一个有效的解决方案是通过indexChunk将解决方案与slice和push连接起来，解决方案被分割成块:

function splitChunks(sourceArray, chunkSize) { if(chunkSize <= 0) throw "chunkSize must be greater than 0"; let result = []; for (var i = 0; i < sourceArray.length; i += chunkSize) { result[i / chunkSize] = sourceArray.slice(i, i + chunkSize); } return result; } let ar1 = [ 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20 ]; console.log("Split in chunks with 4 size", splitChunks(ar1, 4)); console.log("Split in chunks with 7 size", splitChunks(ar1, 7));

我推荐使用lodash。分块是其中一个有用的功能。 产品说明:

npm i --save lodash

在你的项目中包括:

import * as _ from 'lodash';

用法:

const arrayOfElements = ["Element 1","Element 2","Element 3", "Element 4", "Element 5","Element 6","Element 7","Element 8","Element 9","Element 10","Element 11","Element 12"]
const chunkedElements = _.chunk(arrayOfElements, 10)

你可以在这里找到我的样本: https://playcode.io/659171/

老问题:新答案!事实上，我一直在想这个问题的答案，并让一个朋友改进了它!就是这样:

Array.prototype.chunk = function ( n ) {
    if ( !this.length ) {
        return [];
    }
    return [ this.slice( 0, n ) ].concat( this.slice(n).chunk(n) );
};

[1,2,3,4,5,6,7,8,9,0].chunk(3);
> [[1,2,3],[4,5,6],[7,8,9],[0]]

对于功能性的解决方案，使用Ramda:

其中，popularProducts是输入数组，5是数据块大小

导入splitEvery from 'ramda/src/splitEvery' popularProducts splitEvery(5)。Map ((chunk, i) => { //用chunk做一些事情 })

嗨，试试这个——

 function split(arr, howMany) {
        var newArr = []; start = 0; end = howMany;
        for(var i=1; i<= Math.ceil(arr.length / howMany); i++) {
            newArr.push(arr.slice(start, end));
            start = start + howMany;
            end = end + howMany
        }
        console.log(newArr)
    }
    split([1,2,3,4,55,6,7,8,8,9],3)

in coffeescript:

b = (a.splice(0, len) while a.length)

demo 
a = [1, 2, 3, 4, 5, 6, 7]

b = (a.splice(0, 2) while a.length)
[ [ 1, 2 ],
  [ 3, 4 ],
  [ 5, 6 ],
  [ 7 ] ]