使用Perl:

ls | perl -nle 'print if -d;'

我只是把它添加到我的.bashrc文件中(如果你只需要/想要一个会话，你也可以在命令行上输入它):

alias lsd='ls -ld */'

然后lsd会产生想要的结果。

我用以下方法部分解决了这个问题:

cd "/path/to/pricipal/folder"

for i in $(ls -d .*/); do sudo ln -s "$PWD"/${i%%/} /home/inukaze/${i%%/}; done

    ln: «/home/inukaze/./.»: can't overwrite a directory
    ln: «/home/inukaze/../..»: can't overwrite a directory
    ln: accesing to «/home/inukaze/.config»: too much symbolics links levels
    ln: accesing to «/home/inukaze/.disruptive»: too much symbolics links levels
    ln: accesing to «/home/inukaze/innovations»: too much symbolics links levels
    ln: accesing to «/home/inukaze/sarl»: too much symbolics links levels
    ln: accesing to «/home/inukaze/.e_old»: too much symbolics links levels
    ln: accesing to «/home/inukaze/.gnome2_private»: too much symbolics links levels
    ln: accesing to «/home/inukaze/.gvfs»: too much symbolics links levels
    ln: accesing to «/home/inukaze/.kde»: too much symbolics links levels
    ln: accesing to «/home/inukaze/.local»: too much symbolics links levels
    ln: accesing to «/home/inukaze/.xVideoServiceThief»: too much symbolics links levels

好吧，这对我来说是主要的部分:)

如果你有空间在你的文件夹名称$9打印不工作尝试下面的命令

ls -l yourfolder/alldata/ | grep '^d' | awk '{print $9" " $10}'

输出

ls -l yourfolder/alldata/ | grep '^d' | awk '{print $9" " $10}'
testing_Data 
Folder 1

如果不需要列出隐藏目录，我提供:

ls -l | grep "^d" | awk -F" " '{print $9}'

如果需要列出隐藏目录，请使用:

ls -Al | grep "^d" | awk -F" " '{print $9}'

Or

find -maxdepth 1 -type d | awk -F"./" '{print $2}'

对于所有没有子文件夹的文件夹:

find /home/alice/Documents -maxdepth 1 -type d

对于所有带子文件夹的文件夹:

find /home/alice/Documents -type d