我有一本嵌套的字典。是否只有一种方法可以安全地传递价值观?
try:
example_dict['key1']['key2']
except KeyError:
pass
或者python有一个类似get()的方法用于嵌套字典?
我有一本嵌套的字典。是否只有一种方法可以安全地传递价值观?
try:
example_dict['key1']['key2']
except KeyError:
pass
或者python有一个类似get()的方法用于嵌套字典?
当前回答
Glom是一个很好的库,可以进入点查询:
In [1]: from glom import glom
In [2]: data = {'a': {'b': {'c': 'd'}}}
In [3]: glom(data, "a.b.c")
Out[3]: 'd'
查询失败有一个很好的堆栈跟踪,指出确切的故障点:
In [4]: glom(data, "a.b.foo")
---------------------------------------------------------------------------
PathAccessError Traceback (most recent call last)
<ipython-input-4-2a3467493ac4> in <module>
----> 1 glom(data, "a.b.foo")
~/.cache/pypoetry/virtualenvs/neural-knapsack-dE7ihQtM-py3.8/lib/python3.8/site-packages/glom/core.py in glom(target, spec, **kwargs)
2179
2180 if err:
-> 2181 raise err
2182 return ret
2183
PathAccessError: error raised while processing, details below.
Target-spec trace (most recent last):
- Target: {'a': {'b': {'c': 'd'}}}
- Spec: 'a.b.foo'
glom.core.PathAccessError: could not access 'foo', part 2 of Path('a', 'b', 'foo'), got error: KeyError('foo')
默认保护:
In [5]: glom(data, "a.b.foo", default="spam")
Out[5]: 'spam'
格洛姆的魅力在于多功能的规格参数。例如,可以很容易地从以下数据中提取所有的名字:
In [8]: data = {
...: "people": [
...: {"first_name": "Alice", "last_name": "Adams"},
...: {"first_name": "Bob", "last_name": "Barker"}
...: ]
...: }
In [9]: glom(data, ("people", ["first_name"]))
Out[9]: ['Alice', 'Bob']
更多的例子请阅读glom文档。
其他回答
下面是一个基于unutbu函数答案的解决方案:
Python命名指南 默认值作为参数 不用try,只是检查key是否在object上
def safe_get(dictionary, *keys, default=None):
for key in keys:
if key not in dictionary:
return default
dictionary = dictionary[key]
return dictionary
对于二级键检索,你可以这样做:
key2_value = (example_dict.get('key1') or {}).get('key2')
一个简单的类,可以包装字典,并根据键进行检索:
class FindKey(dict):
def get(self, path, default=None):
keys = path.split(".")
val = None
for key in keys:
if val:
if isinstance(val, list):
val = [v.get(key, default) if v else None for v in val]
else:
val = val.get(key, default)
else:
val = dict.get(self, key, default)
if not val:
break
return val
例如:
person = {'person':{'name':{'first':'John'}}}
FindDict(person).get('person.name.first') # == 'John'
如果该键不存在,则默认返回None。你可以在FindDict包装器中使用default=键覆盖它,例如':
FindDict(person, default='').get('person.name.last') # == doesn't exist, so ''
因为如果缺少一个键就会引发一个键错误是合理的,我们甚至可以不检查它,让它像这样单一:
def get_dict(d, kl):
cur = d[kl[0]]
return get_dict(cur, kl[1:]) if len(kl) > 1 else cur
从Python 3.4开始,你可以使用suppress (KeyError)来访问嵌套的json对象,而不用担心KeyError
from contextlib import suppress
with suppress(KeyError):
a1 = json_obj['key1']['key2']['key3']
a2 = json_obj['key4']['key5']['key6']
a3 = json_obj['key7']['key8']['key9']
Techdragon提供。看看他的回答,了解更多细节:https://stackoverflow.com/a/45874251/1189659