也许有人可以帮助解释为什么，但如果你试图从App.js页面上的新安装的Create React App中点击props来查找位置，你会得到:

无法读取未定义的属性“搜索”

即使我有App.js作为主路径:

<Route exact path='/' render={props => (

只在App.js上，使用window。地点对我来说很合适:

import queryString from 'query-string';
...
const queryStringParams = queryString.parse(window.location.search);

从v4开始，React路由器不再直接在其location对象中提供查询参数。原因是

There are a number of popular packages that do query string parsing/stringifying slightly differently, and each of these differences might be the "correct" way for some users and "incorrect" for others. If React Router picked the "right" one, it would only be right for some people. Then, it would need to add a way for other users to substitute in their preferred query parsing package. There is no internal use of the search string by React Router that requires it to parse the key-value pairs, so it doesn't have a need to pick which one of these should be "right".

包含了这个之后，只解析location会更有意义。在需要查询对象的视图组件中搜索。

你可以通过覆盖react-router中的withRouter来实现这一点

customWithRouter.js

import { compose, withPropsOnChange } from 'recompose';
import { withRouter } from 'react-router';
import queryString from 'query-string';

const propsWithQuery = withPropsOnChange(
    ['location', 'match'],
    ({ location, match }) => {
        return {
            location: {
                ...location,
                query: queryString.parse(location.search)
            },
            match
        };
    }
);

export default compose(withRouter, propsWithQuery)

React Router v4不再有props.location.query对象(见github讨论)。因此，已接受的答案将不适用于较新的项目。

v4的解决方案是使用外部库查询字符串来解析props.location.search

const qs = require('query-string');
//or
import * as qs from 'query-string';

console.log(location.search);
//=> '?foo=bar'

const parsed = qs.parse(location.search);
console.log(parsed);
//=> {foo: 'bar'}

如果你没有得到这个。道具…根据其他答案，您可能需要使用withthrouter (docs v4):

import React from 'react'
import PropTypes from 'prop-types'
import { withRouter } from 'react-router'

// A simple component that shows the pathname of the current location
class ShowTheLocation extends React.Component {
  static propTypes = {
    match: PropTypes.object.isRequired,
    location: PropTypes.object.isRequired,
    history: PropTypes.object.isRequired
  }

  render() {
    const { match, location, history } = this.props

    return (
      <div>You are now at {location.pathname}</div>
    )
  }
}

// Create a new component that is "connected" (to borrow redux terminology) to the router.  
const TwitterSsoButton = withRouter(ShowTheLocation)  

// This gets around shouldComponentUpdate
withRouter(connect(...)(MyComponent))

// This does not
connect(...)(withRouter(MyComponent))

在React-Router-Dom V5中

function useQeury() {
 const [query, setQeury] = useState({});
 const search = useLocation().search.slice(1);

 useEffect(() => {
   setQeury(() => {
     const query = new URLSearchParams(search);
     const result = {};
     for (let [key, value] of query.entries()) {
       result[key] = value;
     }
     setQeury(result);
   }, [search]);
 }, [search, setQeury]);

 return { ...query };
}


// you can destruct query search like:
const {page , search} = useQuery()

// result
// {page : 1 , Search: "ABC"}

在需要访问可以使用的参数的组件中

this.props.location.state.from.search

这将显示整个查询字符串(在?标志)