PHP将所有数组都视为关联数组,因此没有任何内置函数。谁能推荐一种相当有效的方法来检查数组是否“是一个列表”(只包含从0开始的数字键)?
基本上,我希望能够区分这些:
$sequentialArray = [
'apple', 'orange', 'tomato', 'carrot'
];
这:
$assocArray = [
'fruit1' => 'apple',
'fruit2' => 'orange',
'veg1' => 'tomato',
'veg2' => 'carrot'
];
检查数组是否有所有的关联键。使用stdClass & get_object_vars ^):
$assocArray = array('fruit1' => 'apple',
'fruit2' => 'orange',
'veg1' => 'tomato',
'veg2' => 'carrot');
$assoc_object = (object) $assocArray;
$isAssoc = (count($assocArray) === count (get_object_vars($assoc_object)));
var_dump($isAssoc); // true
为什么?函数get_object_vars只返回可访问的属性(请参阅在将数组转换为对象期间发生的更多信息)。然后,只是逻辑上:如果基本数组元素的计数等于对象的可访问属性的计数-所有键都是关联的。
一些测试:
$assocArray = array('apple', 'orange', 'tomato', 'carrot');
$assoc_object = (object) $assocArray;
$isAssoc = (count($assocArray) === count (get_object_vars($assoc_object)));
var_dump($isAssoc); // false
//...
$assocArray = array( 0 => 'apple', 'orange', 'tomato', '4' => 'carrot');
$assoc_object = (object) $assocArray;
$isAssoc = (count($assocArray) === count (get_object_vars($assoc_object)));
var_dump($isAssoc); // false
//...
$assocArray = array('fruit1' => 'apple',
NULL => 'orange',
'veg1' => 'tomato',
'veg2' => 'carrot');
$assoc_object = (object) $assocArray;
$isAssoc = (count($assocArray) === count (get_object_vars($assoc_object)));
var_dump($isAssoc); //false
Etc.
我认为标量数组的定义因应用程序而异。也就是说,一些应用程序将需要更严格的定义标量数组,而一些应用程序将需要更宽松的定义。
下面我将介绍3种不同严格程度的方法。
<?php
/**
* Since PHP stores all arrays as associative internally, there is no proper
* definition of a scalar array.
*
* As such, developers are likely to have varying definitions of scalar array,
* based on their application needs.
*
* In this file, I present 3 increasingly strict methods of determining if an
* array is scalar.
*
* @author David Farrell <DavidPFarrell@gmail.com>
*/
/**
* isArrayWithOnlyIntKeys defines a scalar array as containing
* only integer keys.
*
* If you are explicitly setting integer keys on an array, you
* may need this function to determine scalar-ness.
*
* @param array $a
* @return boolean
*/
function isArrayWithOnlyIntKeys(array $a)
{
if (!is_array($a))
return false;
foreach ($a as $k => $v)
if (!is_int($k))
return false;
return true;
}
/**
* isArrayWithOnlyAscendingIntKeys defines a scalar array as
* containing only integer keys in ascending (but not necessarily
* sequential) order.
*
* If you are performing pushes, pops, and unsets on your array,
* you may need this function to determine scalar-ness.
*
* @param array $a
* @return boolean
*/
function isArrayWithOnlyAscendingIntKeys(array $a)
{
if (!is_array($a))
return false;
$prev = null;
foreach ($a as $k => $v)
{
if (!is_int($k) || (null !== $prev && $k <= $prev))
return false;
$prev = $k;
}
return true;
}
/**
* isArrayWithOnlyZeroBasedSequentialIntKeys defines a scalar array
* as containing only integer keys in sequential, ascending order,
* starting from 0.
*
* If you are only performing operations on your array that are
* guaranteed to either maintain consistent key values, or that
* re-base the keys for consistency, then you can use this function.
*
* @param array $a
* @return boolean
*/
function isArrayWithOnlyZeroBasedSequentialIntKeys(array $a)
{
if (!is_array($a))
return false;
$i = 0;
foreach ($a as $k => $v)
if ($i++ !== $k)
return false;
return true;
}
我的解决方案是获得如下数组的键,并检查是否键不是整数:
private function is_hash($array) {
foreach($array as $key => $value) {
return ! is_int($key);
}
return false;
}
像下面这样获取哈希数组的array_keys是错误的:
array_keys(array(
"abc" => "gfb",
"bdc" => "dbc"
)
);
将输出:
array(
0 => "abc",
1 => "bdc"
)
因此,将它与评分最高的答案中提到的一系列数字进行比较并不是一个好主意。它总是说它是一个哈希数组如果你试着比较键和范围。
这是函数-
public function is_assoc_array($array){
if(is_array($array) !== true){
return false;
}else{
$check = json_decode(json_encode($array));
if(is_object($check) === true){
return true;
}else{
return false;
}
}
}
一些例子
print_r((is_assoc_array(['one','two','three']))===true?'Yes':'No'); \\No
print_r(is_assoc_array(['one'=>'one','two'=>'two','three'=>'three'])?'Yes':'No'); \\Yes
print_r(is_assoc_array(['1'=>'one','2'=>'two','3'=>'three'])?'Yes':'No'); \\Yes
print_r(is_assoc_array(['0'=>'one','1'=>'two','2'=>'three'])?'Yes':'No'); \\No
在其中一个答案中@devios1有一个类似的解决方案,但这只是使用PHP的内置json相关函数的另一种方式。我还没有检查这个解决方案在性能方面如何与其他已经在这里发布的解决方案相比。但它确实帮助我解决了这个问题。希望这能有所帮助。