我试图在Android中创建一个邮件发送应用程序。
如果我使用:
Intent emailIntent = new Intent(android.content.Intent.ACTION_SEND);
这将启动内置的Android应用程序;我试图发送邮件按钮点击直接不使用这个应用程序。
我试图在Android中创建一个邮件发送应用程序。
如果我使用:
Intent emailIntent = new Intent(android.content.Intent.ACTION_SEND);
这将启动内置的Android应用程序;我试图发送邮件按钮点击直接不使用这个应用程序。
当前回答
其他答案中提供的所有代码都是正确的,运行正常,但有点混乱,所以我决定发布一个库(尽管仍在开发中),以更简单的方式使用它:AndroidMail。
你只需要创建一个MailSender,构建一个邮件并发送它(已经在后台处理了一个AsyncTask)。
MailSender mailSender = new MailSender(email, password);
Mail.MailBuilder builder = new Mail.MailBuilder();
Mail mail = builder
.setSender(senderMail)
.addRecipient(new Recipient(recipient))
.setText("Hello")
.build();
mailSender.sendMail(mail);
您可以收到通知的电子邮件发送,它还支持不同的收件人类型(TO,抄送和密件抄送),附件和html:
MailSender mailSender = new MailSender(email, password);
Mail.MailBuilder builder = new Mail.MailBuilder();
Mail mail = builder
.setSender(senderMail)
.addRecipient(new Recipient(recipient))
.addRecipient(new Recipient(Recipient.TYPE.CC, recipientCC))
.setText("Hello")
.setHtml("<h1 style=\"color:red;\">Hello</h1>")
.addAttachment(new Attachment(filePath, fileName))
.build();
mailSender.sendMail(mail, new MailSender.OnMailSentListener() {
@Override
public void onSuccess() {
// mail sent!
}
@Override
public void onError(Exception error) {
// something bad happened :(
}
});
您可以通过Gradle或Maven获取:
compile 'it.enricocandino:androidmail:1.0.0-SNAPSHOT'
如果你有任何问题,请告诉我!:)
其他回答
编辑:JavaMail 1.5.5声称支持Android,所以你不需要其他任何东西。
我已经将最新的JavaMail(1.5.4)移植到Android。它可以在Maven Central中获得,只需添加以下内容到build.gradle~~
compile 'eu.ocathain.com.sun.mail:javax.mail:1.5.4'
然后你就可以按照官方教程学习了。
源代码可以在这里找到:https://bitbucket.org/artbristol/javamail-forked-android
这里有很多解决方案。然而,我认为我们必须改变GMail的配置,以允许从不太安全的设备访问。转到下面的链接并启用它。这对我很有用
https://myaccount.google.com/lesssecureapps?pli=1
对于那些想在2020年与Kotlin一起使用JavaMail的人:
首先:将这些依赖项添加到构建中。gradle文件(官方JavaMail Maven依赖项)
实现“com.sun.mail: android-mail: 1.6.5” 实现“com.sun.mail: android激活:1.6.5”
实现“org.bouncycastle: bcmail-jdk15on: 1.65” 实现“org.jetbrains.kotlinx: kotlinx-coroutines-core: 1.3.7” 实现“org.jetbrains.kotlinx: kotlinx-coroutines-android: 1.3.7”
BouncyCastle是出于安全考虑。
第二步:将这些权限添加到AndroidManifest.xml中
<uses-permission android:name="android.permission.INTERNET" />
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />
第三:当使用SMTP时,创建一个配置文件
object Config {
const val EMAIL_FROM = "You_Sender_Email@email.com"
const val PASS_FROM = "Your_Sender_Password"
const val EMAIL_TO = "Your_Destination_Email@email.com"
}
第四:创建Mailer对象
object Mailer {
init {
Security.addProvider(BouncyCastleProvider())
}
private fun props(): Properties = Properties().also {
// Smtp server
it["mail.smtp.host"] = "smtp.gmail.com"
// Change when necessary
it["mail.smtp.auth"] = "true"
it["mail.smtp.port"] = "465"
// Easy and fast way to enable ssl in JavaMail
it["mail.smtp.ssl.enable"] = true
}
// Dont ever use "getDefaultInstance" like other examples do!
