如何从SQL Server表对象生成类?
我说的不是使用ORM。我只需要创建实体(简单类)。喜欢的东西:
public class Person
{
public string Name { get;set; }
public string Phone { get;set; }
}
给定一个表，比如:
+----+-------+----------------+
| ID | Name | Phone |
+----+-------+----------------+
| 1 | Alice | (555) 555-5550 |
| 2 | Bob | (555) 555-5551 |
| 3 | Cathy | (555) 555-5552 |
+----+-------+----------------+
当前回答
设置@TableName为你的表名。
declare @TableName sysname = 'TableName'
declare @Result varchar(max) = 'public class ' + @TableName + '
{'
select @Result = @Result + '
public ' + ColumnType + NullableSign + ' ' + ColumnName + ' { get; set; }
'
from
(
select
replace(col.name, ' ', '_') ColumnName,
column_id ColumnId,
case typ.name
when 'bigint' then 'long'
when 'binary' then 'byte[]'
when 'bit' then 'bool'
when 'char' then 'string'
when 'date' then 'DateTime'
when 'datetime' then 'DateTime'
when 'datetime2' then 'DateTime'
when 'datetimeoffset' then 'DateTimeOffset'
when 'decimal' then 'decimal'
when 'float' then 'double'
when 'image' then 'byte[]'
when 'int' then 'int'
when 'money' then 'decimal'
when 'nchar' then 'string'
when 'ntext' then 'string'
when 'numeric' then 'decimal'
when 'nvarchar' then 'string'
when 'real' then 'float'
when 'smalldatetime' then 'DateTime'
when 'smallint' then 'short'
when 'smallmoney' then 'decimal'
when 'text' then 'string'
when 'time' then 'TimeSpan'
when 'timestamp' then 'long'
when 'tinyint' then 'byte'
when 'uniqueidentifier' then 'Guid'
when 'varbinary' then 'byte[]'
when 'varchar' then 'string'
else 'UNKNOWN_' + typ.name
end ColumnType,
case
when col.is_nullable = 1 and typ.name in ('bigint', 'bit', 'date', 'datetime', 'datetime2', 'datetimeoffset', 'decimal', 'float', 'int', 'money', 'numeric', 'real', 'smalldatetime', 'smallint', 'smallmoney', 'time', 'tinyint', 'uniqueidentifier')
then '?'
else ''
end NullableSign
from sys.columns col
join sys.types typ on
col.system_type_id = typ.system_type_id AND col.user_type_id = typ.user_type_id
where object_id = object_id(@TableName)
) t
order by ColumnId
set @Result = @Result + '
}'
print @Result
其他回答
我将几个基于SQL的答案(主要是Alex Aza的根答案)打包到kassify中，这是一个控制台应用程序，可以一次性为指定的数据库生成所有类:
例如，给定一个Users表，它是这样的:
+----+------------------+-----------+---------------------+
| Id | Name | Username | Email |
+----+------------------+-----------+---------------------+
| 1 | Leanne Graham | Bret | Sincere@april.biz |
| 2 | Ervin Howell | Antonette | Shanna@melissa.tv |
| 3 | Clementine Bauch | Samantha | Nathan@yesenia.net |
+----+------------------+-----------+---------------------+
klassify将生成一个名为Users.cs的文件，看起来像这样:
public class User
{
public int Id {get; set; }
public string Name { get;set; }
public string Username { get; set; }
public string Email { get; set; }
}
它将为每个表输出一个文件。丢弃你不用的东西。
使用
--out, -o:
output directory << defaults to the current directory >>
--user, -u:
sql server user id << required >>
--password, -p:
sql server password << required >>
--server, -s:
sql server << defaults to localhost >>
--database, -d:
sql database << required >>
--timeout, -t:
connection timeout << defaults to 30 >>
--help, -h:
show help
有点晚了，但我已经创建了一个web工具来帮助创建一个c#(或其他)对象从SQL结果，SQL表和SQL SP。
sql2object.com
这可以让你安全地输入所有的属性和类型。
如果无法识别类型，则将选择默认类型。
商业化，但codessmith Generator做到了:http://www.codesmithtools.com/product/generator
如果它对其他人有用，使用属性映射处理Code-First方法，我想要一些只需要在对象模型中绑定实体的东西。所以感谢食肉牛的回答，我根据他们自己的建议扩展了它，并做了一些调整。
因此，这依赖于这个解决方案，包括两个部分，这两个部分都是SQL标量值函数:
一个'Initial Caps'函数(取自: https://social.msdn.microsoft.com/Forums/sqlserver/en-US/8a58dbe1-7a4b-4287-afdc-bfecb4e69b23/similar-to-initcap-in-sql-server-tsql 并略有修改，以满足我的需求)
ALTER function [dbo].[ProperCase] (@cStringToProper varchar(8000))
returns varchar(8000)
as
begin
declare @Position int
select @cStringToProper = stuff(lower(@cStringToProper) , 1 , 1 , upper(left(@cStringToProper , 1)))
, @Position = patindex('%[^a-zA-Z][a-z]%' , @cStringToProper collate Latin1_General_Bin)
