如何通过Java读取文件夹中的所有文件?这与哪个API无关。


当前回答

package com.commandline.folder;

import java.io.File;
import java.nio.file.Files;
import java.nio.file.Path;
import java.nio.file.Paths;
import java.util.stream.Stream;

public class FolderReadingDemo {
    public static void main(String[] args) {
        String str = args[0];
        final File folder = new File(str);
//      listFilesForFolder(folder);
        listFilesForFolder(str);
    }

    public static void listFilesForFolder(String str) {
        try (Stream<Path> paths = Files.walk(Paths.get(str))) {
            paths.filter(Files::isRegularFile).forEach(System.out::println);
        } catch (Exception e) {
            e.printStackTrace();
        }
    }

    public static void listFilesForFolder(final File folder) {
        for (final File fileEntry : folder.listFiles()) {
            if (fileEntry.isDirectory()) {
                listFilesForFolder(fileEntry);
            } else {
                System.out.println(fileEntry.getName());
            }
        }
    }

}

其他回答

这将读取指定路径下的指定文件扩展名文件(也可以查看子文件夹)

public static Map<String,List<File>> getFileNames(String 
dirName,Map<String,List<File>> filesContainer,final String fileExt){
    String dirPath = dirName;
    List<File>files = new ArrayList<>();
    Map<String,List<File>> completeFiles = filesContainer; 
    if(completeFiles == null) {
        completeFiles = new HashMap<>();
    }
    File file = new File(dirName);

    FileFilter fileFilter = new FileFilter() {
        @Override
        public boolean accept(File file) {
            boolean acceptFile = false;
            if(file.isDirectory()) {
                acceptFile = true;
            }else if (file.getName().toLowerCase().endsWith(fileExt))
              {
                acceptFile = true;
              }
            return acceptFile;
        }
    };
    for(File dirfile : file.listFiles(fileFilter)) {
        if(dirfile.isFile() && 
dirfile.getName().toLowerCase().endsWith(fileExt)) {
            files.add(dirfile);
        }else if(dirfile.isDirectory()) {
            if(!files.isEmpty()) {
                completeFiles.put(dirPath, files);  
            }

getFileNames(dirfile.getAbsolutePath(),completeFiles,fileExt);
        }
    }
    if(!files.isEmpty()) {
        completeFiles.put(dirPath, files);  
    }
    return completeFiles;
}
private static final String ROOT_FILE_PATH="/";
File f=new File(ROOT_FILE_PATH);
File[] allSubFiles=f.listFiles();
for (File file : allSubFiles) {
    if(file.isDirectory())
    {
        System.out.println(file.getAbsolutePath()+" is directory");
        //Steps for directory
    }
    else
    {
        System.out.println(file.getAbsolutePath()+" is file");
        //steps for files
    }
}

使用Java 1.7来递归列出命令行指定目录中的文件的简单示例:

import java.io.File;

public class List {
    public static void main(String[] args) {
        for (String f : args) {
            listDir(f);
        }
    }

    private static void listDir(String dir) {
        File f = new File(dir);
        File[] list = f.listFiles();

        if (list == null) {
            return;
        }

        for (File entry : list) {
            System.out.println(entry.getName());
            if (entry.isDirectory()) {
                listDir(entry.getAbsolutePath());
            }
        }
    }
}

我们可以使用org.apache.commons.io.FileUtils,使用listFiles()方法来读取给定文件夹中的所有文件。

eg:

FileUtils.listFiles(directory, new String[] {"ext1", "ext2"}, true)

这将读取给定目录中具有给定扩展名的所有文件,我们可以在数组中传递多个扩展名,并在文件夹中递归读取(true参数)。

File directory = new File("/user/folder");      
File[] myarray;  
myarray=new File[10];
myarray=directory.listFiles();
for (int j = 0; j < myarray.length; j++)
{
       File path=myarray[j];
       FileReader fr = new FileReader(path);
       BufferedReader br = new BufferedReader(fr);
       String s = "";
       while (br.ready()) {
          s += br.readLine() + "\n";
       }
}