如何在python中发送多部分/表单数据请求?怎么发文件,我懂,但是怎么用这种方法发表单数据就不懂了。
当前回答
这是在多部分请求中发送文件的一种方法
import requests
headers = {"Authorization": "Bearer <token>"}
myfile = 'file.txt'
myfile2 = {'file': (myfile, open(myfile, 'rb'),'application/octet-stream')}
url = 'https://example.com/path'
r = requests.post(url, files=myfile2, headers=headers,verify=False)
print(r.content)
其他方法
import requests
url = "https://example.com/path"
payload={}
files=[
('file',('file',open('/path/to/file','rb'),'application/octet-stream'))
]
headers = {
'Authorization': 'Bearer <token>'
}
response = requests.request("POST", url, headers=headers, data=payload, files=files)
print(response.text)
我都测试过了,两者都很好。
其他回答
下面是使用请求上传带有附加参数的单个文件的简单代码片段:
url = 'https://<file_upload_url>'
fp = '/Users/jainik/Desktop/data.csv'
files = {'file': open(fp, 'rb')}
payload = {'file_id': '1234'}
response = requests.put(url, files=files, data=payload, verify=False)
请注意,您不需要显式地指定任何内容类型。
注:想评论上述答案之一,但不能因为低声誉,所以起草了一个新的回应在这里。
发送multipart/form-data键和值
curl命令:
curl -X PUT http://127.0.0.1:8080/api/xxx ...
-H 'content-type: multipart/form-data; boundary=----xxx' \
-F taskStatus=1
python请求-更复杂的POST请求:
updateTaskUrl = "http://127.0.0.1:8080/api/xxx"
updateInfoDict = {
"taskStatus": 1,
}
resp = requests.put(updateTaskUrl, data=updateInfoDict)
发送多部分/表单数据文件
curl命令:
curl -X POST http://127.0.0.1:8080/api/xxx ...
-H 'content-type: multipart/form-data; boundary=----xxx' \
-F file=@/Users/xxx.txt
POST一个多部分编码的文件:
filePath = "/Users/xxx.txt"
fileFp = open(filePath, 'rb')
fileInfoDict = {
"file": fileFp,
}
resp = requests.post(uploadResultUrl, files=fileInfoDict)
这是所有。
我试图用python 3中的请求模块发送一个请求到URL_server。 这对我来说很管用:
# -*- coding: utf-8 *-*
import json, requests
URL_SERVER_TO_POST_DATA = "URL_to_send_POST_request"
HEADERS = {"Content-Type" : "multipart/form-data;"}
def getPointsCC_Function():
file_data = {
'var1': (None, "valueOfYourVariable_1"),
'var2': (None, "valueOfYourVariable_2")
}
try:
resElastic = requests.post(URL_GET_BALANCE, files=file_data)
res = resElastic.json()
except Exception as e:
print(e)
print (json.dumps(res, indent=4, sort_keys=True))
getPointsCC_Function()
地点:
URL_SERVER_TO_POST_DATA =我们要发送数据的服务器 报头=发送的报头 file_data =发送的参数
这是你需要上传一个大的单一文件作为多部分formdata的python片段。在服务器端运行NodeJs Multer中间件。
import requests
latest_file = 'path/to/file'
url = "http://httpbin.org/apiToUpload"
files = {'fieldName': open(latest_file, 'rb')}
r = requests.put(url, files=files)
对于服务器端,请检查multer文档:https://github.com/expressjs/multer 这里的字段single('fieldName')用于接受单个文件,如下所示:
var upload = multer().single('fieldName');
import json
import os
import requests
from requests_toolbelt import MultipartEncoder
AUTH_API_ENDPOINT = "http://localhost:3095/api/auth/login"
def file_upload(path_img, token ):
url = 'http://localhost:3095/api/shopping/product/image'
name_img = os.path.basename(path_img)
mp_encoder = MultipartEncoder(
fields={
'email': 'mcm9@gmail.com',
'source': 'tmall',
'productId': 'product_0001',
'image': (name_img, open(path_img, 'rb'), 'multipart/form-data')
#'spam': ('spam.txt', open('spam.txt', 'rb'), 'text/plain'),
}
)
head = {'Authorization': 'Bearer {}'.format(token),
'Content-Type': mp_encoder.content_type}
with requests.Session() as s:
result = s.post(url, data=mp_encoder, headers=head)
return result
def do_auth(username, password, url=AUTH_API_ENDPOINT):
data = {
"email": username,
"password": password
}
# sending post request and saving response as response object
r = requests.post(url=url, data=data)
# extracting response text
response_text = r.text
d = json.loads(response_text)
# print(d)
return d
if __name__ == '__main__':
result = do_auth('mcm4@gmail.com','123456')
token = result.get('data').get('payload').get('token')
print(token)
result = file_upload('/home/mcm/Pictures/1234.png',token)
print(result.json())