你应该使用viewPager来使用viewpage . setcurrentitem ()

 viewPager.setCurrentItem(n);
 tabLayout.setOnTabSelectedListener(new TabLayout.OnTabSelectedListener() {
            @Override
            public void onTabSelected(TabLayout.Tab tab) {
                viewPager.setCurrentItem(tab.getPosition());
            }

            @Override
            public void onTabUnselected(TabLayout.Tab tab) {
            }

            @Override
            public void onTabReselected(TabLayout.Tab tab) {

            }
        });

用这个:

tabs.getTabAt(index).select();

请记住，如果currentTabIndex和index是相同的，那么这将发送您的流到onTabReselected而不是onTabSelected。

如果您在理解上有困难，这段代码可以帮助您

private void MyTabLayout(){
    TabLayout.Tab myTab = myTabLayout.newTab(); // create a new tab
    myTabLayout.addTab(myTab); // add my new tab to myTabLayout
    myTab.setText("new tab"); 
    myTab.select(); // select the new tab
}

你也可以在你的代码中添加这个:

myTabLayout.setTabTextColors(getColor(R.color.colorNormalTab),getColor(R.color.colorSelectedTab));

如果你知道你想要选择的标签的索引，你可以这样做:

TabLayout tabLayout = (TabLayout) findViewById(R.id.tabs);
TabLayout.Tab tab = tabLayout.getTabAt(someIndex);
tab.select();

即使你使用TabLayout本身而没有ViewPager(这是非典型的，可能是不好的做法，但我见过这样做)，这种技术也是有效的。

用这个:

<android.support.design.widget.TabLayout
    android:id="@+id/patienthomescreen_tabs"
    android:layout_width="match_parent"
    android:layout_height="72sp"
    app:tabGravity="fill"
    app:tabMode="fixed"
    app:tabIndicatorColor="@android:color/white"
    app:tabSelectedTextColor="@color/green"/>

在OnClickListener中:

TabLayout tabLayout = (TabLayout) findViewById(R.id.patienthomescreen_tabs);
TabLayout.Tab tab = tabLayout.getTabAt(someIndex);
tab.select();

请记住，如果currentTabIndex和index是相同的，那么这将发送您的流到onTabReselected而不是onTabSelected。

我使用TabLayout切换片段。它在大多数情况下都是有效的，除了当我试图以编程方式使用tab.select()，我的TabLayout选择一个选项卡时。OnTabSelectedListener将触发onTabSelected(TabLayout。Tab Tab)，这会让我很伤心。我正在寻找一种不触发侦听器的方法来做程序化选择。

So I adapted @kenodoggy 's answer to my use. I was further facing a problem where some of the internal objects would return null (because they weren't created yet, because I was answering onActivityResult() from my fragment, which occurs before onCreate() in the case the activity is singleTask or singleInstance) so I wrote up a detailed if/else sequence which would report the error and fall through without the NullPointerException that would otherwise trigger. I use Timber for logging, if you're not using that substitute with Log.e().

void updateSelectedTabTo(int position) {
    if (tabLayout != null){
        int selected = tabLayout.getSelectedTabPosition();
        if (selected != -1){
            TabLayout.Tab oldTab = tabLayout.getTabAt(0);
            if (oldTab != null){
                View view = oldTab.getCustomView();
                if (view != null){
                    view.setSelected(false);
                }
                else {
                    Timber.e("oldTab customView is null");
                }
            }
            else {
                Timber.e("oldTab is null");
            }
        }
        else {
            Timber.e("selected is -1");
        }
        TabLayout.Tab newTab = tabLayout.getTabAt(position);
        if (newTab != null){
            View view = newTab.getCustomView();
            if (view != null){
                view.setSelected(false);
            }
            else {
                Timber.e("newTab customView is null");
            }
        }
        else {
            Timber.e("newTab is null");
        }
    }
    else {
        Timber.e("tablayout is null");
    }
}

这里，tabLayout是绑定到XML中的tabLayout对象的内存变量。我不使用滚动标签功能，所以我把它也删除了。