如何在我的路由中定义路由。jsx文件捕获__firebase_request_key参数值从一个URL生成的Twitter的单点登录过程后，从他们的服务器重定向?
http://localhost:8000/#/signin?_k=v9ifuf&__firebase_request_key=blablabla
我尝试了以下路由配置，但:redirectParam没有捕获提到的参数:
<Router>
<Route path="/" component={Main}>
<Route path="signin" component={SignIn}>
<Route path=":redirectParam" component={TwitterSsoButton} />
</Route>
</Route>
</Router>
当前回答
假设有一个url如下所示
http://localhost:3000/callback?code=6c3c9b39-de2f-3bf4-a542-3e77a64d3341
如果我们想从该URL提取代码，下面的方法将工作。
const authResult = new URLSearchParams(window.location.search);
const code = authResult.get('code')
其他回答
在React-Router-Dom V5中
function useQeury() {
const [query, setQeury] = useState({});
const search = useLocation().search.slice(1);
useEffect(() => {
setQeury(() => {
const query = new URLSearchParams(search);
const result = {};
for (let [key, value] of query.entries()) {
result[key] = value;
}
setQeury(result);
}, [search]);
}, [search, setQeury]);
return { ...query };
}
// you can destruct query search like:
const {page , search} = useQuery()
// result
// {page : 1 , Search: "ABC"}
如果你的路由器是这样的
<Route exact path="/category/:id" component={ProductList}/>
你会得到这样的id
this.props.match.params.id
如果你没有得到这个。道具…根据其他答案，您可能需要使用withthrouter (docs v4):
import React from 'react'
import PropTypes from 'prop-types'
import { withRouter } from 'react-router'
// A simple component that shows the pathname of the current location
class ShowTheLocation extends React.Component {
static propTypes = {
match: PropTypes.object.isRequired,
location: PropTypes.object.isRequired,
history: PropTypes.object.isRequired
}
render() {
const { match, location, history } = this.props
return (
<div>You are now at {location.pathname}</div>
)
}
}
// Create a new component that is "connected" (to borrow redux terminology) to the router.
const TwitterSsoButton = withRouter(ShowTheLocation)
// This gets around shouldComponentUpdate
withRouter(connect(...)(MyComponent))
// This does not
connect(...)(withRouter(MyComponent))
React路由器v4
使用组件
<Route path="/users/:id" component={UserPage}/>
this.props.match.params.id
该组件自动使用路由道具呈现。
使用渲染
<Route path="/users/:id" render={(props) => <UserPage {...props} />}/>
this.props.match.params.id
路由道具被传递给渲染函数。
不是反应的方式，但我相信这个单行函数可以帮助你:)
const getQueryParams = (query = null) => [...(new URLSearchParams(query||window.location.search||"")).entries()].reduce((a,[k,v])=>(a[k]=v,a),{});
或:
const getQueryParams = (query = null) => (query||window.location.search.replace('?','')).split('&').map(e=>e.split('=').map(decodeURIComponent)).reduce((r,[k,v])=>(r[k]=v,r),{});
或完整版:
const getQueryParams = (query = null) => {
return (
(query || window.location.search.replace("?", ""))
// get array of KeyValue pairs
.split("&")
// Decode values
.map((pair) => {
let [key, val] = pair.split("=");
return [key, decodeURIComponent(val || "")];
})
// array to object
.reduce((result, [key, val]) => {
result[key] = val;
return result;
}, {})
);
};
例子: URL:…?= = 1 b =建发集团有限公司的测试 代码:
getQueryParams()
//=> {a: "1", b: "c", d: "test"}
getQueryParams('type=user&name=Jack&age=22')
//=> {type: "user", name: "Jack", age: "22" }
