我试图使用scikit-learn的LabelEncoder来编码字符串标签的pandas DataFrame。由于数据帧有许多(50+)列,我想避免为每一列创建一个LabelEncoder对象;我宁愿只有一个大的LabelEncoder对象,它可以跨所有数据列工作。

将整个DataFrame扔到LabelEncoder中会产生以下错误。请记住,我在这里使用的是虚拟数据;实际上,我正在处理大约50列的字符串标记数据,所以需要一个解决方案,不引用任何列的名称。

import pandas
from sklearn import preprocessing 

df = pandas.DataFrame({
    'pets': ['cat', 'dog', 'cat', 'monkey', 'dog', 'dog'], 
    'owner': ['Champ', 'Ron', 'Brick', 'Champ', 'Veronica', 'Ron'], 
    'location': ['San_Diego', 'New_York', 'New_York', 'San_Diego', 'San_Diego', 
                 'New_York']
})

le = preprocessing.LabelEncoder()

le.fit(df)

回溯(最近一次调用): 文件“”,第1行,在 文件"/Users/bbalin/anaconda/lib/python2.7/site-packages/sklearn/预处理/label.py",第103行 y = column_or_1d(y, warn=True) 文件"/Users/bbalin/anaconda/lib/python2.7/site-packages/sklearn/utils/validation.py",第306行,在column_or_1d中 raise ValueError("错误的输入形状{0}".format(形状)) ValueError:错误的输入形状(6,3)

对于如何解决这个问题有什么想法吗?


当前回答

import pandas as pd
from sklearn.preprocessing import LabelEncoder

train=pd.read_csv('.../train.csv')

#X=train.loc[:,['waterpoint_type_group','status','waterpoint_type','source_class']].values
# Create a label encoder object 
def MultiLabelEncoder(columnlist,dataframe):
    for i in columnlist:

        labelencoder_X=LabelEncoder()
        dataframe[i]=labelencoder_X.fit_transform(dataframe[i])
columnlist=['waterpoint_type_group','status','waterpoint_type','source_class','source_type']
MultiLabelEncoder(columnlist,train)

在这里,我正在从位置读取一个csv,在函数中,我正在传递列列表,我想要labelencode和dataframe,我想应用这个。

其他回答

下面是我一次性转换多列的解决方案,以及精确的inverse_transform

from sklearn import preprocessing
columns = ['buying','maint','lug_boot','safety','cls']  # columns names where transform is required
for X in columns:
  exec(f'le_{X} = preprocessing.LabelEncoder()')  #create label encoder with name "le_X", where X is column name
  exec(f'df.{X} = le_{X}.fit_transform(df.{X})')  #execute fit transform for column X with respective lable encoder "le_X", where X is column name
df.head()  # to display transformed results

for X in columns:
  exec(f'df.{X} = le_{X}.inverse_transform(df.{X})')  #execute inverse_transform for column X with respective lable encoder "le_X", where X is column name
df.head() # to display Inverse transformed results of df

正如larsmans提到的,LabelEncoder()只接受1维数组作为参数。也就是说,可以很容易地滚动自己的标签编码器,对您选择的多个列进行操作,并返回转换后的数据框架。我在这里的代码部分基于Zac Stewart的优秀博客文章。

创建自定义编码器只需要创建一个响应fit()、transform()和fit_transform()方法的类。对你来说,一个好的开始可能是这样的:

import pandas as pd
from sklearn.preprocessing import LabelEncoder
from sklearn.pipeline import Pipeline

# Create some toy data in a Pandas dataframe
fruit_data = pd.DataFrame({
    'fruit':  ['apple','orange','pear','orange'],
    'color':  ['red','orange','green','green'],
    'weight': [5,6,3,4]
})

class MultiColumnLabelEncoder:
    def __init__(self,columns = None):
        self.columns = columns # array of column names to encode

    def fit(self,X,y=None):
        return self # not relevant here

    def transform(self,X):
        '''
        Transforms columns of X specified in self.columns using
        LabelEncoder(). If no columns specified, transforms all
        columns in X.
        '''
        output = X.copy()
        if self.columns is not None:
            for col in self.columns:
                output[col] = LabelEncoder().fit_transform(output[col])
        else:
            for colname,col in output.iteritems():
                output[colname] = LabelEncoder().fit_transform(col)
        return output

    def fit_transform(self,X,y=None):
        return self.fit(X,y).transform(X)

假设我们想对两个分类属性(fruit和color)进行编码,而不使用数字属性权重。我们可以这样做:

MultiColumnLabelEncoder(columns = ['fruit','color']).fit_transform(fruit_data)

它转换了我们的fruit_data数据集

to

传递给它一个完全由分类变量组成的数据框架,省略columns参数将导致每个列都被编码(我相信这是你最初寻找的):

MultiColumnLabelEncoder().fit_transform(fruit_data.drop('weight',axis=1))

这个转换

to

.

