您应该使用ANSI函数来读取一行，例如。fgets。调用后，你需要在调用上下文中使用free()，例如:

...
const char *entirecontent=readLine(myFile);
puts(entirecontent);
free(entirecontent);
...

const char *readLine(FILE *file)
{
  char *lineBuffer=calloc(1,1), line[128];

  if ( !file || !lineBuffer )
  {
    fprintf(stderr,"an ErrorNo 1: ...");
    exit(1);
  }

  for(; fgets(line,sizeof line,file) ; strcat(lineBuffer,line) )
  {
    if( strchr(line,'\n') ) *strchr(line,'\n')=0;
    lineBuffer=realloc(lineBuffer,strlen(lineBuffer)+strlen(line)+1);
    if( !lineBuffer )
    {
      fprintf(stderr,"an ErrorNo 2: ...");
      exit(2);
    }
  }
  return lineBuffer;
}

在readLine函数中，返回一个指向行数组的指针(严格地说，是指向该行数组第一个字符的指针，但这里的区别无关紧要)。由于它是一个自动变量(即，它“在堆栈上”)，当函数返回时，内存将被回收。你看到的是乱七八糟的东西，因为printf把它自己的东西放到了堆栈上。

您需要从函数返回一个动态分配的缓冲区。你已经有一个了，它是lineBuffer;你所要做的就是把它截断成所需的长度。

    lineBuffer[count] = '\0';
    realloc(lineBuffer, count + 1);
    return lineBuffer;
}

ADDED(对评论中后续问题的回应):readLine返回一个指向组成该行的字符的指针。这个指针是处理该行内容所需要的指针。当你用完这些字符占用的内存时，你也必须通过它来释放内存。下面是如何使用readLine函数:

char *line = readLine(file);
printf("LOG: read a line: %s\n", line);
if (strchr(line, 'a')) { puts("The line contains an a"); }
/* etc. */
free(line);
/* After this point, the memory allocated for the line has been reclaimed.
   You can't use the value of `line` again (though you can assign a new value
   to the `line` variable if you want). */

我想要一个代码从地面0，所以我这样做，逐行读取字典的单词的内容。

char temp_str [20];//你可以根据你的要求改变缓冲区的大小和一个文件中的单行长度。

注意，每次读取line时，我都将缓冲区初始化为Null字符。这个功能可以自动化，但因为我需要一个概念的证明，并想要一个字节一个字节地设计程序

#include<stdio.h>

int main()
{
int i;
char temp_ch;
FILE *fp=fopen("data.txt","r");
while(temp_ch!=EOF)
{
 i=0;
  char temp_str[20]={'\0','\0','\0','\0','\0','\0','\0','\0','\0','\0','\0','\0','\0','\0','\0','\0','\0','\0','\0'};
while(temp_ch!='\n')
{
  temp_ch=fgetc(fp);
  temp_str[i]=temp_ch;
  i++;
}
if(temp_ch=='\n')
{
temp_ch=fgetc(fp);
temp_str[i]=temp_ch;
}
printf("%s",temp_str);
}
return 0;
}

FILE* filePointer;
int bufferLength = 255;
char buffer[bufferLength]; /* not ISO 90 compatible */

filePointer = fopen("file.txt", "r");

while(fgets(buffer, bufferLength, filePointer)) {
    printf("%s\n", buffer);
}

fclose(filePointer);

完整的fgets()解决方案:

#include <stdio.h>
#include <string.h>

#define MAX_LEN 256

int main(void)
{
    FILE* fp;
    fp = fopen("file.txt", "r");
    if (fp == NULL) {
      perror("Failed: ");
      return 1;
    }

    char buffer[MAX_LEN];
    while (fgets(buffer, MAX_LEN, fp))
    {
        // Remove trailing newline
        buffer[strcspn(buffer, "\n")] = 0;
        printf("%s\n", buffer);
    }

    fclose(fp);
    return 0;
}

输出:

First line of file
Second line of file
Third (and also last) line of file

记住，如果你想从标准输入(而不是像这种情况下的文件)中读取，那么你所要做的就是将stdin作为fgets()方法的第三个参数传递，就像这样:

while(fgets(buffer, MAX_LEN, stdin))

附录

从fgets()输入中删除尾随换行符

如何在c中检测文件是否打开

const char *readLine(FILE *file, char* line) {

    if (file == NULL) {
        printf("Error: file pointer is null.");
        exit(1);
    }

    int maximumLineLength = 128;
    char *lineBuffer = (char *)malloc(sizeof(char) * maximumLineLength);

    if (lineBuffer == NULL) {
        printf("Error allocating memory for line buffer.");
        exit(1);
    }

    char ch = getc(file);
    int count = 0;

    while ((ch != '\n') && (ch != EOF)) {
        if (count == maximumLineLength) {
            maximumLineLength += 128;
            lineBuffer = realloc(lineBuffer, maximumLineLength);
            if (lineBuffer == NULL) {
                printf("Error reallocating space for line buffer.");
                exit(1);
            }
        }
        lineBuffer[count] = ch;
        count++;

        ch = getc(file);
    }

    lineBuffer[count] = '\0';
    char line[count + 1];
    strncpy(line, lineBuffer, (count + 1));
    free(lineBuffer);
    return line;

}


char linebuffer[256];
while (!feof(myFile)) {
    const char *line = readLine(myFile, linebuffer);
    printf("%s\n", line);
}

注意，'line'变量是在调用函数中声明的，然后传递，所以你的readLine函数填充预定义的缓冲区并返回它。这是大多数C库的工作方式。

我知道还有其他办法

defining the char line[] as static (static char line[MAX_LINE_LENGTH] -> it will hold it's value AFTER returning from the function). -> bad, the function is not reentrant, and race condition can occur -> if you call it twice from two threads, it will overwrite it's results malloc()ing the char line[], and freeing it in calling functions -> too many expensive mallocs, and, delegating the responsibility to free the buffer to another function (the most elegant solution is to call malloc and free on any buffers in same function)

顺便说一下，从char*到const char*的显式强制转换是多余的。

在btw2中，不需要malloc() lineBuffer，只需要定义它为char lineBuffer[128]，所以你不需要释放它

btw3不使用“动态大小堆栈数组”(将数组定义为char arrayName[some_nonconstant_variable])，如果你不确切地知道你在做什么，它只在C99中工作。