只从“这里”列出目录的一行程序。

文件计数。

for i in `ls -d */`; do g=`find ./$i -type f -print| wc -l`; echo "Directory $i contains $g files."; done

如果不需要列出隐藏目录，我提供:

ls -l | grep "^d" | awk -F" " '{print $9}'

如果需要列出隐藏目录，请使用:

ls -Al | grep "^d" | awk -F" " '{print $9}'

Or

find -maxdepth 1 -type d | awk -F"./" '{print $2}'

我用以下方法部分解决了这个问题:

cd "/path/to/pricipal/folder"

for i in $(ls -d .*/); do sudo ln -s "$PWD"/${i%%/} /home/inukaze/${i%%/}; done

    ln: «/home/inukaze/./.»: can't overwrite a directory
    ln: «/home/inukaze/../..»: can't overwrite a directory
    ln: accesing to «/home/inukaze/.config»: too much symbolics links levels
    ln: accesing to «/home/inukaze/.disruptive»: too much symbolics links levels
    ln: accesing to «/home/inukaze/innovations»: too much symbolics links levels
    ln: accesing to «/home/inukaze/sarl»: too much symbolics links levels
    ln: accesing to «/home/inukaze/.e_old»: too much symbolics links levels
    ln: accesing to «/home/inukaze/.gnome2_private»: too much symbolics links levels
    ln: accesing to «/home/inukaze/.gvfs»: too much symbolics links levels
    ln: accesing to «/home/inukaze/.kde»: too much symbolics links levels
    ln: accesing to «/home/inukaze/.local»: too much symbolics links levels
    ln: accesing to «/home/inukaze/.xVideoServiceThief»: too much symbolics links levels

好吧，这对我来说是主要的部分:)

试试这个。它适用于所有Linux发行版。

ls -ltr | grep drw

仅列出目录:

ls -l | grep ^d

只列出文件:

ls -l | grep -v ^d 

或者你也可以这样做:

ls -ld */

使用Test -d测试项目是否为目录:

for i in $(ls); do test -d $i && echo $i ; done