如何使用Scanner类从控制台读取输入?就像这样:

System.out.println("Enter your username: ");
Scanner = input(); // Or something like this, I don't know the code

基本上,我想要的只是让扫描器读取用户名的输入,并将输入分配给一个String变量。


当前回答

读取输入: 扫描仪扫描仪=新的扫描仪(System.in); 字符串输入= scanner.nextLine(); 当你调用一个带有参数/形参的方法时读取输入: 如果(arg游戏。长度!= 2){ System.err。println(" utilzare: java Grep < filier > <cuvant>"); system . exit (1); } 尝试{ grep (args [0], arg游戏[1]); } catch (IOException e) { System.out.println (e.getMessage ()); }

其他回答

import java.util.*;

class Ss
{
    int id, salary;
    String name;

   void Ss(int id, int salary, String name)
    {
        this.id = id;
        this.salary = salary;
        this.name = name;
    }

    void display()
    {
        System.out.println("The id of employee:" + id);
        System.out.println("The name of employye:" + name);
        System.out.println("The salary of employee:" + salary);
    }
}

class employee
{
    public static void main(String args[])
    {
        Scanner sc = new Scanner(System.in);

        Ss s = new Ss(sc.nextInt(), sc.nextInt(), sc.nextLine());
        s.display();
    }
}

从控制台读取数据

BufferedReader is synchronized, so read operations on a BufferedReader can be safely done from multiple threads. The buffer size may be specified, or the default size(8192) may be used. The default is large enough for most purposes. readLine() « just reads data line by line from the stream or source. A line is considered to be terminated by any one these: \n, \r (or) \r\n Scanner breaks its input into tokens using a delimiter pattern, which by default matches whitespace(\s) and it is recognised by Character.isWhitespace. « Until the user enters data, the scanning operation may block, waiting for input. « Use Scanner(BUFFER_SIZE = 1024) if you want to parse a specific type of token from a stream. « A scanner however is not thread safe. It has to be externally synchronized. next() « Finds and returns the next complete token from this scanner. nextInt() « Scans the next token of the input as an int.

Code

String name = null;
int number;

java.io.BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
name = in.readLine(); // If the user has not entered anything, assume the default value.
number = Integer.parseInt(in.readLine()); // It reads only String,and we need to parse it.
System.out.println("Name " + name + "\t number " + number);

java.util.Scanner sc = new Scanner(System.in).useDelimiter("\\s");
name = sc.next();  // It will not leave until the user enters data.
number = sc.nextInt(); // We can read specific data.
System.out.println("Name " + name + "\t number " + number);

// The Console class is not working in the IDE as expected.
java.io.Console cnsl = System.console();
if (cnsl != null) {
    // Read a line from the user input. The cursor blinks after the specified input.
    name = cnsl.readLine("Name: ");
    System.out.println("Name entered: " + name);
}

流的输入和输出

Reader Input:     Output:
Yash 777          Line1 = Yash 777
     7            Line1 = 7

Scanner Input:    Output:
Yash 777          token1 = Yash
                  token2 = 777

你可以流动这段代码:

Scanner obj= new Scanner(System.in);
String s = obj.nextLine();

你写过

Scanner = input()

这是错误的方法,你必须创建一个整数或字符串,我更喜欢字符串,然后给一个字符串任意的名字,可以是I可以是n,或者其他的,记住你是在给用户名取名字你也可以给名字取用户名,代码是

String username = sc.nextline();
System.our.println("the username is" + username);

我希望你现在明白了

你可以在Java中使用Scanner类

Scanner scan = new Scanner(System.in);
String s = scan.nextLine();
System.out.println("String: " + s);