我发现了更多的解决方案，因为我想有每一行适当缩进:

You may use echo: echo "this is line one" \ "\n""this is line two" \ "\n""this is line three" \ > filename It does not work if you put "\n" just before \ on the end of a line. Alternatively, you can use printf for better portability (I happened to have a lot of problems with echo): printf '%s\n' \ "this is line one" \ "this is line two" \ "this is line three" \ > filename Yet another solution might be: text='' text="${text}this is line one\n" text="${text}this is line two\n" text="${text}this is line three\n" printf "%b" "$text" > filename or text='' text+="this is line one\n" text+="this is line two\n" text+="this is line three\n" printf "%b" "$text" > filename Another solution is achieved by mixing printf and sed. if something then printf '%s' ' this is line one this is line two this is line three ' | sed '1d;$d;s/^ //g' fi It is not easy to refactor code formatted like this as you hardcode the indentation level into the code. It is possible to use a helper function and some variable substitution tricks: unset text _() { text="${text}${text+ }${*}"; } # That's an empty line which demonstrates the reasoning behind # the usage of "+" instead of ":+" in the variable substitution # above. _ "" _ "this is line one" _ "this is line two" _ "this is line three" unset -f _ printf '%s' "$text"

这里只提一个简单的单行连接，因为它有时很有用。

# for bash

v=" guga "$'\n'"   puga "

# Just for an example.
v2="bar "$'\n'"   foo "$'\n'"$v"

# Let's simplify the previous version of $v2.
n=$'\n'
v3="bar ${n}   foo ${n}$v"

echo "$v3" 

你会得到这样的结果

bar 
   foo 
 guga 
   puga 

所有前导和结尾空格将被保留

echo "$v3" > filename

有很多方法可以做到这一点。对我来说，将缩进的字符串输送到sed中效果很好。

printf_strip_indent() {
   printf "%s" "$1" | sed "s/^\s*//g" 
}

printf_strip_indent "this is line one
this is line two
this is line three" > "file.txt"

这个答案是基于Mateusz Piotrowski的回答，但做了一些改进。

Echo在传递给它的参数之间添加空格。$text受变量扩展和单词分割的影响，所以你的echo命令相当于:

echo -e "this" "is" "line" "one\n" "this" "is" "line" "two\n"  ...

你可以看到在“this”之前加了一个空格。你可以删除换行符，并引用$text来保留换行符:

text="this is line one
this is line two
this is line three"

echo "$text" > filename

或者你可以使用printf，它比echo更健壮和可移植:

printf "%s\n" "this is line one" "this is line two" "this is line three" > filename

在支持大括号展开的bash中，你甚至可以这样做:

printf "%s\n" "this is line "{one,two,three} > filename

如果你把它放在下面，它就会工作:

AA='first line
\nsecond line 
\nthird line'
echo $AA
output:
first line
second line
third line

我听到这个答案，但也想把它输送到另一个命令。给出的答案是正确的，但如果有人想要管道它，您需要在像这样的多行字符串之前管道它

echo | tee /tmp/pipetest << EndOfMessage
This is line 1.
This is line 2.
Line 3.
EndOfMessage

这将允许您拥有多行字符串，但也可以将其放在后续命令的stdin中。