假设我这里有一个字符串:
var fullName: String = "First Last"
我想在空白处拆分字符串,并将值分配给它们各自的变量
var fullNameArr = // something like: fullName.explode(" ")
var firstName: String = fullNameArr[0]
var lastName: String? = fullnameArr[1]
此外,有时用户可能没有姓氏。
假设我这里有一个字符串:
var fullName: String = "First Last"
我想在空白处拆分字符串,并将值分配给它们各自的变量
var fullNameArr = // something like: fullName.explode(" ")
var firstName: String = fullNameArr[0]
var lastName: String? = fullnameArr[1]
此外,有时用户可能没有姓氏。
当前回答
雨燕3
let line = "AAA BBB\t CCC"
let fields = line.components(separatedBy: .whitespaces).filter {!$0.isEmpty}
返回三个字符串AAA、BBB和CCC筛选出空字段处理多个空格和制表字符如果要处理新行,请将.whittespaces替换为.whittespace和新行
其他回答
斯威夫特4
let words = "these words will be elements in an array".components(separatedBy: " ")
只有拆分才是正确的答案,这里有两个以上空格的差异。
雨燕5
var temp = "Hello world ni hao"
let arr = temp.components(separatedBy: .whitespacesAndNewlines)
// ["Hello", "world", "", "", "", "", "ni", "hao"]
let arr2 = temp.components(separatedBy: " ")
// ["Hello", "world", "", "", "", "", "ni", "hao"]
let arr3 = temp.split(whereSeparator: {$0 == " "})
// ["Hello", "world", "ni", "hao"]
对于swift 2,XCode 7.1:
let complete_string:String = "Hello world"
let string_arr = complete_string.characters.split {$0 == " "}.map(String.init)
let hello:String = string_arr[0]
let world:String = string_arr[1]
let str = "one two"
let strSplit = str.characters.split(" ").map(String.init) // returns ["one", "two"]
Xcode 7.2(7C68)
这在Beta 5中再次发生了变化。哭泣!它现在是CollectionType上的一个方法
旧版本:
var fullName = "First Last"
var fullNameArr = split(fullName) {$0 == " "}
新建:
var fullName = "First Last"
var fullNameArr = fullName.split {$0 == " "}
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