在你的情况下，简短而漂亮的代码

Object.fromEntries(str.split(',').map(i => i.split(':')));

如果你有一个像foo: 1, bar: 2这样的字符串，你可以将它转换为一个有效的obj:

str
  .split(',')
  .map(x => x.split(':').map(y => y.trim()))
  .reduce((a, x) => {
    a[x[0]] = x[1];
    return a;
  }, {});

感谢javascript中的niggler。

更新说明:

const obj = 'foo: 1, bar: 2'
  .split(',') // split into ['foo: 1', 'bar: 2']
  .map(keyVal => { // go over each keyVal value in that array
    return keyVal
      .split(':') // split into ['foo', '1'] and on the next loop ['bar', '2']
      .map(_ => _.trim()) // loop over each value in each array and make sure it doesn't have trailing whitespace, the _ is irrelavent because i'm too lazy to think of a good var name for this
  })
  .reduce((accumulator, currentValue) => { // reduce() takes a func and a beginning object, we're making a fresh object
    accumulator[currentValue[0]] = currentValue[1]
    // accumulator starts at the beginning obj, in our case {}, and "accumulates" values to it
    // since reduce() works like map() in the sense it iterates over an array, and it can be chained upon things like map(),
    // first time through it would say "okay accumulator, accumulate currentValue[0] (which is 'foo') = currentValue[1] (which is '1')
    // so first time reduce runs, it starts with empty object {} and assigns {foo: '1'} to it
    // second time through, it "accumulates" {bar: '2'} to it. so now we have {foo: '1', bar: '2'}
    return accumulator
  }, {}) // when there are no more things in the array to iterate over, it returns the accumulated stuff

console.log(obj)

令人困惑的MDN文档:

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/map https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/Reduce

演示:http://jsbin.com/hiduhijevu/edit?js,控制台

功能:

const str2obj = str => {
  return str
    .split(',')
    .map(keyVal => {
      return keyVal
        .split(':')
        .map(_ => _.trim())
    })
    .reduce((accumulator, currentValue) => {
      accumulator[currentValue[0]] = currentValue[1]
      return accumulator
    }, {})
}

console.log(str2obj('foo: 1, bar: 2')) // see? works!

你的字符串看起来像一个没有花括号的JSON字符串。

这应该工作，然后:

obj = eval('({' + str + '})');

警告:这会引入重大的安全漏洞，例如使用不受信任的数据(应用程序用户输入的数据)进行XSS。

你需要使用JSON.parse()将String转换为Object:

var obj = JSON.parse('{ "firstName":"name1", "lastName": "last1" }');

var stringExample = "firstName:name1, lastName:last1 | firstName:name2, lastName:last2";    

var initial_arr_objects = stringExample.split("|");
    var objects =[];
    initial_arr_objects.map((e) => {
          var string = e;
          var fields = string.split(','),fieldObject = {};
        if( typeof fields === 'object') {
           fields.forEach(function(field) {
              var c = field.split(':');
              fieldObject[c[0]] = c[1]; //use parseInt if integer wanted
           });
        }
            console.log(fieldObject)
            objects.push(fieldObject);
        });

"objects"数组将包含所有对象

string = "firstName:name1, lastName:last1";

这是可行的:

var fields = string.split(', '),
    fieldObject = {};

if( typeof fields === 'object') ){
   fields.each(function(field) {
      var c = property.split(':');
      fieldObject[c[0]] = c[1];
   });
}

然而，这并不是有效的。当你有这样的东西时会发生什么:

string = "firstName:name1, lastName:last1, profileUrl:http://localhost/site/profile/1";

Split()将拆分'http'。所以我建议您使用一个特殊的分隔符，如pipe

 string = "firstName|name1, lastName|last1";


   var fields = string.split(', '),
        fieldObject = {};

    if( typeof fields === 'object') ){
       fields.each(function(field) {
          var c = property.split('|');
          fieldObject[c[0]] = c[1];
       });
    }