while @Position > 0
select @cStringToProper = stuff(@cStringToProper , @Position , 2 , upper(substring(@cStringToProper , @Position , 2)))
, @Position = patindex('%[^a-zA-Z][a-z]%' , @cStringToProper collate Latin1_General_Bin)
select @cStringToProper = replace(@cStringToProper, '_','')
return @cStringToProper
end
输出函数本身，它扩展了食肉牛的解决方案: 正确输出换行符 执行一些基本的表格 写出合适的a [Table]映射(如建议的那样) 写出适当的[Column]映射，包括类型名(如建议的那样) 允许实体名称与表的名称不同 修复当表中有大量列时Print @Result截断的限制
CREATE FUNCTION [dbo].[GetEntityObject] (@NameSpace NVARCHAR(MAX), @TableName NVARCHAR(MAX), @EntityName NVARCHAR(MAX)) RETURNS NVARCHAR(MAX) AS BEGIN
DECLARE @result NVARCHAR(MAX)
SET @result = @result + 'using System;' + CHAR(13) + CHAR(13)
IF (@NameSpace IS NOT NULL) BEGIN
SET @result = @result + 'namespace ' + @NameSpace + CHAR(13) + '{' + CHAR(13) END
SET @result = @result + '[Table(name: ' + CHAR(34) + @TableName + CHAR(34) + ')]' + CHAR(13) SET @result = @result + 'public class ' + @EntityName + CHAR(13) + '{' + CHAR(13)
SET @result = @result + '#region Instance Properties' + CHAR(13)
SELECT @result = @result + CHAR(13) + '[Column(name: ' + CHAR(34) + OriginalColumnName + CHAR(34) + ', TypeName = ' + CHAR(34) + DataType
+ CHAR(34) + ')]' + CHAR(13)
+ 'public ' + ColumnType + ' ' + ColumnName + ' { get; set; } ' + CHAR(13) FROM (
SELECT dbo.ProperCase (c.COLUMN_NAME) AS ColumnName
, CASE c.DATA_TYPE
WHEN 'bigint' THEN
CASE C.IS_NULLABLE
WHEN 'YES' THEN 'Int64?' ELSE 'Int64' END
WHEN 'binary' THEN 'Byte[]'
WHEN 'bit' THEN
CASE C.IS_NULLABLE
WHEN 'YES' THEN 'Boolean?' ELSE 'Boolean' END
WHEN 'char' THEN 'String'
WHEN 'date' THEN
CASE C.IS_NULLABLE
WHEN 'YES' THEN 'DateTime?' ELSE 'DateTime' END
WHEN 'datetime' THEN
CASE C.IS_NULLABLE
WHEN 'YES' THEN 'DateTime?' ELSE 'DateTime' END
WHEN 'datetime2' THEN
CASE C.IS_NULLABLE
WHEN 'YES' THEN 'DateTime?' ELSE 'DateTime' END
WHEN 'datetimeoffset' THEN
CASE C.IS_NULLABLE
WHEN 'YES' THEN 'DateTimeOffset?' ELSE 'DateTimeOffset' END
WHEN 'decimal' THEN
CASE C.IS_NULLABLE
WHEN 'YES' THEN 'Decimal?' ELSE 'Decimal' END
WHEN 'float' THEN
CASE C.IS_NULLABLE
WHEN 'YES' THEN 'Single?' ELSE 'Single' END
WHEN 'image' THEN 'Byte[]'
WHEN 'int' THEN
CASE C.IS_NULLABLE
WHEN 'YES' THEN 'Int32?' ELSE 'Int32' END
WHEN 'money' THEN
CASE C.IS_NULLABLE
WHEN 'YES' THEN 'Decimal?' ELSE 'Decimal' END
WHEN 'nchar' THEN 'String'
WHEN 'ntext' THEN 'String'
WHEN 'numeric' THEN
CASE C.IS_NULLABLE
WHEN 'YES' THEN 'Decimal?' ELSE 'Decimal' END
WHEN 'nvarchar' THEN 'String'
WHEN 'real' THEN
CASE C.IS_NULLABLE
WHEN 'YES' THEN 'Double?' ELSE 'Double' END
WHEN 'smalldatetime' THEN
CASE C.IS_NULLABLE
WHEN 'YES' THEN 'DateTime?' ELSE 'DateTime' END
WHEN 'smallint' THEN
CASE C.IS_NULLABLE
WHEN 'YES' THEN 'Int16?' ELSE 'Int16'END
WHEN 'smallmoney' THEN
CASE C.IS_NULLABLE
WHEN 'YES' THEN 'Decimal?' ELSE 'Decimal' END
WHEN 'text' THEN 'String'
WHEN 'time' THEN
CASE C.IS_NULLABLE
WHEN 'YES' THEN 'TimeSpan?' ELSE 'TimeSpan' END
WHEN 'timestamp' THEN
CASE C.IS_NULLABLE
WHEN 'YES' THEN 'DateTime?' ELSE 'DateTime' END
WHEN 'tinyint' THEN
CASE C.IS_NULLABLE
WHEN 'YES' THEN 'Byte?' ELSE 'Byte' END
WHEN 'uniqueidentifier' THEN 'Guid'
WHEN 'varbinary' THEN 'Byte[]'
WHEN 'varchar' THEN 'String'
ELSE 'Object'
END AS ColumnType
, c.ORDINAL_POSITION , c.COLUMN_NAME as OriginalColumnName ,c.DATA_TYPE as DataType
FROM INFORMATION_SCHEMA.COLUMNS c WHERE c.TABLE_NAME = @TableName) t ORDER BY t.ORDINAL_POSITION
SET @result = @result + CHAR(13) + '#endregion Instance Properties' + CHAR(13)
SET @result = @result + '}' + CHAR(13)
IF (@TableName IS NOT NULL) BEGIN
SET @result = @result + CHAR(13) + '}' END
return @result END
在MS SQL Management Studio中使用:
选择dbo。GetEntityObject(“我的名字”、“我的名字”、“我的名字”)
将生成一个可以复制粘贴到Visual Studio中的列值。
如果这对任何人都有帮助，那太好了!
因为之前没有人提到它，所以还有Scaffold-DbContext
在NuGet Package Manager控制台类型如下: Microsoft.EntityFrameworkCore.SqlServer -OutputDir "输出目录"