请注意,当它试图编码已经是数值的属性时可能会阻塞(如果您愿意,可以添加一些代码来处理这个问题)。

另一个很好的特性是我们可以在管道中使用这个自定义转换器:

encoding_pipeline = Pipeline([
    ('encoding',MultiColumnLabelEncoder(columns=['fruit','color']))
    # add more pipeline steps as needed
])
encoding_pipeline.fit_transform(fruit_data)

如果你在数据框架中有数值和类别两种类型的数据 你可以使用:这里X是我的数据框架,有分类变量和数值变量

from sklearn import preprocessing
le = preprocessing.LabelEncoder()

for i in range(0,X.shape[1]):
    if X.dtypes[i]=='object':
        X[X.columns[i]] = le.fit_transform(X[X.columns[i]])

注意:如果你对转换它们不感兴趣,这个技巧是很好的。

这个怎么样?

def MultiColumnLabelEncode(choice, columns, X):
    LabelEncoders = []
    if choice == 'encode':
        for i in enumerate(columns):
            LabelEncoders.append(LabelEncoder())
        i=0    
        for cols in columns:
            X[:, cols] = LabelEncoders[i].fit_transform(X[:, cols])
            i += 1
    elif choice == 'decode': 
        for cols in columns:
            X[:, cols] = LabelEncoders[i].inverse_transform(X[:, cols])
            i += 1
    else:
        print('Please select correct parameter "choice". Available parameters: encode/decode')

这不是最有效的,但它工作,它是超级简单。

这是一年半后的事实,但我也需要能够。transform()多个熊猫数据帧列一次(以及能够。inverse_transform()他们)。这扩展了上面@PriceHardman的优秀建议:

class MultiColumnLabelEncoder(LabelEncoder):
    """
    Wraps sklearn LabelEncoder functionality for use on multiple columns of a
    pandas dataframe.

    """
    def __init__(self, columns=None):
        self.columns = columns

    def fit(self, dframe):
        """
        Fit label encoder to pandas columns.

        Access individual column classes via indexig `self.all_classes_`

        Access individual column encoders via indexing
        `self.all_encoders_`
        """
        # if columns are provided, iterate through and get `classes_`
        if self.columns is not None:
            # ndarray to hold LabelEncoder().classes_ for each
            # column; should match the shape of specified `columns`
            self.all_classes_ = np.ndarray(shape=self.columns.shape,
                                           dtype=object)
            self.all_encoders_ = np.ndarray(shape=self.columns.shape,
                                            dtype=object)
            for idx, column in enumerate(self.columns):
                # fit LabelEncoder to get `classes_` for the column
                le = LabelEncoder()
                le.fit(dframe.loc[:, column].values)
                # append the `classes_` to our ndarray container
                self.all_classes_[idx] = (column,
                                          np.array(le.classes_.tolist(),
                                                  dtype=object))
                # append this column's encoder
                self.all_encoders_[idx] = le
        else:
            # no columns specified; assume all are to be encoded
            self.columns = dframe.iloc[:, :].columns
            self.all_classes_ = np.ndarray(shape=self.columns.shape,
                                           dtype=object)
            for idx, column in enumerate(self.columns):
                le = LabelEncoder()
                le.fit(dframe.loc[:, column].values)
                self.all_classes_[idx] = (column,
                                          np.array(le.classes_.tolist(),
                                                  dtype=object))
                self.all_encoders_[idx] = le
        return self

    def fit_transform(self, dframe):
        """
        Fit label encoder and return encoded labels.

