如何在大量jar文件中找到特定的类名?

(查找实际的类名,而不是引用它的类。)


当前回答

不知道为什么这里的脚本从来都不适合我。如此:

#!/bin/bash
for i in *.jar; do jar -tf "$i" | grep $1 | xargs -I{} echo -e "$i : {}" ; done

其他回答

查找匹配给定字符串的jar:

找到。name \*.jar -exec grep -l YOUR_CLASSNAME {} \;

文件名:searchForFiles.py

import os, zipfile, glob, sys

def main():
    searchFile = sys.argv[1] #class file to search for, sent from batch file below (optional, see second block of code below)
    listOfFilesInJar = []
    for file in glob.glob("*.jar"):
        archive = zipfile.ZipFile(file, 'r')
        for x in archive.namelist():
            if str(searchFile) in str(x):
                listOfFilesInJar.append(file)

    for something in listOfFilesInJar:
        print("location of "+str(searchFile)+": ",something)

if __name__ == "__main__":
    sys.exit(main())

你可以通过创建一个带有以下文本的.bat文件(用你正在搜索的文件替换“AddWorkflows.class”)来轻松运行:

(文件:CallSearchForFiles.bat)

@echo off
python -B -c "import searchForFiles;x=searchForFiles.main();" AddWorkflows.class
pause

您可以双击CallSearchForFiles.bat来运行它,或者从命令行“CallSearchForFiles.bat SearchFile.class”调用它。

单击以查看示例输出

你可以使用locate和grep:

locate jar | xargs grep 'my.class'

确保在使用locate之前运行updatedb。

要在一个jar文件夹(及其子文件夹)中找到一个类: https://jarscan.com/

Usage: java -jar jarscan.jar [-help | /?]
                    [-dir directory name]
                    [-zip]
                    [-showProgress]
                    <-files | -class | -package>
                    <search string 1> [search string 2]
                    [search string n]

Help:
  -help or /?           Displays this message.

  -dir                  The directory to start searching
                        from default is "."

  -zip                  Also search Zip files

  -showProgress         Show a running count of files read in

  -files or -class      Search for a file or Java class
                        contained in some library.
                        i.e. HttpServlet

  -package              Search for a Java package
                        contained in some library.
                        i.e. javax.servlet.http

  search string         The file or package to
                        search for.
                        i.e. see examples above

例子:

java -jar jarscan.jar -dir C:\Folder\To\Search -showProgress -class GenericServlet

使用unzip (zipinfo)的bash脚本解决方案。在Ubuntu 12上测试。

#!/bin/bash

# ./jarwalker.sh "/a/Starting/Path" "aClassName"

IFS=$'\n'
jars=( $( find -P "$1" -type f -name "*.jar" ) )

for jar in ${jars[*]}
    do
        classes=( $( zipinfo -1 ${jar} | awk -F '/' '{print $NF}' | grep .class | awk -F '.' '{print $1}' ) )
        if [ ${#classes[*]} -ge 0 ]; then
            for class in ${classes[*]}
                do
                    if [ ${class} == "$2" ]; then
                        echo "Found in ${jar}"
                    fi
                done
        fi
    done