我需要只使用文件名来显示图像,而不是使用资源id。

ImageView imgView = new ImageView(this);
imgView.setBackgroundResource(R.drawable.img1);

我在可绘制文件夹中有图像img1。我想展示文件中的图像。

我该怎么做呢?


当前回答

你可以使用:

ImageView imgView = new ImageView(this);
InputStream is = getClass().getResourceAsStream("/drawable/" + fileName);
imgView.setImageDrawable(Drawable.createFromStream(is, ""));

其他回答

       public static Bitmap decodeFile(String path) {
    Bitmap b = null;
    File f = new File(path);
    // Decode image size
    BitmapFactory.Options o = new BitmapFactory.Options();
    o.inJustDecodeBounds = true;

    FileInputStream fis = null;
    try {
        fis = new FileInputStream(f);
        BitmapFactory.decodeStream(fis, null, o);
        fis.close();

        int IMAGE_MAX_SIZE = 1024; // maximum dimension limit
        int scale = 1;
        if (o.outHeight > IMAGE_MAX_SIZE || o.outWidth > IMAGE_MAX_SIZE) {
            scale = (int) Math.pow(2, (int) Math.round(Math.log(IMAGE_MAX_SIZE / (double) Math.max(o.outHeight, o.outWidth)) / Math.log(0.5)));
        }

        // Decode with inSampleSize
        BitmapFactory.Options o2 = new BitmapFactory.Options();
        o2.inSampleSize = scale;

        fis = new FileInputStream(f);
        b = BitmapFactory.decodeStream(fis, null, o2);
        fis.close();

    } catch (Exception e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

    return b;
}

public static Bitmap showBitmapFromFile(String file_path)
{
    try {
        File imgFile = new  File(file_path);
        if(imgFile.exists()){

            Bitmap pic_Bitmap = decodeFile(file_path);
            return pic_Bitmap;

        }
    } catch (Exception e) {
        MyLog.e("Exception showBitmapFromFile");
        return null;
    }
    return null;
}   

如果你在列表视图中使用图像加载,那么使用Aquery概念。

https://github.com/AshishPsaini/AqueryExample

     AQuery  aq= new AQuery((Activity) activity, convertView);
            //load image from file, down sample to target width of 250 pixels .gi 
    File file=new File("//pic/path/here/aaaa.jpg");
    if(aq!=null)
    aq.id(holder.pic_imageview).image(file, 250);

我想你可以用这个

Bitmap bmImg = BitmapFactory.decodeFile("path of your img1");
imageView.setImageBitmap(bmImg);
mageView.setImageResource(R.id.img);
String path = Environment.getExternalStorageDirectory()+ "/Images/test.jpg";

File imgFile = new File(path);
if(imgFile.exists())
{
   Bitmap myBitmap = BitmapFactory.decodeFile(imgFile.getAbsolutePath());
   ImageView imageView=(ImageView)findViewById(R.id.imageView);
  imageView.setImageBitmap(myBitmap);
}

您可以使用它来访问特定的文件夹并获得特定的图像

 public void Retrieve(String path, String Name)
   {
    File imageFile = new File(path+Name);

    if(imageFile.exists()){

        Bitmap myBitmap = BitmapFactory.decodeFile(path+Name);
        myImage = (ImageView) findViewById(R.id.savedImage);
        myImage.setImageBitmap(myBitmap);
        Toast.makeText(SaveImage.this, myBitmap.toString(), Toast.LENGTH_LONG).show();

    }
}

然后你就可以过来了

Retrieve(Environment.getExternalStorageDirectory().toString()+"/Aqeel/Images/","Image2.PNG");
Toast.makeText(SaveImage.this, "Saved", Toast.LENGTH_LONG).show();