我可以使用MomentJs得到两个日期之间的差异，如下所示:
moment(end.diff(startTime)).format("m[m] s[s]")
但是，我还想在适用的情况下显示小时(仅当>= 60分钟已经过时)。
然而，当我试图检索持续时间小时使用以下:
var duration = moment.duration(end.diff(startTime));
var hours = duration.hours();
它返回当前的小时数，而不是两个日期之间的小时数。
我如何得到两个时刻之间的小时差?
当前回答
你所需要做的就是把hours作为第二个参数传递给moments diff函数。
var a = moment([21,30,00], "HH:mm:ss")
var b = moment([09,30,00], "HH:mm:ss")
a.diff(b, 'hours') // 12
文档:https://momentjs.com/docs/ # / /显示/不同
例子:
const dateFormat = "YYYY-MM-DD HH:mm:ss"; // Get your start and end date/times const rightNow = moment().format(dateFormat); const thisTimeYesterday = moment().subtract(1, 'days').format(dateFormat); // pass in hours as the second parameter to the diff function const differenceInHours = moment(rightNow).diff(thisTimeYesterday, 'hours'); console.log(`${differenceInHours} hours have passed since this time yesterday`); <script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.20.1/moment.min.js"> </script>
其他回答
下面的代码块展示了如何使用MomentJS计算两个日期之间的天数差异。
var now = moment(new Date()); //todays date
var end = moment("2015-12-1"); // another date
var duration = moment.duration(now.diff(end));
var days = duration.asDays();
console.log(days)
var timecompare = {
tstr: "",
get: function (current_time, startTime, endTime) {
this.tstr = "";
var s = current_time.split(":"), t1 = tm1.split(":"), t2 = tm2.split(":"), t1s = Number(t1[0]), t1d = Number(t1[1]), t2s = Number(t2[0]), t2d = Number(t2[1]);
if (t1s < t2s) {
this.t(t1s, t2s);
}
if (t1s > t2s) {
this.t(t1s, 23);
this.t(0, t2s);
}
var saat_dk = Number(s[1]);
if (s[0] == tm1.substring(0, 2) && saat_dk >= t1d)
return true;
if (s[0] == tm2.substring(0, 2) && saat_dk <= t2d)
return true;
if (this.tstr.indexOf(s[0]) != 1 && this.tstr.indexOf(s[0]) != -1 && !(this.tstr.indexOf(s[0]) == this.tstr.length - 2))
return true;
return false;
},
t: function (ii, brk) {
for (var i = 0; i <= 23; i++) {
if (i < ii)
continue;
var s = (i < 10) ? "0" + i : i + "";
this.tstr += "," + s;
if (brk == i)
break;
}
}};
var __startTime = moment("2016-06-06T09:00").format();
var __endTime = moment("2016-06-06T21:00").format();
var __duration = moment.duration(moment(__endTime).diff(__startTime));
var __hours = __duration.asHours();
console.log(__hours);
或者你可以简单地做:
var a = moment('2016-06-06T21:03:55');//now
var b = moment('2016-05-06T20:03:55');
console.log(a.diff(b, 'minutes')) // 44700
console.log(a.diff(b, 'hours')) // 745
console.log(a.diff(b, 'days')) // 31
console.log(a.diff(b, 'weeks')) // 4
文档:
我知道这个问题已经回答了，但如果你想要递归的更通用的东西，不依赖于moment fromNow，你可以使用我创建的这个函数。当然，您可以根据需要更改其逻辑，使其支持年和秒。
var createdAt = moment('2019-05-13T14:23:00.607Z');
var expiresAt = moment('2019-05-14T14:23:00.563Z');
// You can also add years in the beginning of the array or seconds in its end
const UNITS = ["months", "weeks", "days", "hours", "minutes"]
function getValidFor (createdAt, expiresAt, unit = 'months') {
const validForUnit = expiresAt.diff(createdAt, unit);
// you could adjust the if to your needs
if (validForUnit > 1 || unit === "minutes") {
return [validForUnit, unit];
}
return getValidFor(createdAt, expiresAt, UNITS[UNITS.indexOf(unit) + 1]);
}
