虽然这个问题在2012年就被提出了，但苹果仍然没有给出将设备模式标识符转换为设备名称的方法。 有很多答案依赖于硬编码这些名称，不幸的是，当苹果发布新设备时，这些名称很快就过时了。

我们需要的是一种方法来获得一个不断更新的列表，它就在这里:https://github.com/ptrkstr/Devices

每次添加新设备时，这个Swift包都会更新，你所需要做的就是更新你的依赖项来获得它们。

下面是它的代码(代码可能不包含所有设备的字符串，我和其他人在GitHub上维护相同的代码，所以请从那里获取最新的代码)

Objective-C: GitHub/DeviceUtil

吉hub /恶魔大师

#include <sys/types.h>
#include <sys/sysctl.h>

- (NSString*)hardwareDescription {
    NSString *hardware = [self hardwareString];
    if ([hardware isEqualToString:@"iPhone1,1"]) return @"iPhone 2G";
    if ([hardware isEqualToString:@"iPhone1,2"]) return @"iPhone 3G";
    if ([hardware isEqualToString:@"iPhone3,1"]) return @"iPhone 4";
    if ([hardware isEqualToString:@"iPhone4,1"]) return @"iPhone 4S";
    if ([hardware isEqualToString:@"iPhone5,1"]) return @"iPhone 5";
    if ([hardware isEqualToString:@"iPod1,1"]) return @"iPodTouch 1G";
    if ([hardware isEqualToString:@"iPod2,1"]) return @"iPodTouch 2G";
    if ([hardware isEqualToString:@"iPad1,1"]) return @"iPad";
    if ([hardware isEqualToString:@"iPad2,6"]) return @"iPad Mini";
    if ([hardware isEqualToString:@"iPad4,1"]) return @"iPad Air WIFI";
    //there are lots of other strings too, checkout the github repo
    //link is given at the top of this answer

    if ([hardware isEqualToString:@"i386"]) return @"Simulator";
    if ([hardware isEqualToString:@"x86_64"]) return @"Simulator";

    return nil;
}

- (NSString*)hardwareString {
    size_t size = 100;
    char *hw_machine = malloc(size);
    int name[] = {CTL_HW,HW_MACHINE};
    sysctl(name, 2, hw_machine, &size, NULL, 0);
    NSString *hardware = [NSString stringWithUTF8String:hw_machine];
    free(hw_machine);
    return hardware;
}

芬兰湾的科特林本机:

memScoped {
            val q = alloc<utsname>()
            uname(q.ptr)
            val identifier = NSString.stringWithCString(q.machine, encoding = NSUTF8StringEncoding)
        }

以下是Aniruddh基于uname的方法的现代版本，它不依赖于Mirror，应该适用于Swift 4.2及更高版本:

import UIKit

extension UIDevice {
  var machineName: String {
    var info = utsname()
    return withUnsafeMutablePointer(to: &info) { info in
      // We could alternatively return nil here, or handle
      // errors some other way.
      guard uname(info) == 0 else { return model }
      let offset = MemoryLayout.offset(of: \utsname.machine)!
      let machine = UnsafeRawPointer(info).advanced(by: offset).assumingMemoryBound(to: CChar.self)
      return String(cString: machine)
    }
  }
}

不使用镜像也可以在Swift中获取设备名称。Swift可以在需要的地方自动将内容转换为指针。其实很简单:

/// Returns "iPhone1,1", etc.
var deviceName: String {
    var sysinfo = utsname()
    uname(&sysinfo)
    return String(cString: &sysinfo.machine.0)
}

(向这个被低估的答案致敬https://stackoverflow.com/a/43599474/843454)

这个解决方案适用于物理设备和iOS模拟器，模拟器返回的模型与物理设备返回的模型相同。iPhone X (GSM)为iPhone10,6，而不是“x86_64”。

定义- Swift 4:

import UIKit

extension UIDevice {
    var modelName: String {
        var systemInfo = utsname()
        uname(&systemInfo)
        let machineMirror = Mirror(reflecting: systemInfo.machine)
        let identifier = machineMirror.children.reduce("") { identifier, element in
            guard let value = element.value as? Int8, value != 0 else { return identifier }
            return identifier + String(UnicodeScalar(UInt8(value)))
        }
        if let value = ProcessInfo.processInfo.environment["SIMULATOR_MODEL_IDENTIFIER"] {
            return value
        } else {
            return identifier
        }
    }
}

用法:

print(UIDevice.current.modelName)