这是我的几个小时…逐行读取整个文件。

char * readline(FILE *fp, char *buffer)
{
    int ch;
    int i = 0;
    size_t buff_len = 0;

    buffer = malloc(buff_len + 1);
    if (!buffer) return NULL;  // Out of memory

    while ((ch = fgetc(fp)) != '\n' && ch != EOF)
    {
        buff_len++;
        void *tmp = realloc(buffer, buff_len + 1);
        if (tmp == NULL)
        {
            free(buffer);
            return NULL; // Out of memory
        }
        buffer = tmp;

        buffer[i] = (char) ch;
        i++;
    }
    buffer[i] = '\0';

    // Detect end
    if (ch == EOF && (i == 0 || ferror(fp)))
    {
        free(buffer);
        return NULL;
    }
    return buffer;
}

void lineByline(FILE * file){
char *s;
while ((s = readline(file, 0)) != NULL)
{
    puts(s);
    free(s);
    printf("\n");
}
}

int main()
{
    char *fileName = "input-1.txt";
    FILE* file = fopen(fileName, "r");
    lineByline(file);
    return 0;
}

这个例子有一些错误:

you forgot to add \n to your printfs. Also error messages should go to stderr i.e. fprintf(stderr, .... (not a biggy but) consider using fgetc() rather than getc(). getc() is a macro, fgetc() is a proper function getc() returns an int so ch should be declared as an int. This is important since the comparison with EOF will be handled correctly. Some 8 bit character sets use 0xFF as a valid character (ISO-LATIN-1 would be an example) and EOF which is -1, will be 0xFF if assigned to a char. There is a potential buffer overflow at the line lineBuffer[count] = '\0'; If the line is exactly 128 characters long, count is 128 at the point that gets executed. As others have pointed out, line is a locally declared array. You can't return a pointer to it. strncpy(count + 1) will copy at most count + 1 characters but will terminate if it hits '\0' Because you set lineBuffer[count] to '\0' you know it will never get to count + 1. However, if it did, it would not put a terminating '\0' on, so you need to do it. You often see something like the following: char buffer [BUFFER_SIZE]; strncpy(buffer, sourceString, BUFFER_SIZE - 1); buffer[BUFFER_SIZE - 1] = '\0'; if you malloc() a line to return (in place of your local char array), your return type should be char* - drop the const.

void readLine(FILE* file, char* line, int limit)
{
    int i;
    int read;

    read = fread(line, sizeof(char), limit, file);
    line[read] = '\0';

    for(i = 0; i <= read;i++)
    {
        if('\0' == line[i] || '\n' == line[i] || '\r' == line[i])
        {
            line[i] = '\0';
            break;
        }
    }

    if(i != read)
    {
        fseek(file, i - read + 1, SEEK_CUR);
    }
}

这个怎么样?

您应该使用ANSI函数来读取一行，例如。fgets。调用后，你需要在调用上下文中使用free()，例如:

...
const char *entirecontent=readLine(myFile);
puts(entirecontent);
free(entirecontent);
...

const char *readLine(FILE *file)
{
  char *lineBuffer=calloc(1,1), line[128];

  if ( !file || !lineBuffer )
  {
    fprintf(stderr,"an ErrorNo 1: ...");
    exit(1);
  }

  for(; fgets(line,sizeof line,file) ; strcat(lineBuffer,line) )
  {
    if( strchr(line,'\n') ) *strchr(line,'\n')=0;
    lineBuffer=realloc(lineBuffer,strlen(lineBuffer)+strlen(line)+1);
    if( !lineBuffer )
    {
      fprintf(stderr,"an ErrorNo 2: ...");
      exit(2);
    }
  }
  return lineBuffer;
}

如果你的任务不是发明逐行读取函数，而只是逐行读取文件，你可以使用一个典型的代码片段，包括getline()函数(参见手册页):

#define _GNU_SOURCE
#include <stdio.h>
#include <stdlib.h>

int main(void)
{
    FILE * fp;
    char * line = NULL;
    size_t len = 0;
    ssize_t read;

    fp = fopen("/etc/motd", "r");
    if (fp == NULL)
        exit(EXIT_FAILURE);

    while ((read = getline(&line, &len, fp)) != -1) {
        printf("Retrieved line of length %zu:\n", read);
        printf("%s", line);
    }

    fclose(fp);
    if (line)
        free(line);
    exit(EXIT_SUCCESS);
}

const char *readLine(FILE *file, char* line) {

    if (file == NULL) {
        printf("Error: file pointer is null.");
        exit(1);
    }

    int maximumLineLength = 128;
    char *lineBuffer = (char *)malloc(sizeof(char) * maximumLineLength);

    if (lineBuffer == NULL) {
        printf("Error allocating memory for line buffer.");
        exit(1);
    }

    char ch = getc(file);
    int count = 0;

    while ((ch != '\n') && (ch != EOF)) {
        if (count == maximumLineLength) {
            maximumLineLength += 128;
            lineBuffer = realloc(lineBuffer, maximumLineLength);
            if (lineBuffer == NULL) {
                printf("Error reallocating space for line buffer.");
                exit(1);
            }
        }
        lineBuffer[count] = ch;
        count++;

        ch = getc(file);
    }

    lineBuffer[count] = '\0';
    char line[count + 1];
    strncpy(line, lineBuffer, (count + 1));
    free(lineBuffer);
    return line;

}


char linebuffer[256];
while (!feof(myFile)) {
    const char *line = readLine(myFile, linebuffer);
    printf("%s\n", line);
}

注意，'line'变量是在调用函数中声明的，然后传递，所以你的readLine函数填充预定义的缓冲区并返回它。这是大多数C库的工作方式。

我知道还有其他办法

defining the char line[] as static (static char line[MAX_LINE_LENGTH] -> it will hold it's value AFTER returning from the function). -> bad, the function is not reentrant, and race condition can occur -> if you call it twice from two threads, it will overwrite it's results malloc()ing the char line[], and freeing it in calling functions -> too many expensive mallocs, and, delegating the responsibility to free the buffer to another function (the most elegant solution is to call malloc and free on any buffers in same function)

顺便说一下，从char*到const char*的显式强制转换是多余的。

在btw2中，不需要malloc() lineBuffer，只需要定义它为char lineBuffer[128]，所以你不需要释放它

btw3不使用“动态大小堆栈数组”(将数组定义为char arrayName[some_nonconstant_variable])，如果你不确切地知道你在做什么，它只在C99中工作。