我可以使用MomentJs得到两个日期之间的差异，如下所示:
moment(end.diff(startTime)).format("m[m] s[s]")
但是，我还想在适用的情况下显示小时(仅当>= 60分钟已经过时)。
然而，当我试图检索持续时间小时使用以下:
var duration = moment.duration(end.diff(startTime));
var hours = duration.hours();
它返回当前的小时数，而不是两个日期之间的小时数。
我如何得到两个时刻之间的小时差?
当前回答
如果你想要两个日期之间的总分钟数，下面的代码将帮助你充分开始日期:2018-05-04 02:08:05，结束日期:2018-05-14 09:04:07…
function countDaysAndTimes(startDate,endDate){
return new Promise(function (resolve, reject) {
var dayObj = new Object;
var finalArray = new Array;
var datetime1 = moment(startDate);
var datetime2 = moment(endDate);
if(datetime1.format('D') != datetime2.format('D') || datetime1.format('M') != datetime2.format('M') || datetime1.format('YYYY') != datetime2.format('YYYY')){
var onlyDate1 = startDate.split(" ");
var onlyDate2 = endDate.split(" ");
var totalDays = moment(onlyDate2[0]).diff(moment(onlyDate1[0]), 'days')
// First Day Entry
dayObj.startDate = startDate;
dayObj.endDate = moment(onlyDate1[0]).add(1, 'day').format('YYYY-MM-DD')+" 00:00:00";
dayObj.minutes = moment(dayObj.endDate).diff(moment(dayObj.startDate), 'minutes');
finalArray.push(dayObj);
// Between Days Entry
var i = 1;
if(totalDays > 1){
for(i=1; i<totalDays; i++){
var dayObj1 = new Object;
dayObj1.startDate = moment(onlyDate1[0]).add(i, 'day').format('YYYY-MM-DD')+" 00:00:00";
dayObj1.endDate = moment(onlyDate1[0]).add(i+1, 'day').format('YYYY-MM-DD')+" 00:00:00";
dayObj1.minutes = moment(dayObj1.endDate).diff(moment(dayObj1.startDate), 'minutes');
finalArray.push(dayObj1);
}
}
// Last Day Entry
var dayObj2 = new Object;
dayObj2.startDate = moment(onlyDate1[0]).add(i, 'day').format('YYYY-MM-DD')+" 00:00:00";
dayObj2.endDate = endDate ;
dayObj2.minutes = moment(dayObj2.endDate).diff(moment(dayObj2.startDate), 'minutes');
finalArray.push(dayObj2);
}
else{
dayObj.startDate = startDate;
dayObj.endDate = endDate;
dayObj.minutes = datetime2.diff(datetime1, 'minutes');
finalArray.push(dayObj);
}
console.log(JSON.stringify(finalArray));
// console.table(finalArray);
resolve(finalArray);
});
}
输出
[
{
"startDate":"2018-05-04 02:08:05",
"endDate":"2018-05-05 00:00:00",
"minutes":1311
},
{
"startDate":"2018-05-05 00:00:00",
"endDate":"2018-05-06 00:00:00",
"minutes":1440
},
{
"startDate":"2018-05-06 00:00:00",
"endDate":"2018-05-07 00:00:00",
"minutes":1440
},
{
"startDate":"2018-05-07 00:00:00",
"endDate":"2018-05-08 00:00:00",
"minutes":1440
},
{
"startDate":"2018-05-08 00:00:00",
"endDate":"2018-05-09 00:00:00",
"minutes":1440
},
{
"startDate":"2018-05-09 00:00:00",
"endDate":"2018-05-10 00:00:00",
"minutes":1440
},
{
"startDate":"2018-05-10 00:00:00",
"endDate":"2018-05-11 00:00:00",
"minutes":1440
},
{
"startDate":"2018-05-11 00:00:00",
"endDate":"2018-05-12 00:00:00",
"minutes":1440
},
{
"startDate":"2018-05-12 00:00:00",
"endDate":"2018-05-13 00:00:00",
"minutes":1440
},
{
"startDate":"2018-05-13 00:00:00",
"endDate":"2018-05-14 00:00:00",
"minutes":1440
},
{
"startDate":"2018-05-14 00:00:00",
"endDate":"2018-05-14 09:04:07",
"minutes":544
}
]
其他回答
就我而言，我想要的是小时和分钟:
var duration = moment.duration(end.diff(startTime));
var hours = duration.hours(); //hours instead of asHours
var minutes = duration.minutes(); //minutes instead of asMinutes
更多信息请参考官方文档。
有一个叫做fromNow()的很棒的moment方法，它会以人类可读的形式返回特定时间的时间，就像这样:
moment('2019-04-30T07:30:53.000Z').fromNow() // an hour ago || a day ago || 10 days ago
或者如果你想在两个特定的日期之间，你可以使用:
var a = moment([2007, 0, 28]);
var b = moment([2007, 0, 29]);
a.from(b); // "a day ago"
摘自文档:
都可以() 从()
var start=moment(1541243900000);
var end=moment(1541243942882);
var duration = moment.duration(end.diff(startTime));
var hours = duration.asHours();
如您所见，开始日期和结束日期需要是此方法工作的时刻对象。
来源:https://momentjs.com/docs/ / /显示/不同
let startDate = "2022-08-14"; let endDate = "2022-08-20"; let startDateMoment = moment(startDate.split('-'));// ["2022"， "08"， "14"] let endDateMoment = moment(endDate.split('-')); console.log('Difference: '， endDateMoment. log)diff (startDateMoment '时间'));/ / 6 < script src = " https://momentjs.com/downloads/moment.js " > < /脚本>
我知道这个问题已经回答了，但如果你想要递归的更通用的东西，不依赖于moment fromNow，你可以使用我创建的这个函数。当然，您可以根据需要更改其逻辑，使其支持年和秒。
var createdAt = moment('2019-05-13T14:23:00.607Z');
var expiresAt = moment('2019-05-14T14:23:00.563Z');
// You can also add years in the beginning of the array or seconds in its end
const UNITS = ["months", "weeks", "days", "hours", "minutes"]
function getValidFor (createdAt, expiresAt, unit = 'months') {
const validForUnit = expiresAt.diff(createdAt, unit);
// you could adjust the if to your needs
if (validForUnit > 1 || unit === "minutes") {
return [validForUnit, unit];
}
return getValidFor(createdAt, expiresAt, UNITS[UNITS.indexOf(unit) + 1]);
}
