我可以使用MomentJs得到两个日期之间的差异,如下所示:

moment(end.diff(startTime)).format("m[m] s[s]")

但是,我还想在适用的情况下显示小时(仅当>= 60分钟已经过时)。

然而,当我试图检索持续时间小时使用以下:

var duration = moment.duration(end.diff(startTime));
var hours = duration.hours();

它返回当前的小时数,而不是两个日期之间的小时数。

我如何得到两个时刻之间的小时差?


当前回答

也许对某人有用

          var ax = moment(
            new Date().toLocaleString(), // today/now is 09/12/2021 10:00:00
            "DD/MM/YYYY HH:mm:ss"
            ).diff(
              moment(
                "12/11/2022 13:43:11", // some time in future or past
                "DD/MM/YYYY HH:mm:ss"
              )
          );
          console.log('if today is in the future of the compared date then 
          result should be negative ==>', ax);
          // ax bigger than 0 zero means date in past. ms less than zero is in future

其他回答

下面的代码块展示了如何使用MomentJS计算两个日期之间的天数差异。

var now = moment(new Date()); //todays date
var end = moment("2015-12-1"); // another date
var duration = moment.duration(now.diff(end));
var days = duration.asDays();
console.log(days)
var __startTime = moment("2016-06-06T09:00").format();
var __endTime = moment("2016-06-06T21:00").format();

var __duration = moment.duration(moment(__endTime).diff(__startTime));
var __hours = __duration.asHours();
console.log(__hours);
            var timecompare = {
            tstr: "",
            get: function (current_time, startTime, endTime) {
                this.tstr = "";
                var s = current_time.split(":"), t1 = tm1.split(":"), t2 = tm2.split(":"), t1s = Number(t1[0]), t1d = Number(t1[1]), t2s = Number(t2[0]), t2d = Number(t2[1]);

                if (t1s < t2s) {
                    this.t(t1s, t2s);
                }

                if (t1s > t2s) {
                    this.t(t1s, 23);
                    this.t(0, t2s);
                }

                var saat_dk = Number(s[1]);

                if (s[0] == tm1.substring(0, 2) && saat_dk >= t1d)
                    return true;
                if (s[0] == tm2.substring(0, 2) && saat_dk <= t2d)
                    return true;
                if (this.tstr.indexOf(s[0]) != 1 && this.tstr.indexOf(s[0]) != -1 && !(this.tstr.indexOf(s[0]) == this.tstr.length - 2))
                    return true;

                return false;

            },
            t: function (ii, brk) {
                for (var i = 0; i <= 23; i++) {
                    if (i < ii)
                        continue;
                    var s = (i < 10) ? "0" + i : i + "";
                    this.tstr += "," + s;
                    if (brk == i)
                        break;
                }
            }};

如果你想要两个日期之间的总分钟数,下面的代码将帮助你充分开始日期:2018-05-04 02:08:05,结束日期:2018-05-14 09:04:07…

function countDaysAndTimes(startDate,endDate){
return new Promise(function (resolve, reject) {
var dayObj = new Object;
var finalArray = new Array;

var datetime1 = moment(startDate);
var datetime2 = moment(endDate);
if(datetime1.format('D') != datetime2.format('D') || datetime1.format('M') != datetime2.format('M') ||  datetime1.format('YYYY') != datetime2.format('YYYY')){
  var onlyDate1 = startDate.split(" ");
  var onlyDate2 = endDate.split(" ");
  var totalDays = moment(onlyDate2[0]).diff(moment(onlyDate1[0]), 'days')

  // First Day Entry
  dayObj.startDate = startDate;
  dayObj.endDate = moment(onlyDate1[0]).add(1, 'day').format('YYYY-MM-DD')+" 00:00:00";
  dayObj.minutes = moment(dayObj.endDate).diff(moment(dayObj.startDate), 'minutes');
  finalArray.push(dayObj);

  // Between Days Entry
  var i = 1;
  if(totalDays > 1){
    for(i=1; i<totalDays; i++){
      var dayObj1 = new Object;
      dayObj1.startDate = moment(onlyDate1[0]).add(i, 'day').format('YYYY-MM-DD')+" 00:00:00";
      dayObj1.endDate = moment(onlyDate1[0]).add(i+1, 'day').format('YYYY-MM-DD')+" 00:00:00";
      dayObj1.minutes = moment(dayObj1.endDate).diff(moment(dayObj1.startDate), 'minutes');
      finalArray.push(dayObj1);
    }
  }

  // Last Day Entry
  var dayObj2 = new Object;
  dayObj2.startDate = moment(onlyDate1[0]).add(i, 'day').format('YYYY-MM-DD')+" 00:00:00";
  dayObj2.endDate = endDate ;
  dayObj2.minutes = moment(dayObj2.endDate).diff(moment(dayObj2.startDate), 'minutes');
  finalArray.push(dayObj2);

}
else{
  dayObj.startDate = startDate;
  dayObj.endDate = endDate;
  dayObj.minutes = datetime2.diff(datetime1, 'minutes');
  finalArray.push(dayObj);
}
console.log(JSON.stringify(finalArray));
// console.table(finalArray);
resolve(finalArray);
});
}

输出

 [
  {
  "startDate":"2018-05-04 02:08:05",
  "endDate":"2018-05-05 00:00:00",
  "minutes":1311
  },
  {
  "startDate":"2018-05-05 00:00:00",
  "endDate":"2018-05-06 00:00:00",
  "minutes":1440
  },
  {
  "startDate":"2018-05-06 00:00:00",
  "endDate":"2018-05-07 00:00:00",
  "minutes":1440
  },
  {
  "startDate":"2018-05-07 00:00:00",
  "endDate":"2018-05-08 00:00:00",
  "minutes":1440
  },
  {
  "startDate":"2018-05-08 00:00:00",
  "endDate":"2018-05-09 00:00:00",
  "minutes":1440
  },
  {
  "startDate":"2018-05-09 00:00:00",
  "endDate":"2018-05-10 00:00:00",
  "minutes":1440
  },
  {
  "startDate":"2018-05-10 00:00:00",
  "endDate":"2018-05-11 00:00:00",
  "minutes":1440
  },
  {
  "startDate":"2018-05-11 00:00:00",
  "endDate":"2018-05-12 00:00:00",
  "minutes":1440
  },
  {
  "startDate":"2018-05-12 00:00:00",
  "endDate":"2018-05-13 00:00:00",
  "minutes":1440
  },
  {
  "startDate":"2018-05-13 00:00:00",
  "endDate":"2018-05-14 00:00:00",
  "minutes":1440
  },
  {
  "startDate":"2018-05-14 00:00:00",
  "endDate":"2018-05-14 09:04:07",
  "minutes":544
  }
 ]

我知道这很老了,但这里有一个简单的解决方案:

const hourDiff = start.diff(end, "hours");

开始和结束都是力矩对象。

享受吧!