如何通过Java读取文件夹中的所有文件?这与哪个API无关。


当前回答

防止listFiles()函数的nullpointerexception,并递归地从子目录中获取所有文件。

 public void listFilesForFolder(final File folder,List<File> fileList) {
    File[] filesInFolder = folder.listFiles();
    if (filesInFolder != null) {
        for (final File fileEntry : filesInFolder) {
            if (fileEntry.isDirectory()) {
            listFilesForFolder(fileEntry,fileList);
        } else {
            fileList.add(fileEntry);
        }
     }
    }
 }

 List<File> fileList = new List<File>();
 final File folder = new File("/home/you/Desktop");
 listFilesForFolder(folder);

其他回答

private static final String ROOT_FILE_PATH="/";
File f=new File(ROOT_FILE_PATH);
File[] allSubFiles=f.listFiles();
for (File file : allSubFiles) {
    if(file.isDirectory())
    {
        System.out.println(file.getAbsolutePath()+" is directory");
        //Steps for directory
    }
    else
    {
        System.out.println(file.getAbsolutePath()+" is file");
        //steps for files
    }
}
import java.io.File;


public class Test {

public void test1() {
    System.out.println("TEST 1");
}

public static void main(String[] args) throws SecurityException, ClassNotFoundException{

    File actual = new File("src");
    File list[] = actual.listFiles();
    for(int i=0; i<list.length; i++){
        String substring = list[i].getName().substring(0, list[i].getName().indexOf("."));
        if(list[i].isFile() && list[i].getName().contains(".java")){
                if(Class.forName(substring).getMethods()[0].getName().contains("main")){
                    System.out.println("CLASS NAME "+Class.forName(substring).getName());
                }

         }
    }

}
}

只要传递你的文件夹,它就会告诉你关于方法的主类。

/**
 * Function to read all mp3 files from sdcard and store the details in an
 * ArrayList
 */


public ArrayList<HashMap<String, String>> getPlayList() 
    {
        ArrayList<HashMap<String, String>> songsList=new ArrayList<>();
        File home = new File(MEDIA_PATH);

        if (home.listFiles(new FileExtensionFilter()).length > 0) {
            for (File file : home.listFiles(new FileExtensionFilter())) {
                HashMap<String, String> song = new HashMap<String, String>();
                song.put(
                        "songTitle",
                        file.getName().substring(0,
                                (file.getName().length() - 4)));
                song.put("songPath", file.getPath());

                // Adding each song to SongList
                songsList.add(song);
            }
        }
        // return songs list array
        return songsList;
    }

    /**
     * Class to filter files which have a .mp3 extension
     * */
    class FileExtensionFilter implements FilenameFilter 
    {
        @Override
        public boolean accept(File dir, String name) {
            return (name.endsWith(".mp3") || name.endsWith(".MP3"));
        }
    }

你可以过滤任何文本文件或任何其他扩展..把它换成。mp3

java.io.FileFilter的用法很好,见https://stackoverflow.com/a/286001/146745

File fl = new File(dir);
File[] files = fl.listFiles(new FileFilter() {          
    public boolean accept(File file) {
        return file.isFile();
    }
});

从Test文件夹中列出类路径内的文件

import java.io.File;
import java.io.IOException;

public class Hello {

    public static void main(final String[] args) throws IOException {

        System.out.println("List down all the files present on the server directory");
        File file1 = new File("/prog/FileTest/src/Test");
        File[] files = file1.listFiles();
        if (null != files) {
            for (int fileIntList = 0; fileIntList < files.length; fileIntList++) {
                String ss = files[fileIntList].toString();
                if (null != ss && ss.length() > 0) {
                    System.out.println("File: " + (fileIntList + 1) + " :" + ss.substring(ss.lastIndexOf("\\") + 1, ss.length()));
                }
            }
        }


    }


}