我找到了这个新方法

bash $ ls -1  | xargs -i -t jar -tvf '{}'| grep Abstract
jar -tvf activation-1.1.jar
jar -tvf antisamy-1.4.3.jar
  2263 Thu Jan 13 21:38:10 IST 2011 org/owasp/validator/html/scan/AbstractAntiSamyScanner.class
...

如果你想，你可以给ls -1 *.jar，或者用查找命令HTH Someone输入xargs。

#!/bin/bash

pattern=$1
shift

for jar in $(find $* -type f -name "*.jar")
do
  match=`jar -tvf $jar | grep $pattern`
  if [ ! -z "$match" ]
  then
    echo "Found in: $jar"
    echo "$match"
  fi
done

要在一个jar文件夹(及其子文件夹)中找到一个类: https://jarscan.com/

Usage: java -jar jarscan.jar [-help | /?]
                    [-dir directory name]
                    [-zip]
                    [-showProgress]
                    <-files | -class | -package>
                    <search string 1> [search string 2]
                    [search string n]

Help:
  -help or /?           Displays this message.

  -dir                  The directory to start searching
                        from default is "."

  -zip                  Also search Zip files

  -showProgress         Show a running count of files read in

  -files or -class      Search for a file or Java class
                        contained in some library.
                        i.e. HttpServlet

  -package              Search for a Java package
                        contained in some library.
                        i.e. javax.servlet.http

  search string         The file or package to
                        search for.
                        i.e. see examples above

例子:

java -jar jarscan.jar -dir C:\Folder\To\Search -showProgress -class GenericServlet

你可以在一个充满jar的目录中找到一个类，它带有一些shell:

寻找类“FooBar”:

LIB_DIR=/some/dir/full/of/jarfiles
for jarfile in $(find $LIBDIR -name "*.jar"); do
   echo "--------$jarfile---------------"
   jar -tvf $jarfile | grep FooBar
done

不久前，我专门为此写了一个程序:https://github.com/javalite/jar-explorer

还有两个不同的实用程序，称为“JarScan”，可以完全满足您的要求: JarScan (inetfeedback.com)和JarScan (java.net)