我想从一个MySQL数据库的所有表的所有字段搜索一个给定的字符串,可能使用语法为:
SELECT * FROM * WHERE * LIKE '%stuff%'
有可能做这样的事情吗?
我想从一个MySQL数据库的所有表的所有字段搜索一个给定的字符串,可能使用语法为:
SELECT * FROM * WHERE * LIKE '%stuff%'
有可能做这样的事情吗?
当前回答
如果你安装了phpMyAdmin,使用它的“搜索”功能。
选择您的数据库 确保你有一个DB选择(即不是一个表,否则你会得到一个完全不同的搜索对话框) 点击“搜索”标签 选择您想要的搜索词 选择要搜索的表
我在250个表/10GB的数据库上使用过这个功能(在一个快速的服务器上),响应时间非常惊人。
其他回答
即使下面的建议不应该被认为是最终的解决方案,你也可以通过这样做来实现目标:
SET SESSION group_concat_max_len = 1000000;
SET @search = 'Text_To_Search';
DROP table IF EXISTS table1;
CREATE TEMPORARY TABLE table1 AS
(SELECT
CONCAT('SELECT \'',TABLE_NAME,'\' as \'table_name\',\'',COLUMN_NAME,'\' as \'column_name\',CONVERT(count(*),char) as \'matches\' FROM `',
TABLE_NAME,'` where `',COLUMN_NAME,'` like \'%',@search,'%\' UNION ') as 'query'
FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_SCHEMA = 'db_name' limit 1000000);
set @query = (SELECT GROUP_CONCAT(t1.`query` SEPARATOR '') as 'final_query' from table1 t1 limit 1);
set @query = (SELECT SUBSTRING(@query, 1, length(@query) - 7));
PREPARE stmt FROM @query;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
请记住:
选项:group_concat_max_len和limit 1000000并不总是必需的,这将取决于您的服务器/IDE配置。以防我加进去。 执行此命令后,您将得到一个3列响应:[table_name], [column_name], [matches] 列'matches'是给定表/列中出现的次数。 这个查询非常快。
免责声明:它只对个人使用有用,换句话说,请不要在生产系统中使用它,因为考虑到搜索参数与其他字符串连接,它对SQL注入攻击很敏感。 如果你想创建一个prod. ready函数,那么你需要创建一个带有LOOP的存储过程。
这个解决方案 a)只有MySQL,不需要其他语言,并且 b)返回SQL结果,准备处理!
#Search multiple database tables and/or columns
#Version 0.1 - JK 2014-01
#USAGE: 1. set the search term @search, 2. set the scope by adapting the WHERE clause of the `information_schema`.`columns` query
#NOTE: This is a usage example and might be advanced by setting the scope through a variable, putting it all in a function, and so on...
#define the search term here (using rules for the LIKE command, e.g % as a wildcard)
SET @search = '%needle%';
#settings
SET SESSION group_concat_max_len := @@max_allowed_packet;
#ini variable
SET @sql = NULL;
#query for prepared statement
SELECT
GROUP_CONCAT("SELECT '",`TABLE_NAME`,"' AS `table`, '",`COLUMN_NAME`,"' AS `column`, `",`COLUMN_NAME`,"` AS `value` FROM `",TABLE_NAME,"` WHERE `",COLUMN_NAME,"` LIKE '",@search,"'" SEPARATOR "\nUNION\n") AS col
INTO @sql
FROM `information_schema`.`columns`
WHERE TABLE_NAME IN
(
SELECT TABLE_NAME FROM `information_schema`.`columns`
WHERE
TABLE_SCHEMA IN ("my_database")
&& TABLE_NAME IN ("my_table1", "my_table2") || TABLE_NAME LIKE "my_prefix_%"
);
#prepare and execute the statement
PREPARE stmt FROM @sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
这是检索所有列和表的最简单的查询
SELECT * FROM information_schema.`COLUMNS` C WHERE TABLE_SCHEMA = 'YOUR_DATABASE'
在phpMyAdmin中,可以通过搜索选项卡搜索所有表或名称中有特定字符串的表。
有良好的查询…\ ^ ^ /
这是我知道的最简单的方法。 在PHPMyAdmin中选择你的DB,然后转到“搜索”选项卡,写下你想要找到的内容以及你要搜索的位置。如果要从所有表中搜索单词,则选择所有表。然后“开始”,看看结果。
我也做了我自己的mysql爬虫来搜索一些wordpress配置,在界面和数据库中都无法找到它,数据库转储太沉重和不可读。我得说我现在不能没有它。
它的工作原理类似于@Olivier,但它管理外来的数据库/表名,并且是像小丑一样安全。
<?php
$database = 'database';
$criteria = '*iemblo'; // you can use * and ? as jokers
$dbh = new PDO("mysql:host=127.0.0.1;dbname={$database};charset=utf8", 'root', '');
$dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$tables = $dbh->query("SHOW TABLES");
while (($table = $tables->fetch(PDO::FETCH_NUM)) !== false)
{
$fields = $dbh->prepare("SELECT COLUMN_NAME FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_SCHEMA = ? AND TABLE_NAME = ?");
$fields->execute(array ($database, $table[0]));
$ors = array ();
while (($field = $fields->fetch(PDO::FETCH_NUM)) !== false)
{
$ors[] = str_replace("`", "``", $field[0]) . " LIKE REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(:search, '\\\\', '\\\\\\\\'), '%', '\\%'), '_', '\\_'), '*', '%'), '?', '_')";
}
$request = 'SELECT * FROM ';
$request .= str_replace("`", "``", $table[0]);
$request .= ' WHERE ';
$request .= implode(' OR ', $ors);
$rows = $dbh->prepare($request);
$rows->execute(array ('search' => $criteria));
$count = $rows->rowCount();
if ($count == 0)
{
continue;
}
$str = "Table '{$table[0]}' contains {$count} rows matching '{$criteria}'.";
echo str_repeat('-', strlen($str)), PHP_EOL;
echo $str, PHP_EOL;
echo str_repeat('-', strlen($str)), PHP_EOL;
$counter = 1;
while (($row = $rows->fetch(PDO::FETCH_ASSOC)) !== false)
{
$col = 0;
$title = "Row #{$counter}:";
echo $title;
foreach ($row as $column => $value)
{
echo
(($col++ > 0) ? str_repeat(' ', strlen($title) + 1) : ' '),
$column, ': ',
trim(preg_replace('!\s+!', ' ', str_replace(array ("\r", "\t", "\n"), array ("", "", " "), $value))),
PHP_EOL;
}
echo PHP_EOL;
$counter++;
}
}
运行这个脚本可以输出如下内容:
---------------------------------------------------
Table 'customers' contains 1 rows matching '*iemblo'.
---------------------------------------------------
Row #1: email_client: my@email.com
numero_client_compta: C05135
nom_client: Tiemblo
adresse_facturation_1: 151, My Street
adresse_facturation_2:
ville_facturation: Nantes
code_postal_facturation: 44300
pays_facturation: FR
numero_tva_client:
zone_geographique: UE
prenom_client: Alain
commentaires:
nom_societe:
email_facturation: my@email.com