesMoreThanTwoComponents() {
    var (firstName, lastName) = NameComponentsSplitter.split(fullName: "John Clark Smith")
    XCTAssertEqual(firstName, "John Clark")
    XCTAssertEqual(lastName, "Smith")

    (firstName, lastName) = NameComponentsSplitter.split(fullName: "John Clark Jr. Smith")
    XCTAssertEqual(firstName, "John Clark Jr.")
    XCTAssertEqual(lastName, "Smith")
}

func testThatItHandlesEmptyInput() {
    let (firstName, lastName) = NameComponentsSplitter.split(fullName: "")
    XCTAssertEqual(firstName, nil)
    XCTAssertEqual(lastName, nil)
}

只需在fullName上调用componentsSeparatedByString方法

import Foundation

var fullName: String = "First Last"
let fullNameArr = fullName.componentsSeparatedByString(" ")

var firstName: String = fullNameArr[0]
var lastName: String = fullNameArr[1]

Swift 3更新+

import Foundation

let fullName    = "First Last"
let fullNameArr = fullName.components(separatedBy: " ")

let name    = fullNameArr[0]
let surname = fullNameArr[1]

这是用于swift 4.2在20181206 1610的字符串和CSV文件

var dataArray : [[String]] = []
 let path = Bundle.main.path(forResource: "csvfilename", ofType: "csv")
        let url = URL(fileURLWithPath: path!)
        do {
            let data = try Data(contentsOf: url) 
            let content = String(data: data, encoding: .utf8)
            let parsedCSV = content?.components(separatedBy: "\r\n").map{ $0.components(separatedBy: ";") }
           for line in parsedCSV!
            {
                dataArray.append(line)
           }
        }
        catch let jsonErr {
            print("\n   Error read CSV file: \n ", jsonErr)
        }

            print("\n MohNada 20181206 1610 - The final result is \(dataArray)  \n ")

根据Swift 2.2

您只需编写2行代码,就会得到拆分字符串。

let fullName = "FirstName LastName"
var splitedFullName = fullName.componentsSeparatedByString(" ")
print(splitedFullName[0])
print(splitedFullName[1]) 

享受。:)