你是怎么做到的?给定一个字节数组:
byte[] foo = new byte[4096];
我如何得到数组的前x字节作为一个单独的数组?(具体来说,我需要它作为一个IEnumerable<byte>)
这是用于使用Sockets的。我认为最简单的方法是数组切片,类似于perl语法:
@bar = @foo[0..40];
将前41个元素返回到@bar数组中。c#中是否有我遗漏的东西,或者有其他我应该做的事情?
LINQ对我来说是一个选择。NET 3.5),如果有帮助的话。
你是怎么做到的?给定一个字节数组:
byte[] foo = new byte[4096];
我如何得到数组的前x字节作为一个单独的数组?(具体来说,我需要它作为一个IEnumerable<byte>)
这是用于使用Sockets的。我认为最简单的方法是数组切片,类似于perl语法:
@bar = @foo[0..40];
将前41个元素返回到@bar数组中。c#中是否有我遗漏的东西,或者有其他我应该做的事情?
LINQ对我来说是一个选择。NET 3.5),如果有帮助的话。
当前回答
这可能是一个解决方案:
var result = foo.Slice(40, int.MaxValue);
然后结果是一个IEnumerable< IEnumerable<字节>>,其中第一个IEnumerable<字节>包含foo的前40个字节,第二个IEnumerable<字节>包含其余的字节。
我写了一个包装类,整个迭代是懒惰的,希望对大家有所帮助:
public static class CollectionSlicer
{
public static IEnumerable<IEnumerable<T>> Slice<T>(this IEnumerable<T> source, params int[] steps)
{
if (!steps.Any(step => step != 0))
{
throw new InvalidOperationException("Can't slice a collection with step length 0.");
}
return new Slicer<T>(source.GetEnumerator(), steps).Slice();
}
}
public sealed class Slicer<T>
{
public Slicer(IEnumerator<T> iterator, int[] steps)
{
_iterator = iterator;
_steps = steps;
_index = 0;
_currentStep = 0;
_isHasNext = true;
}
public int Index
{
get { return _index; }
}
public IEnumerable<IEnumerable<T>> Slice()
{
var length = _steps.Length;
var index = 1;
var step = 0;
for (var i = 0; _isHasNext; ++i)
{
if (i < length)
{
step = _steps[i];
_currentStep = step - 1;
}
while (_index < index && _isHasNext)
{
_isHasNext = MoveNext();
}
if (_isHasNext)
{
yield return SliceInternal();
index += step;
}
}
}
private IEnumerable<T> SliceInternal()
{
if (_currentStep == -1) yield break;
yield return _iterator.Current;
for (var count = 0; count < _currentStep && _isHasNext; ++count)
{
_isHasNext = MoveNext();
if (_isHasNext)
{
yield return _iterator.Current;
}
}
}
private bool MoveNext()
{
++_index;
return _iterator.MoveNext();
}
private readonly IEnumerator<T> _iterator;
private readonly int[] _steps;
private volatile bool _isHasNext;
private volatile int _currentStep;
private volatile int _index;
}
其他回答
对于字节数组,System.Buffer.BlockCopy会给你最好的性能。
下面是一个使用泛型的扩展函数,其行为类似于PHP函数array_slice。允许负偏移量和负长度。
public static class Extensions
{
public static T[] Slice<T>(this T[] arr, int offset, int length)
{
int start, end;
// Determine start index, handling negative offset.
if (offset < 0)
start = arr.Length + offset;
else
start = offset;
// Clamp start index to the bounds of the input array.
if (start < 0)
start = 0;
else if (start > arr.Length)
start = arr.Length;
// Determine end index, handling negative length.
if (length < 0)
end = arr.Length + length;
else
end = start + length;
// Clamp end index to the bounds of the input array.
if (end < 0)
end = 0;
if (end > arr.Length)
end = arr.Length;
// Get the array slice.
int len = end - start;
T[] result = new T[len];
for (int i = 0; i < len; i++)
{
result[i] = arr[start + i];
}
return result;
}
}
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace data_seniens
{
class Program
{
static void Main(string[] args)
{
//new list
float [] x=new float[]{11.25f,18.0f,20.0f,10.75f,9.50f, 11.25f, 18.0f, 20.0f, 10.75f, 9.50f };
//variable
float eat_sleep_area=x[1]+x[3];
//print
foreach (var VARIABLE in x)
{
if (VARIABLE < x[7])
{
Console.WriteLine(VARIABLE);
}
}
//keep app run
Console.ReadLine();
}
}
}
您可以对原始数组(即IList)使用包装器,就像下面(未经测试的)代码一样。
public class SubList<T> : IList<T>
{
#region Fields
private readonly int startIndex;
private readonly int endIndex;
private readonly int count;
private readonly IList<T> source;
#endregion
public SubList(IList<T> source, int startIndex, int count)
{
this.source = source;
this.startIndex = startIndex;
this.count = count;
this.endIndex = this.startIndex + this.count - 1;
}
#region IList<T> Members
public int IndexOf(T item)
{
if (item != null)
{
for (int i = this.startIndex; i <= this.endIndex; i++)
{
if (item.Equals(this.source[i]))
return i;
}
}
else
{
for (int i = this.startIndex; i <= this.endIndex; i++)
{
if (this.source[i] == null)
return i;
}
}
return -1;
}
public void Insert(int index, T item)
{
throw new NotSupportedException();
}
public void RemoveAt(int index)
{
throw new NotSupportedException();
}
public T this[int index]
{
get
{
if (index >= 0 && index < this.count)
return this.source[index + this.startIndex];
else
throw new IndexOutOfRangeException("index");
}
set
{
if (index >= 0 && index < this.count)
this.source[index + this.startIndex] = value;
else
throw new IndexOutOfRangeException("index");
}
}
#endregion
#region ICollection<T> Members
public void Add(T item)
{
throw new NotSupportedException();
}
public void Clear()
{
throw new NotSupportedException();
}
public bool Contains(T item)
{
return this.IndexOf(item) >= 0;
}
public void CopyTo(T[] array, int arrayIndex)
{
for (int i=0; i<this.count; i++)
{
array[arrayIndex + i] = this.source[i + this.startIndex];
}
}
public int Count
{
get { return this.count; }
}
public bool IsReadOnly
{
get { return true; }
}
public bool Remove(T item)
{
throw new NotSupportedException();
}
#endregion
#region IEnumerable<T> Members
public IEnumerator<T> GetEnumerator()
{
for (int i = this.startIndex; i < this.endIndex; i++)
{
yield return this.source[i];
}
}
#endregion
#region IEnumerable Members
IEnumerator IEnumerable.GetEnumerator()
{
return GetEnumerator();
}
#endregion
}
您可以使用Take扩展方法
var array = new byte[] {1, 2, 3, 4};
var firstTwoItems = array.Take(2);