邮差生成的代码文件上传附加的表单字段:

import http.client
import mimetypes
from codecs import encode

conn = http.client.HTTPSConnection("data.XXXX.com")
dataList = []
boundary = 'wL36Yn8afVp8Ag7AmP8qZ0SA4n1v9T'
dataList.append(encode('--' + boundary))
dataList.append(encode('Content-Disposition: form-data; name=batchSize;'))

dataList.append(encode('Content-Type: {}'.format('text/plain')))
dataList.append(encode(''))

dataList.append(encode("1"))
dataList.append(encode('--' + boundary))
dataList.append(encode('Content-Disposition: form-data; name=file; filename={0}'.format('FileName-1.json')))

fileType = mimetypes.guess_type('FileName-1.json')[0] or 'application/octet-stream'
dataList.append(encode('Content-Type: {}'.format(fileType)))
dataList.append(encode(''))

with open('FileName-1.json', 'rb') as f:
  dataList.append(f.read())
dataList.append(encode('--'+boundary+'--'))
dataList.append(encode(''))
body = b'\r\n'.join(dataList)
payload = body
headers = {
  'Cookie': 'XXXXXXXXXXX',
  'Content-type': 'multipart/form-data; boundary={}'.format(boundary)
}
conn.request("POST", "/fileupload/uri/XXXX", payload, headers)
res = conn.getresponse()
data = res.read()
print(data.decode("utf-8"))

发送multipart/form-data键和值

curl命令:

curl -X PUT http://127.0.0.1:8080/api/xxx ...
-H 'content-type: multipart/form-data; boundary=----xxx' \
-F taskStatus=1

python请求-更复杂的POST请求:

    updateTaskUrl = "http://127.0.0.1:8080/api/xxx"
    updateInfoDict = {
        "taskStatus": 1,
    }
    resp = requests.put(updateTaskUrl, data=updateInfoDict)

发送多部分/表单数据文件

curl命令:

curl -X POST http://127.0.0.1:8080/api/xxx ...
-H 'content-type: multipart/form-data; boundary=----xxx' \
-F file=@/Users/xxx.txt

POST一个多部分编码的文件:

    filePath = "/Users/xxx.txt"
    fileFp = open(filePath, 'rb')
    fileInfoDict = {
        "file": fileFp,
    }
    resp = requests.post(uploadResultUrl, files=fileInfoDict)

这是所有。

这是你需要上传一个大的单一文件作为多部分formdata的python片段。在服务器端运行NodeJs Multer中间件。

import requests
latest_file = 'path/to/file'
url = "http://httpbin.org/apiToUpload"
files = {'fieldName': open(latest_file, 'rb')}
r = requests.put(url, files=files)

对于服务器端，请检查multer文档:https://github.com/expressjs/multer 这里的字段single('fieldName')用于接受单个文件，如下所示:

var upload = multer().single('fieldName');

这是在多部分请求中发送文件的一种方法

import requests
headers = {"Authorization": "Bearer <token>"}
myfile = 'file.txt'
myfile2 = {'file': (myfile, open(myfile, 'rb'),'application/octet-stream')}
url = 'https://example.com/path'
r = requests.post(url, files=myfile2, headers=headers,verify=False)
print(r.content)

其他方法

import requests

url = "https://example.com/path"

payload={}
files=[
  ('file',('file',open('/path/to/file','rb'),'application/octet-stream'))
]
headers = {
  'Authorization': 'Bearer <token>'
}

response = requests.request("POST", url, headers=headers, data=payload, files=files)

print(response.text)

我都测试过了，两者都很好。

您需要使用网站HTML中上传文件的name属性。例子:

autocomplete="off" name="image">

你看到name="image">?你可以在上传文件的网站的HTML中找到它。您需要使用它来上传Multipart/form-data文件

脚本:

import requests

site = 'https://prnt.sc/upload.php' # the site where you upload the file
filename = 'image.jpg'  # name example

这里，在image的位置，用HTML添加上传文件的名称

up = {'image':(filename, open(filename, 'rb'), "multipart/form-data")}

如果上传需要点击按钮进行上传，可以这样使用:

data = {
     "Button" : "Submit",
}

然后启动请求

request = requests.post(site, files=up, data=data)

完成，文件上传成功

通过在POST请求中指定files参数，请求的Content-Type被自动设置为multipart/form-data(后面跟着用于分隔multipart负载中的每个主体部分的边界字符串)，无论您只发送文件，还是同时发送form-data和文件(因此，在这种情况下，不应该尝试手动设置Content-Type)。然而，如果只发送表单数据，则Content-Type将自动设置为application/x-www-form-urlencoded。

You can print out the Content-Type header of the request to verify the above using the example given below, which shows how to upload multiple files (or a single file) with (optionally) the same key (i.e., 'files' in the case below), as well as with optional form-data (i.e., data=data in the example below). The documentation on how to POST single and multiple files can be found here and here, respectively. In case you need to upload large files without reading them into memory, have a look at Streaming Uploads. For the server side—in case this is needed—please have a look at this answer, from which the code snippet below has been taken, and which uses the FastAPI web framework.

import requests

url = 'http://127.0.0.1:8000/submit'
files = [('files', open('a.txt', 'rb')), ('files', open('b.txt', 'rb'))]
#file = {'file': open('a.txt','rb')} # to send a single file
data ={"name": "foo", "point": 0.13, "is_accepted": False}
r = requests.post(url=url, data=data, files=files) 
print(r.json())
print(r.request.headers['content-type'])