Try:

maxInt = -1 >>> 1

在Firefox 3.6中是2^31 - 1。

要用于位操作的任何值必须在0x80000000(-2147483648或-2^31)和0x7fffffff(2147483647或2^31 - 1)之间。

控制台会告诉您0x80000000等于+2147483648，但是0x80000000 & 0x80000000等于-2147483648。

我用一个公式做了一个简单的测试，X-(X+1)=-1，我在Safari、Opera和Firefox(在OS X上测试)上可以得到的X的最大值是9e15。下面是我用于测试的代码:

javascript: alert(9e15-(9e15+1));

在JavaScript中，数字的表示是2^53 - 1。

然而，按位操作是在32位(4个字节)上计算的，这意味着如果你超过32位移位，你将开始丢失位。

让我们来看看源头

描述

The MAX_SAFE_INTEGER constant has a value of 9007199254740991 (9,007,199,254,740,991 or ~9 quadrillion). The reasoning behind that number is that JavaScript uses double-precision floating-point format numbers as specified in IEEE 754 and can only safely represent numbers between -(2^53 - 1) and 2^53 - 1. Safe in this context refers to the ability to represent integers exactly and to correctly compare them. For example, Number.MAX_SAFE_INTEGER + 1 === Number.MAX_SAFE_INTEGER + 2 will evaluate to true, which is mathematically incorrect. See Number.isSafeInteger() for more information. Because MAX_SAFE_INTEGER is a static property of Number, you always use it as Number.MAX_SAFE_INTEGER, rather than as a property of a Number object you created.

浏览器兼容性

的wrotes:

任何你想用于位操作的东西都必须在 0x80000000(-2147483648或-2^31)和0x7fffffff(2147483647或2^31 - 1)。 控制台会告诉您0x80000000等于+2147483648，但是 0x80000000 & 0x80000000 = -2147483648

十六进制小数是无符号的正数值，因此0x80000000 = 2147483648 -这在数学上是正确的。如果你想让它成为一个带符号的值，你必须右移:0x80000000 >> 0 = -2147483648。你也可以写成1 << 31。