如何通过Java读取文件夹中的所有文件?这与哪个API无关。


当前回答

File folder = new File("/Users/you/folder/");
File[] listOfFiles = folder.listFiles();

for (File file : listOfFiles) {
    if (file.isFile()) {
        System.out.println(file.getName());
    }
}

其他回答

您可以将文件路径设置为参数,并创建包含所有文件路径的列表,而不必手动将其放入列表中。然后使用for循环和读取器。txt文件示例:

public static void main(String[] args) throws IOException{    
File[] files = new File(args[0].replace("\\", "\\\\")).listFiles(new FilenameFilter() { @Override public boolean accept(File dir, String name) { return name.endsWith(".txt"); } });
    ArrayList<String> filedir = new ArrayList<String>();
    String FILE_TEST = null;
    for (i=0; i<files.length; i++){
            filedir.add(files[i].toString());
            CSV_FILE_TEST=filedir.get(i) 

        try(Reader testreader = Files.newBufferedReader(Paths.get(FILE_TEST));
            ){
              //write your stuff
                 }}}
File folder = new File("/Users/you/folder/");
File[] listOfFiles = folder.listFiles();

for (File file : listOfFiles) {
    if (file.isFile()) {
        System.out.println(file.getName());
    }
}

如果你想要更多的选项,你可以使用这个函数来填充文件夹中文件的数组列表。选项有:递归性和匹配的模式。

public static ArrayList<File> listFilesForFolder(final File folder,
        final boolean recursivity,
        final String patternFileFilter) {

    // Inputs
    boolean filteredFile = false;

    // Ouput
    final ArrayList<File> output = new ArrayList<File> ();

    // Foreach elements
    for (final File fileEntry : folder.listFiles()) {

        // If this element is a directory, do it recursivly
        if (fileEntry.isDirectory()) {
            if (recursivity) {
                output.addAll(listFilesForFolder(fileEntry, recursivity, patternFileFilter));
            }
        }
        else {
            // If there is no pattern, the file is correct
            if (patternFileFilter.length() == 0) {
                filteredFile = true;
            }
            // Otherwise we need to filter by pattern
            else {
                filteredFile = Pattern.matches(patternFileFilter, fileEntry.getName());
            }

            // If the file has a name which match with the pattern, then add it to the list
            if (filteredFile) {
                output.add(fileEntry);
            }
        }
    }

    return output;
}

最佳,安德

上面有很多很好的答案,这里有一种不同的方法:在maven项目中,您放在resources文件夹中的所有内容都会默认复制到target/classes文件夹中。查看在运行时可用的内容

 ClassLoader contextClassLoader = 
 Thread.currentThread().getContextClassLoader();
    URL resource = contextClassLoader.getResource("");
    File file = new File(resource.toURI());
    File[] files = file.listFiles();
    for (File f : files) {
        System.out.println(f.getName());
    }

现在要从一个特定的文件夹中获取文件,假设你的资源文件夹中有一个名为“res”的文件夹,只需替换:

URL resource = contextClassLoader.getResource("res");

如果你想访问你的com.companyName包,那么:

contextClassLoader.getResource("com.companyName");

这将很好地工作:

private static void addfiles(File inputValVal, ArrayList<File> files)
{
  if(inputVal.isDirectory())
  {
    ArrayList <File> path = new ArrayList<File>(Arrays.asList(inputVal.listFiles()));

    for(int i=0; i<path.size(); ++i)
    {
        if(path.get(i).isDirectory())
        {
            addfiles(path.get(i),files);
        }
        if(path.get(i).isFile())
        {
            files.add(path.get(i));
        }
     }

    /*  Optional : if you need to have the counts of all the folders and files you can create 2 global arrays 
        and store the results of the above 2 if loops inside these arrays */
   }

   if(inputVal.isFile())
   {
     files.add(inputVal);
   }

}