在Swift 4中将字符串拆分为数组的步骤。

赋值字符串基于@spling。

注意：variableName.components（separatedBy:“split关键字”）

let fullName: String = "First Last @ triggerd event of the session by session storage @ it can be divided by the event of the trigger."
let fullNameArr = fullName.components(separatedBy: "@")
print("split", fullNameArr)

在Swift 4中将字符串拆分为数组的步骤。

赋值字符串基于@spling。

注意：variableName.components（separatedBy:“split关键字”）

let fullName: String = "First Last @ triggerd event of the session by session storage @ it can be divided by the event of the trigger."
let fullNameArr = fullName.components(separatedBy: "@")
print("split", fullNameArr)

非顶部：

对于搜索如何使用子字符串（而不是字符）拆分字符串的人来说，下面是一个有效的解决方案：

// TESTING
let str1 = "Hello user! What user's details? Here user rounded with space."
let a = str1.split(withSubstring: "user") // <-------------- HERE IS A SPLIT
print(a) // ["Hello ", "! What ", "\'s details? Here ", " rounded with space."]

// testing the result
var result = ""
for item in a {
    if !result.isEmpty {
        result += "user"
    }
    result += item
}
print(str1) // "Hello user! What user's details? Here user rounded with space."
print(result) // "Hello user! What user's details? Here user rounded with space."
print(result == str1) // true

/// Extension providing `split` and `substring` methods.
extension String {
    
    /// Split given string with substring into array
    /// - Parameters:
    ///   - string: the string
    ///   - substring: the substring to search
    /// - Returns: array of components
    func split(withSubstring substring: String) -> [String] {
        var a = [String]()
        var str = self
        while let range = str.range(of: substring) {
            let i = str.distance(from: str.startIndex, to: range.lowerBound)
            let j = str.distance(from: str.startIndex, to: range.upperBound)
            let left = str.substring(index: 0, length: i)
            let right = str.substring(index: j, length: str.length - j)
            a.append(left)
            str = right
        }
        if !str.isEmpty {
            a.append(str)
        }
        return a
    }
    
    /// the length of the string
    public var length: Int {
        return self.count
    }
    
    /// Get substring, e.g. "ABCDE".substring(index: 2, length: 3) -> "CDE"
    ///
    /// - parameter index:  the start index
    /// - parameter length: the length of the substring
    ///
    /// - returns: the substring
    public func substring(index: Int, length: Int) -> String {
        if self.length <= index {
            return ""
        }
        let leftIndex = self.index(self.startIndex, offsetBy: index)
        if self.length <= index + length {
            return String(self[leftIndex..<self.endIndex])
        }
        let rightIndex = self.index(self.endIndex, offsetBy: -(self.length - index - length))
        return String(self[leftIndex..<rightIndex])
    }

}

let fullName : String = "Steve.Jobs"
let fullNameArr : [String] = fullName.components(separatedBy: ".")

var firstName : String = fullNameArr[0]
var lastName : String = fullNameArr[1]

我发现了一个有趣的案例

方法1

var data:[String] = split( featureData ) { $0 == "\u{003B}" }

当我使用此命令从从服务器加载的数据中拆分一些符号时，它可以在模拟器中测试时拆分，并与测试设备同步，但不会在发布应用程序和Ad Hoc中拆分

我花了很多时间来跟踪这个错误，它可能会被某些Swift版本或iOS版本诅咒，或者两者都没有

这也与HTML代码无关，因为我尝试stringByRemovangPercentEncoding，但它仍然不起作用

2015年10月10日新增

在Swift 2.0中，此方法已更改为

var data:[String] = featureData.split {$0 == "\u{003B}"}

方法2

var data:[String] = featureData.componentsSeparatedByString("\u{003B}")

当我使用此命令时，它可以正确分割从服务器加载的相同数据

结论，我真的建议使用方法2

string.componentsSeparatedByString("")

斯威夫特2.2添加了错误处理和大写字符串：

func setFullName(fullName: String) {
    var fullNameComponents = fullName.componentsSeparatedByString(" ")

    self.fname = fullNameComponents.count > 0 ? fullNameComponents[0]: ""
    self.sname = fullNameComponents.count > 1 ? fullNameComponents[1]: ""

    self.fname = self.fname!.capitalizedString
    self.sname = self.sname!.capitalizedString
}