我可以使用MomentJs得到两个日期之间的差异，如下所示:
moment(end.diff(startTime)).format("m[m] s[s]")
但是，我还想在适用的情况下显示小时(仅当>= 60分钟已经过时)。
然而，当我试图检索持续时间小时使用以下:
var duration = moment.duration(end.diff(startTime));
var hours = duration.hours();
它返回当前的小时数，而不是两个日期之间的小时数。
我如何得到两个时刻之间的小时差?
当前回答
我知道这很老了，但这里有一个简单的解决方案:
const hourDiff = start.diff(end, "hours");
开始和结束都是力矩对象。
享受吧!
其他回答
如果你想要两个日期之间的总分钟数，下面的代码将帮助你充分开始日期:2018-05-04 02:08:05，结束日期:2018-05-14 09:04:07…
function countDaysAndTimes(startDate,endDate){
return new Promise(function (resolve, reject) {
var dayObj = new Object;
var finalArray = new Array;
var datetime1 = moment(startDate);
var datetime2 = moment(endDate);
if(datetime1.format('D') != datetime2.format('D') || datetime1.format('M') != datetime2.format('M') || datetime1.format('YYYY') != datetime2.format('YYYY')){
var onlyDate1 = startDate.split(" ");
var onlyDate2 = endDate.split(" ");
var totalDays = moment(onlyDate2[0]).diff(moment(onlyDate1[0]), 'days')
// First Day Entry
dayObj.startDate = startDate;
dayObj.endDate = moment(onlyDate1[0]).add(1, 'day').format('YYYY-MM-DD')+" 00:00:00";
dayObj.minutes = moment(dayObj.endDate).diff(moment(dayObj.startDate), 'minutes');
finalArray.push(dayObj);
// Between Days Entry
var i = 1;
if(totalDays > 1){
for(i=1; i<totalDays; i++){
var dayObj1 = new Object;
dayObj1.startDate = moment(onlyDate1[0]).add(i, 'day').format('YYYY-MM-DD')+" 00:00:00";
dayObj1.endDate = moment(onlyDate1[0]).add(i+1, 'day').format('YYYY-MM-DD')+" 00:00:00";
dayObj1.minutes = moment(dayObj1.endDate).diff(moment(dayObj1.startDate), 'minutes');
finalArray.push(dayObj1);
}
}
// Last Day Entry
var dayObj2 = new Object;
dayObj2.startDate = moment(onlyDate1[0]).add(i, 'day').format('YYYY-MM-DD')+" 00:00:00";
dayObj2.endDate = endDate ;
dayObj2.minutes = moment(dayObj2.endDate).diff(moment(dayObj2.startDate), 'minutes');
finalArray.push(dayObj2);
}
else{
dayObj.startDate = startDate;
dayObj.endDate = endDate;
dayObj.minutes = datetime2.diff(datetime1, 'minutes');
finalArray.push(dayObj);
}
console.log(JSON.stringify(finalArray));
// console.table(finalArray);
resolve(finalArray);
});
}
输出
[
{
"startDate":"2018-05-04 02:08:05",
"endDate":"2018-05-05 00:00:00",
"minutes":1311
},
{
"startDate":"2018-05-05 00:00:00",
"endDate":"2018-05-06 00:00:00",
"minutes":1440
},
{
"startDate":"2018-05-06 00:00:00",
"endDate":"2018-05-07 00:00:00",
"minutes":1440
},
{
"startDate":"2018-05-07 00:00:00",
"endDate":"2018-05-08 00:00:00",
"minutes":1440
},
{
"startDate":"2018-05-08 00:00:00",
"endDate":"2018-05-09 00:00:00",
"minutes":1440
},
{
"startDate":"2018-05-09 00:00:00",
"endDate":"2018-05-10 00:00:00",
"minutes":1440
},
{
"startDate":"2018-05-10 00:00:00",
"endDate":"2018-05-11 00:00:00",
"minutes":1440
},
{
"startDate":"2018-05-11 00:00:00",
"endDate":"2018-05-12 00:00:00",
"minutes":1440
},
{
"startDate":"2018-05-12 00:00:00",
"endDate":"2018-05-13 00:00:00",
"minutes":1440
},
{
"startDate":"2018-05-13 00:00:00",
"endDate":"2018-05-14 00:00:00",
"minutes":1440
},
{
"startDate":"2018-05-14 00:00:00",
"endDate":"2018-05-14 09:04:07",
"minutes":544
}
]
也许对某人有用
var ax = moment(
new Date().toLocaleString(), // today/now is 09/12/2021 10:00:00
"DD/MM/YYYY HH:mm:ss"
).diff(
moment(
"12/11/2022 13:43:11", // some time in future or past
"DD/MM/YYYY HH:mm:ss"
)
);
console.log('if today is in the future of the compared date then
result should be negative ==>', ax);
// ax bigger than 0 zero means date in past. ms less than zero is in future
你很接近了。你只需要使用duration.asHours()方法(请参阅文档)。
var duration = moment.duration(end.diff(startTime));
var hours = duration.asHours();
根据Moment JS的新Deprecation警告
你需要传递开始和结束日期格式的格式以及值，例如:
let trackStartTime = "2020-12-29 09:59:19.07 +05:30";
let trackEndTime = "2020-12-29 11:04:19.07 +05:30" || moment().format("YYYY-MM-DD HH:mm:ss.SS Z");
let overallActivity = moment.duration(moment(trackEndTime, 'YYYY-MM-DD HH:mm:ss.SS Z').diff(moment(trackStartTime, 'YYYY-MM-DD HH:mm:ss.SS Z'))).asHours();
下面的代码块展示了如何使用MomentJS计算两个日期之间的天数差异。
var now = moment(new Date()); //todays date
var end = moment("2015-12-1"); // another date
var duration = moment.duration(now.diff(end));
var days = duration.asDays();
console.log(days)
