如果你安装了phpMyAdmin，使用它的“搜索”功能。

选择您的数据库 确保你有一个DB选择(即不是一个表，否则你会得到一个完全不同的搜索对话框) 点击“搜索”标签 选择您想要的搜索词 选择要搜索的表

我在250个表/10GB的数据库上使用过这个功能(在一个快速的服务器上)，响应时间非常惊人。

您可以查看information_schema模式。它包含所有表和表中所有字段的列表。然后，您可以使用从该表中获得的信息运行查询。

涉及的表包括SCHEMATA、tables和COLUMNS。有一些外键，这样您就可以在模式中准确地构建表的创建方式。

这个解决方案 a)只有MySQL，不需要其他语言，并且 b)返回SQL结果，准备处理!

#Search multiple database tables and/or columns
#Version 0.1 - JK 2014-01
#USAGE: 1. set the search term @search, 2. set the scope by adapting the WHERE clause of the `information_schema`.`columns` query
#NOTE: This is a usage example and might be advanced by setting the scope through a variable, putting it all in a function, and so on...

#define the search term here (using rules for the LIKE command, e.g % as a wildcard)
SET @search = '%needle%';

#settings
SET SESSION group_concat_max_len := @@max_allowed_packet;

#ini variable
SET @sql = NULL;

#query for prepared statement
SELECT
    GROUP_CONCAT("SELECT '",`TABLE_NAME`,"' AS `table`, '",`COLUMN_NAME`,"' AS `column`, `",`COLUMN_NAME`,"` AS `value` FROM `",TABLE_NAME,"` WHERE `",COLUMN_NAME,"` LIKE '",@search,"'" SEPARATOR "\nUNION\n") AS col
INTO @sql
FROM `information_schema`.`columns`
WHERE TABLE_NAME IN
(
    SELECT TABLE_NAME FROM `information_schema`.`columns`
    WHERE
        TABLE_SCHEMA IN ("my_database")
        && TABLE_NAME IN ("my_table1", "my_table2") || TABLE_NAME LIKE "my_prefix_%"
);

#prepare and execute the statement
PREPARE stmt FROM @sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;

有一个很好的图书馆可以阅读所有表格，ridona

$database = new ridona\Database('mysql:dbname=database_name;host=127.0.0.1', 'db_user','db_pass');

foreach ($database->tables()->by_entire() as $row) {

....do

}

使用实例在CLI下搜索数据库所有表中的字符串。

mysqldump -u UserName --no-create-info --extended-insert=FALSE DBName -p | grep -i "searchingString"

Or,

mysqldump -u UserName --no-create-info --extended-insert=FALSE DBName -p | grep -i "searchingString" > searchingString.sql

我修改了一点Olivier的PHP答案:

print out the results in which the string was found omit tables without results also show output if column names match the search input show total number of results function searchAllDB($search){ global $mysqli; $out = ""; $total = 0; $sql = "SHOW TABLES"; $rs = $mysqli->query($sql); if($rs->num_rows > 0){ while($r = $rs->fetch_array()){ $table = $r[0]; $sql_search = "select * from ".$table." where "; $sql_search_fields = Array(); $sql2 = "SHOW COLUMNS FROM ".$table; $rs2 = $mysqli->query($sql2); if($rs2->num_rows > 0){ while($r2 = $rs2->fetch_array()){ $colum = $r2[0]; $sql_search_fields[] = $colum." like('%".$search."%')"; if(strpos($colum,$search)) { echo "FIELD NAME: ".$colum."\n"; } } $rs2->close(); } $sql_search .= implode(" OR ", $sql_search_fields); $rs3 = $mysqli->query($sql_search); if($rs3 && $rs3->num_rows > 0) { $out .= $table.": ".$rs3->num_rows."\n"; if($rs3->num_rows > 0){ $total += $rs3->num_rows; $out.= print_r($rs3->fetch_all(),1); $rs3->close(); } } } $out .= "\n\nTotal results:".$total; $rs->close(); } return $out; }