没有什么特别的

let str = NSString(format:"%d , %f, %ld, %@", INT_VALUE, FLOAT_VALUE, LONG_VALUE, STRING_VALUE)

我认为这可以帮助你:

import Foundation

let timeNow = time(nil)
let aStr = String(format: "%@%x", "timeNow in hex: ", timeNow)
print(aStr)

结果示例:

timeNow in hex: 5cdc9c8d

由于字符串(格式:"%s"…)在运行时崩溃，下面的代码允许编写类似"hello".center(42);“世界”.alignLeft (42):

extension String {

    // note: symbol names match to nim std/strutils lib:

    func align (_ boxsz: UInt) -> String {
        self.withCString { String(format: "%\(boxsz)s", $0) }
    }

    func alignLeft (_ boxsz: UInt) -> String {
        self.withCString { String(format: "%-\(boxsz)s", $0) }
    }

    func center (_ boxsz: UInt) -> String {
        let n = self.count
        guard boxsz > n else { return self }
        let padding = boxsz - UInt(n)
        let R = padding / 2
        guard R > 0 else { return " " + self }
        let L = (padding%2 == 0) ? R : (R+1)
        return " ".withCString { String(format: "%\(L)s\(self)%\(R)s", $0,$0) }
    }

}

String(format:)的美妙之处在于，你可以保存一个格式化字符串，然后在很多地方重复使用。它也可以本地化到这个地方。在插值的情况下，你必须一遍又一遍地写。

没有什么特别的

let str = NSString(format:"%d , %f, %ld, %@", INT_VALUE, FLOAT_VALUE, LONG_VALUE, STRING_VALUE)

成功尝试一下:

 var letters:NSString = "abcdefghijkl"
        var strRendom = NSMutableString.stringWithCapacity(strlength)
        for var i=0; i<strlength; i++ {
            let rndString = Int(arc4random() % 12)
            //let strlk = NSString(format: <#NSString#>, <#CVarArg[]#>)
            let strlk = NSString(format: "%c", letters.characterAtIndex(rndString))
            strRendom.appendString(String(strlk))
        }