private fun session(emailFrom: String, emailPass: String): Session = Session.getInstance(props(), object : Authenticator() {
override fun getPasswordAuthentication(): PasswordAuthentication {
return PasswordAuthentication(emailFrom, emailPass)
}
})
private fun builtMessage(firstName: String, surName: String): String {
return """
<b>Name:</b> $firstName <br/>
<b>Surname:</b> $surName <br/>
""".trimIndent()
}
private fun builtSubject(issue: String, firstName: String, surName: String):String {
return """
$issue | $firstName, $surName
""".trimIndent()
}
private fun sendMessageTo(emailFrom: String, session: Session, message: String, subject: String) {
try {
MimeMessage(session).let { mime ->
mime.setFrom(InternetAddress(emailFrom))
// Adding receiver
mime.addRecipient(Message.RecipientType.TO, InternetAddress(Config.EMAIL_TO))
// Adding subject
mime.subject = subject
// Adding message
mime.setText(message)
// Set Content of Message to Html if needed
mime.setContent(message, "text/html")
// send mail
Transport.send(mime)
}
} catch (e: MessagingException) {
Log.e("","") // Or use timber, it really doesn't matter
}
}
fun sendMail(firstName: String, surName: String) {
// Open a session
val session = session(Config.EMAIL_FROM, Config.PASSWORD_FROM)
// Create a message
val message = builtMessage(firstName, surName)
// Create subject
val subject = builtSubject(firstName, surName)
// Send Email
CoroutineScope(Dispatchers.IO).launch { sendMessageTo(Config.EMAIL_FROM, session, message, subject) }
}
Note
If you want a more secure way to send your email (and you want a more secure way!), use http as mentioned in the solutions before (I will maybe add it later in this answer) You have to properly check, if the users phone has internet access, otherwise the app will crash. When using gmail, enable "less secure apps" (this will not work, when you gmail has two factors enabled) https://myaccount.google.com/lesssecureapps?pli=1 Some credits belong to: https://medium.com/@chetan.garg36/android-send-mails-not-intent-642d2a71d2ee (he used RxJava for his solution)
我试着用@Vinayak B提交的代码。然而,我得到一个错误说:没有提供smtp
我在这里创建了一个新问题,提供了更多信息
我终于自己修好了。我得用另一个邮件罐 我必须确保我的“不太安全的应用程序访问权限”被打开。
我希望这能帮助那些有同样问题的人。这样做后,这段代码也可以在谷歌玻璃上工作。
为了帮助那些获得网络主线程异常与SDK目标>9。这是使用droopie的代码上面,但将类似于任何工作。
StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder().permitAll().build();
StrictMode.setThreadPolicy(policy);
android.os.NetworkOnMainThreadException
您可以如下所示使用AsyncTask
public void onClickMail(View view) {
new SendEmailAsyncTask().execute();
}
class SendEmailAsyncTask extends AsyncTask <Void, Void, Boolean> {
Mail m = new Mail("from@gmail.com", "my password");
public SendEmailAsyncTask() {
if (BuildConfig.DEBUG) Log.v(SendEmailAsyncTask.class.getName(), "SendEmailAsyncTask()");
String[] toArr = { "to mail@gmail.com"};
m.setTo(toArr);
m.setFrom("from mail@gmail.com");
m.setSubject("Email from Android");
m.setBody("body.");
}
@Override
protected Boolean doInBackground(Void... params) {
if (BuildConfig.DEBUG) Log.v(SendEmailAsyncTask.class.getName(), "doInBackground()");
try {
m.send();
return true;
} catch (AuthenticationFailedException e) {
Log.e(SendEmailAsyncTask.class.getName(), "Bad account details");
e.printStackTrace();
return false;
} catch (MessagingException e) {
Log.e(SendEmailAsyncTask.class.getName(), m.getTo(null) + "failed");
e.printStackTrace();
return false;
} catch (Exception e) {
e.printStackTrace();
return false;
}
}