每个枚举都有一个name()和valueOf(String)方法。前者返回enum的字符串名称，后者给出名称为该字符串的enum值。这就是你要找的吗?

String name = Modes.mode1.name();
Modes mode = Modes.valueOf(name);

Enum本身也有一个静态valueOf(Class, String)，所以你也可以使用:

Modes mode = Enum.valueOf(Modes.class, name);

我的解决方案!

import java.util.HashMap;
import java.util.Map;

public enum MapEnumSample {
    Mustang("One of the fastest cars in the world!"), 
    Mercedes("One of the most beautiful cars in the world!"), 
    Ferrari("Ferrari or Mercedes, which one is the best?");

    private final String description;
    private static Map<String, String> enumMap;

    private MapEnumSample(String description) {
        this.description = description;
    }

    public String getEnumValue() {
        return description;
    }

    public static String getEnumKey(String name) {
        if (enumMap == null) {
            initializeMap();
        }
        return enumMap.get(name);
    }

    private static Map<String, String> initializeMap() {
        enumMap = new HashMap<String, String>();
        for (MapEnumSample access : MapEnumSample.values()) {
            enumMap.put(access.getEnumValue(), access.toString());
        }
        return enumMap;
    }

    public static void main(String[] args) {

        // getting value from Description
        System.out.println(MapEnumSample.getEnumKey("One of the fastest cars in the world!"));

        // getting value from Constant
        System.out.println(MapEnumSample.Mustang.getEnumValue());

        System.out.println(MapEnumSample.getEnumKey("One of the most beautiful cars in the world!"));
        System.out.println(MapEnumSample.Mercedes.getEnumValue());

        // doesnt exist in Enum
        System.out.println("Mustang or Mercedes, which one is the best?");
        System.out.println(MapEnumSample.getEnumKey("Mustang or Mercedes, which one is the best?") == null ? "I don't know!" : "I believe that "
                + MapEnumSample.getEnumKey("Ferrari or Mustang, which one is the best?") + " is the best!.");

        // exists in Enum
        System.out.println("Ferrari or Mercedes, wich one is the best?");
        System.out.println(MapEnumSample.getEnumKey("Ferrari or Mercedes, which one is the best?") == null ? "I don't know!" : "I believe that "
                + MapEnumSample.getEnumKey("Ferrari or Mercedes, which one is the best?") + " is the best!");

    }
}

public enum Environment
{
    PROD("https://prod.domain.com:1088/"),
    SIT("https://sit.domain.com:2019/"),
    CIT("https://cit.domain.com:8080/"),
    DEV("https://dev.domain.com:21323/");

    private String url;

    Environment(String envUrl) {
        this.url = envUrl;
    }

    public String getUrl() {
        return url;
    }
}

String prodUrl = Environment.PROD.getUrl();

它将打印:

https://prod.domain.com:1088/

这种枚举字符串常量的设计在大多数情况下都有效。

我发现这个更容易防止输入错误:

public enum Modes {
    some-really-long-string,
    mode1,
    mode2,
    mode3;

    String str;

    Modes(){
        this.str = super.name();
    }

    @Override
    @NonNull
    public String toString() {
        return str;
    }

然而，当你需要在log/println上使用String时，或者当java自动编译toString()方法时，这可能会起作用，但在这样的代码行中->

// sample method that require (string,value)
intent.putExtra(Modes.mode1 ,shareElement.getMode()); // java error
// first argument enum does not return value

相反，如上所述，你仍然需要扩展枚举，并在这些情况下使用.name():

intent.putExtra(Modes.mode1.name() ,shareElement.getMode()); 

经过多次尝试，我终于想出了这个解决办法

public static enum Operation {

    Addition, Subtraction, Multiplication, Division,;

    public String getUserFriendlyString() {
        if (this==Addition) {
            return " + ";
        } else if (this==Subtraction) {
            return " - ";
        } else if (this==Multiplication) {
            return " * ";
        } else if (this==Division) {
            return " / ";
        }
        return "undefined";
       }
}

你可以试试这个:

public enum Modes {
    some-really-long-string,
    mode1,
    mode2,
    mode3;

    public String toString(){
        switch(this) {
            case some-really-long-string:
                return "some-really-long-string";
            case mode2:
                return "mode2";
            default: return "undefined";
        }
    }

}