如何使用Scanner类从控制台读取输入?就像这样:
System.out.println("Enter your username: ");
Scanner = input(); // Or something like this, I don't know the code
基本上,我想要的只是让扫描器读取用户名的输入,并将输入分配给一个String变量。
如何使用Scanner类从控制台读取输入?就像这样:
System.out.println("Enter your username: ");
Scanner = input(); // Or something like this, I don't know the code
基本上,我想要的只是让扫描器读取用户名的输入,并将输入分配给一个String变量。
当前回答
您可以编写一个简单的程序来询问用户的姓名,并打印任何回复使用的输入。
或者要求用户输入两个数字,您可以对这些数字进行加、乘、减或除,并像计算器一样打印用户输入的答案。
这里你需要Scanner类。你必须导入java.util.Scanner;,并且在你需要使用的代码中:
Scanner input = new Scanner(System.in);
Input是一个变量名。
Scanner input = new Scanner(System.in);
System.out.println("Please enter your name: ");
s = input.next(); // Getting a String value
System.out.println("Please enter your age: ");
i = input.nextInt(); // Getting an integer
System.out.println("Please enter your salary: ");
d = input.nextDouble(); // Getting a double
看看这有什么不同:input.next();, i = input.nextInt();, d = input.nextDouble();
根据String类型,int类型和double类型的变化方式与其他类型相同。不要忘记代码顶部的import语句。
其他回答
import java.util.Scanner;
public class ScannerDemo {
public static void main(String[] arguments){
Scanner input = new Scanner(System.in);
String username;
double age;
String gender;
String marital_status;
int telephone_number;
// Allows a person to enter his/her name
Scanner one = new Scanner(System.in);
System.out.println("Enter Name:" );
username = one.next();
System.out.println("Name accepted " + username);
// Allows a person to enter his/her age
Scanner two = new Scanner(System.in);
System.out.println("Enter Age:" );
age = two.nextDouble();
System.out.println("Age accepted " + age);
// Allows a person to enter his/her gender
Scanner three = new Scanner(System.in);
System.out.println("Enter Gender:" );
gender = three.next();
System.out.println("Gender accepted " + gender);
// Allows a person to enter his/her marital status
Scanner four = new Scanner(System.in);
System.out.println("Enter Marital status:" );
marital_status = four.next();
System.out.println("Marital status accepted " + marital_status);
// Allows a person to enter his/her telephone number
Scanner five = new Scanner(System.in);
System.out.println("Enter Telephone number:" );
telephone_number = five.nextInt();
System.out.println("Telephone number accepted " + telephone_number);
}
}
你可以在Java中使用Scanner类
Scanner scan = new Scanner(System.in);
String s = scan.nextLine();
System.out.println("String: " + s);
下面是执行所需操作的完整类:
import java.util.Scanner;
public class App {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
final int valid = 6;
Scanner one = new Scanner(System.in);
System.out.println("Enter your username: ");
String s = one.nextLine();
if (s.length() < valid) {
System.out.println("Enter a valid username");
System.out.println(
"User name must contain " + valid + " characters");
System.out.println("Enter again: ");
s = one.nextLine();
}
System.out.println("Username accepted: " + s);
Scanner two = new Scanner(System.in);
System.out.println("Enter your age: ");
int a = two.nextInt();
System.out.println("Age accepted: " + a);
Scanner three = new Scanner(System.in);
System.out.println("Enter your sex: ");
String sex = three.nextLine();
System.out.println("Sex accepted: " + sex);
}
}
input.nextInt()方法有问题——它只读取int值。
因此,当使用input.nextLine()读取下一行时,您会收到“\n”,即回车键。所以要跳过这个,你必须添加input.nextLine()。
试着这样做:
System.out.print("Insert a number: ");
int number = input.nextInt();
input.nextLine(); // This line you have to add (it consumes the \n character)
System.out.print("Text1: ");
String text1 = input.nextLine();
System.out.print("Text2: ");
String text2 = input.nextLine();
说明java.util.Scanner如何工作的一个简单示例是从System.in中读取单个整数。这真的很简单。
Scanner sc = new Scanner(System.in);
int i = sc.nextInt();
要检索用户名,我可能会使用sc.nextLine()。
System.out.println("Enter your username: ");
Scanner scanner = new Scanner(System.in);
String username = scanner.nextLine();
System.out.println("Your username is " + username);
如果您想对输入进行更多控制,或者只是验证用户名变量,也可以使用next(字符串模式)。
你可以在java.util.Scanner的API文档中找到更多关于它们实现的信息