如何在uiLabel中同时包含粗体和非粗体文本?

我宁愿不用UIWebView..我也读过这个可能使用NSAttributedString但我不知道如何使用它。什么好主意吗?

苹果在他们的几个应用程序中实现了这一点; 例子截图:

谢谢! ——Dom


当前回答

检查TTTAttributedLabel。它是UILabel的一个替换,它允许你在一个标签中混合字体和颜色,通过设置NSAttributedString作为标签的文本。

其他回答

NSString *needToChangeStr=@"BOOK";
NSString *display_string=[NSString stringWithFormat:@"This is %@",book];

NSMutableAttributedString *attri_str=[[NSMutableAttributedString alloc]initWithString:display_string];

int begin=[display_string length]-[needToChangeStr length];
int end=[needToChangeStr length];


[attri_str addAttribute:NSFontAttributeName value:[UIFont fontWithName:@"HelveticaNeue-Bold" size:30] range:NSMakeRange(begin, end)];

提供要处理的字符串作为输入,并提供粗体/彩色的单词作为输入。

func attributedString(parentString:String, arrayOfStringToProcess:[String], color:UIColor) -> NSAttributedString
{
    let parentAttributedString = NSMutableAttributedString(string:parentString, attributes:nil)
    let parentStringWords = parentAttributedString.string.components(separatedBy: " ")
    if parentStringWords.count != 0
    {
        let wordSearchArray = arrayOfStringToProcess.filter { inputArrayIndex in
            parentStringWords.contains(where: { $0 == inputArrayIndex }
            )}
        for eachWord in wordSearchArray
        {
            parentString.enumerateSubstrings(in: parentString.startIndex..<parentString.endIndex, options: .byWords)
            {
                (substring, substringRange, _, _) in
                if substring == eachWord
                {
                    parentAttributedString.addAttribute(.font, value: UIFont.boldSystemFont(ofSize: 15), range: NSRange(substringRange, in: parentString))
                    parentAttributedString.addAttribute(.foregroundColor, value: color, range: NSRange(substringRange, in: parentString))
                }
            }
        }
    }
    return parentAttributedString
}

在这种情况下,你可以尝试,

UILabel *displayLabel = [[UILabel alloc] initWithFrame:/*label frame*/];
displayLabel.font = [UIFont boldSystemFontOfSize:/*bold font size*/];

NSMutableAttributedString *notifyingStr = [[NSMutableAttributedString alloc] initWithString:@"Updated: 2012/10/14 21:59 PM"];
[notifyingStr beginEditing];
[notifyingStr addAttribute:NSFontAttributeName
                     value:[UIFont systemFontOfSize:/*normal font size*/]
                     range:NSMakeRange(8,10)/*range of normal string, e.g. 2012/10/14*/];
[notifyingStr endEditing];

displayLabel.attributedText = notifyingStr; // or [displayLabel setAttributedText: notifyingStr];

我采用了疯狂酸奶对斯威夫特扩展的回答。

extension UILabel {

    func boldRange(_ range: Range<String.Index>) {
        if let text = self.attributedText {
            let attr = NSMutableAttributedString(attributedString: text)
            let start = text.string.characters.distance(from: text.string.startIndex, to: range.lowerBound)
            let length = text.string.characters.distance(from: range.lowerBound, to: range.upperBound)
            attr.addAttributes([NSFontAttributeName: UIFont.boldSystemFont(ofSize: self.font.pointSize)], range: NSMakeRange(start, length))
            self.attributedText = attr
        }
    }

    func boldSubstring(_ substr: String) {
        if let text = self.attributedText {
            var range = text.string.range(of: substr)
            let attr = NSMutableAttributedString(attributedString: text)
            while range != nil {
                let start = text.string.characters.distance(from: text.string.startIndex, to: range!.lowerBound)
                let length = text.string.characters.distance(from: range!.lowerBound, to: range!.upperBound)
                var nsRange = NSMakeRange(start, length)
                let font = attr.attribute(NSFontAttributeName, at: start, effectiveRange: &nsRange) as! UIFont
                if !font.fontDescriptor.symbolicTraits.contains(.traitBold) {
                    break
                }
                range = text.string.range(of: substr, options: NSString.CompareOptions.literal, range: range!.upperBound..<text.string.endIndex, locale: nil)
            }
            if let r = range {
                boldRange(r)
            }
        }
    }
}

可能在Range和NSRange之间没有很好的转换,但我没有发现更好的东西。

如果您希望更容易地使用带属性字符串,请尝试使用带属性字符串创建者,它将为您生成代码。https://itunes.apple.com/us/app/attributed-string-creator/id730928349