我写这个函数是从文件中读取一行:
const char *readLine(FILE *file) {
if (file == NULL) {
printf("Error: file pointer is null.");
exit(1);
}
int maximumLineLength = 128;
char *lineBuffer = (char *)malloc(sizeof(char) * maximumLineLength);
if (lineBuffer == NULL) {
printf("Error allocating memory for line buffer.");
exit(1);
}
char ch = getc(file);
int count = 0;
while ((ch != '\n') && (ch != EOF)) {
if (count == maximumLineLength) {
maximumLineLength += 128;
lineBuffer = realloc(lineBuffer, maximumLineLength);
if (lineBuffer == NULL) {
printf("Error reallocating space for line buffer.");
exit(1);
}
}
lineBuffer[count] = ch;
count++;
ch = getc(file);
}
lineBuffer[count] = '\0';
char line[count + 1];
strncpy(line, lineBuffer, (count + 1));
free(lineBuffer);
const char *constLine = line;
return constLine;
}
该函数正确地读取文件，使用printf我看到constLine字符串也被正确读取。
然而，如果我像这样使用函数:
while (!feof(myFile)) {
const char *line = readLine(myFile);
printf("%s\n", line);
}
Printf输出胡言乱语。为什么?
如果你的任务不是发明逐行读取函数，而只是逐行读取文件，你可以使用一个典型的代码片段，包括getline()函数(参见手册页):
#define _GNU_SOURCE
#include <stdio.h>
#include <stdlib.h>
int main(void)
{
FILE * fp;
char * line = NULL;
size_t len = 0;
ssize_t read;
fp = fopen("/etc/motd", "r");
if (fp == NULL)
exit(EXIT_FAILURE);
while ((read = getline(&line, &len, fp)) != -1) {
printf("Retrieved line of length %zu:\n", read);
printf("%s", line);
}
fclose(fp);
if (line)
free(line);
exit(EXIT_SUCCESS);
}
如果你的任务不是发明逐行读取函数，而只是逐行读取文件，你可以使用一个典型的代码片段，包括getline()函数(参见手册页):
#define _GNU_SOURCE
#include <stdio.h>
#include <stdlib.h>
int main(void)
{
FILE * fp;
char * line = NULL;
size_t len = 0;
ssize_t read;
fp = fopen("/etc/motd", "r");
if (fp == NULL)
exit(EXIT_FAILURE);
while ((read = getline(&line, &len, fp)) != -1) {
printf("Retrieved line of length %zu:\n", read);
printf("%s", line);
}
fclose(fp);
if (line)
free(line);
exit(EXIT_SUCCESS);
}
这个例子有一些错误:
you forgot to add \n to your printfs. Also error messages should go to stderr i.e. fprintf(stderr, ....
(not a biggy but) consider using fgetc() rather than getc(). getc() is a macro, fgetc() is a proper function
getc() returns an int so ch should be declared as an int. This is important since the comparison with EOF will be handled correctly. Some 8 bit character sets use 0xFF as a valid character (ISO-LATIN-1 would be an example) and EOF which is -1, will be 0xFF if assigned to a char.
There is a potential buffer overflow at the line
lineBuffer[count] = '\0';
If the line is exactly 128 characters long, count is 128 at the point that gets executed.
As others have pointed out, line is a locally declared array. You can't return a pointer to it.
strncpy(count + 1) will copy at most count + 1 characters but will terminate if it hits '\0' Because you set lineBuffer[count] to '\0' you know it will never get to count + 1. However, if it did, it would not put a terminating '\0' on, so you need to do it. You often see something like the following:
char buffer [BUFFER_SIZE];
strncpy(buffer, sourceString, BUFFER_SIZE - 1);
buffer[BUFFER_SIZE - 1] = '\0';
if you malloc() a line to return (in place of your local char array), your return type should be char* - drop the const.
完整的fgets()解决方案:
#include <stdio.h>
#include <string.h>
#define MAX_LEN 256
int main(void)
{
FILE* fp;
fp = fopen("file.txt", "r");
if (fp == NULL) {
perror("Failed: ");
return 1;
}
char buffer[MAX_LEN];
while (fgets(buffer, MAX_LEN, fp))
{
// Remove trailing newline
buffer[strcspn(buffer, "\n")] = 0;
printf("%s\n", buffer);
}
fclose(fp);
return 0;
}
输出:
First line of file
Second line of file
Third (and also last) line of file
记住，如果你想从标准输入(而不是像这种情况下的文件)中读取，那么你所要做的就是将stdin作为fgets()方法的第三个参数传递，就像这样:
while(fgets(buffer, MAX_LEN, stdin))
附录
从fgets()输入中删除尾随换行符
如何在c中检测文件是否打开