        Access individual column classes via indexing
        `self.all_classes_`

        Access individual column encoders via indexing
        `self.all_encoders_`

        Access individual column encoded labels via indexing
        `self.all_labels_`
        """
        # if columns are provided, iterate through and get `classes_`
        if self.columns is not None:
            # ndarray to hold LabelEncoder().classes_ for each
            # column; should match the shape of specified `columns`
            self.all_classes_ = np.ndarray(shape=self.columns.shape,
                                           dtype=object)
            self.all_encoders_ = np.ndarray(shape=self.columns.shape,
                                            dtype=object)
            self.all_labels_ = np.ndarray(shape=self.columns.shape,
                                          dtype=object)
            for idx, column in enumerate(self.columns):
                # instantiate LabelEncoder
                le = LabelEncoder()
                # fit and transform labels in the column
                dframe.loc[:, column] =\
                    le.fit_transform(dframe.loc[:, column].values)
                # append the `classes_` to our ndarray container
                self.all_classes_[idx] = (column,
                                          np.array(le.classes_.tolist(),
                                                  dtype=object))
                self.all_encoders_[idx] = le
                self.all_labels_[idx] = le
        else:
            # no columns specified; assume all are to be encoded
            self.columns = dframe.iloc[:, :].columns
            self.all_classes_ = np.ndarray(shape=self.columns.shape,
                                           dtype=object)
            for idx, column in enumerate(self.columns):
                le = LabelEncoder()
                dframe.loc[:, column] = le.fit_transform(
                        dframe.loc[:, column].values)
                self.all_classes_[idx] = (column,
                                          np.array(le.classes_.tolist(),
                                                  dtype=object))
                self.all_encoders_[idx] = le
        return dframe.loc[:, self.columns].values

    def transform(self, dframe):
        """
        Transform labels to normalized encoding.
        """
        if self.columns is not None:
            for idx, column in enumerate(self.columns):
                dframe.loc[:, column] = self.all_encoders_[
                    idx].transform(dframe.loc[:, column].values)
        else:
            self.columns = dframe.iloc[:, :].columns
            for idx, column in enumerate(self.columns):
                dframe.loc[:, column] = self.all_encoders_[idx]\
                    .transform(dframe.loc[:, column].values)
        return dframe.loc[:, self.columns].values

    def inverse_transform(self, dframe):
        """
        Transform labels back to original encoding.
        """
        if self.columns is not None:
            for idx, column in enumerate(self.columns):
                dframe.loc[:, column] = self.all_encoders_[idx]\
                    .inverse_transform(dframe.loc[:, column].values)
        else:
            self.columns = dframe.iloc[:, :].columns
            for idx, column in enumerate(self.columns):
                dframe.loc[:, column] = self.all_encoders_[idx]\
                    .inverse_transform(dframe.loc[:, column].values)
        return dframe.loc[:, self.columns].values

例子:

如果df和df_copy()是混合类型的pandas数据帧,你可以将MultiColumnLabelEncoder()应用到dtype=object列上,方法如下:

# get `object` columns
df_object_columns = df.iloc[:, :].select_dtypes(include=['object']).columns
df_copy_object_columns = df_copy.iloc[:, :].select_dtypes(include=['object']).columns

# instantiate `MultiColumnLabelEncoder`
mcle = MultiColumnLabelEncoder(columns=object_columns)

# fit to `df` data
mcle.fit(df)

# transform the `df` data
mcle.transform(df)

# returns output like below
array([[1, 0, 0, ..., 1, 1, 0],
       [0, 5, 1, ..., 1, 1, 2],
       [1, 1, 1, ..., 1, 1, 2],
       ..., 
       [3, 5, 1, ..., 1, 1, 2],

# transform `df_copy` data
mcle.transform(df_copy)

# returns output like below (assuming the respective columns 
# of `df_copy` contain the same unique values as that particular 
# column in `df`
array([[1, 0, 0, ..., 1, 1, 0],
       [0, 5, 1, ..., 1, 1, 2],
       [1, 1, 1, ..., 1, 1, 2],
       ..., 
       [3, 5, 1, ..., 1, 1, 2],

# inverse `df` data
mcle.inverse_transform(df)

# outputs data like below
array([['August', 'Friday', '2013', ..., 'N', 'N', 'CA'],
       ['April', 'Tuesday', '2014', ..., 'N', 'N', 'NJ'],
       ['August', 'Monday', '2014', ..., 'N', 'N', 'NJ'],
       ..., 
       ['February', 'Tuesday', '2014', ..., 'N', 'N', 'NJ'],
       ['April', 'Tuesday', '2014', ..., 'N', 'N', 'NJ'],
       ['March', 'Tuesday', '2013', ..., 'N', 'N', 'NJ']], dtype=object)

# inverse `df_copy` data
mcle.inverse_transform(df_copy)

# outputs data like below
array([['August', 'Friday', '2013', ..., 'N', 'N', 'CA'],
       ['April', 'Tuesday', '2014', ..., 'N', 'N', 'NJ'],
       ['August', 'Monday', '2014', ..., 'N', 'N', 'NJ'],
       ..., 
       ['February', 'Tuesday', '2014', ..., 'N', 'N', 'NJ'],
       ['April', 'Tuesday', '2014', ..., 'N', 'N', 'NJ'],
       ['March', 'Tuesday', '2013', ..., 'N', 'N', 'NJ']], dtype=object)

你可以通过索引访问单独的列类、列标签和用于适合每个列的列编码器:

mcle.all_classes_ mcle.all_encoders_ mcle.all_labels_